Write a while loop that prints from 1 to user_num, increasing by 1 each time.
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Sample output with input: 4
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- Match the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eaxThe following code results in an error message. What will the error message be andhow can it be fixed? def TryParseInt(p1, p2):return p1 + p2#Calling Codep3 = TryParseInt(10)int FindSmallestVal() { int num = 0, min = 0; // reads num until the num > 0 while (num <= 0) { cin >> num; // finds the min value in the min,num min = num < min ? num : min; } // returns min return min; }
- Lab01 (Count single digits) Write a program that generates n random integers between 0 and 9 and displays the count for each number. (Hint: Use an array of ten integers, say count, to store the counts for the number of Os, 1s, ..., 9s.) A modular program is expected - use Methods. The program specifications are as below. In the main() method, declare an int array of size 10, named cnums. Implement a method fillCnums(int[] cnt) that initializes the array to zero. Implement a method countDigits(int[] cnt, int n) that accepts the cnums array and an integer n. The method should generate n random numbers in the range of 0 to 9. It should keep a count of how many times each number, 0 to 9; is generated in the array cnums. Implement a method printCnums(int[] cnt) to print the cnums array. Note, print "time" or "times" - which ever is appropriate. Use basic structured programming and procedural programming. Write a main() method that declares the cnums array. Invokes the countDigits() method…/* * rotate4 - Rotate x to the left by 4 * Examples: rotate4(0x87654321) = 0x76543218 * Legal ops: ~ & ^ | + << >> ! * Max ops: 10 * Rating: 2 */int rotate4(int u) { return 2;} Do not use any control constructs such as if, do, while, for, switch, etc.个人空间 Python Programming 作业作答 -> https://mooc1.chaoxing.com/mooc2/work/dowork?courseld=222701483&classld=50725394&cpi=102339231&workld=19472480&answerld... Score GPA e.g Exercise 4.3 = 100 5.0 99: GPA is4.9 290 24.0 92: GPA is4.2 91: GPA is4.1 Write codes to transform a 90: GPA is4.0 given score to GPA following the 89: GPA is3.9 rules shown in the right table. 280 2 3.0 82: GPA is3.2 81: GPA is3.1 Submit the screenshot of your 80: GPA is3.0 test results and check if it's what 79: GPA is2.9 you expected. 2 70 22.0 72: GPA is2.2 71: GPA is2.1 For example, 70: GPA is2.0 69: GPA is1.9 if score=76, then GPA=2.6 if score=88, then GPA=3.8 2 60 21.0 62: GPA is1.2 61: GPA is1.1 if score=32, then GPA=0 60: GPA is1.0 O A 59: GFA 0 44: GPA is 0 < 60
- Python please prime_test.py: def is_prime(num):#ADD CODE to return True if num is prime; False if notdef main():#ADD CODE to call is_prime() for integers 1-100# and print the ones that are primemain()#include <stdio.h>#include <stdlib.h> //declaring variables globally to calculate coinsint cent50 = 0;int cent20 = 0;int cent10 = 0;int cent05 = 0; //calculate change//pass change variable by addressvoid calculateChange(int* change) {//calculate change only if change is positiveif(*change > 0) {if(*change >= 50) {*change -= 50;cent50++;}else if(*change >= 20) {*change -= 20;cent20++;}else if(*change >= 10) {*change -= 10;cent10++;}else if(*change >= 05) {*change -= 05;cent05++;}//call calculateChange recursively calculateChange(change);}} // function to display the cents valuesvoid printChange() { if(cent50)printf("\n50 Cents : %d coins", cent50);if(cent20)printf("\n20 Cents : %d coins", cent20);if(cent10)printf("\n10 Cents : %d coins", cent10);if(cent05)printf("\n05 Cents : %d coins", cent05);//reset all cent variables with 0cent50 = 0;cent20 = 0;cent10 = 0;cent05 = 0; } //take change input from user//change variable passed addressvoid TakeChange(int*…Brute force equation solver this is python program. Numerous engineering and scientific applications require finding solutions to a set of equations. Ex: 8x + 7y = 38 and 3x - 5y = -1 have a solution x = 3, y = 2. Given integer coefficients of two linear equations with variables x and y, use brute force to find an integer solution for x and y in the range -10 to 10. Ex: If the input is: 8 7 38 3 -5 -1 Then the output is: 3 2 Use this brute force approach: For every value of x from -10 to 10 For every value of y from -10 to 10 Check if the current x and y satisfy both equations. If so, output the solution, and finish. Ex: If no solution is found, output: No solution You can assume the two equations have no more than one solution. Note: Elegant mathematical techniques exist to solve such linear equations. However, for other kinds of equations or situations, brute force can be handy. ''' Read in first equation, ax + by = c '''a = int(input())b = int(input())c = int(input()) ''' Read in…
- void exchangeByValue (int x, int y) { printf ("\n\nOriginal x and y received: $d $d", x, y); int temp; temp =x; x=y; y=temp; printf("\nNew: id $d", x, y): } void exchangeByRef (int *x, int *y) { printf ("\n\nOriginal x and y received: $d $d", *x, *y); int temp; temp = *x; *x = *y; *y = temp; printf ("\nNew: id $d", *x, *y); } а. Show the output b. Trace the output (show the tracing using drawing). Explain your answer if necessary.//Assignment 06 */public static void main[](String[] args) { String pass= "ICS 111"; System.out.printIn(valPassword(pass));} /* public static boolean valPassword(String password){ if(password.length() > 6) { if(checkPass(password) { return true; } else { return false; } }else System.out.print("Too small"); return false;} public static boolean checkPass (String password){ boolean hasNum=false; boolean hasCap = false; boolean hasLow = false; char c; for(int i = 0; i < password.length(); i++) { c = password.charAt(1); if(Character.isDigit(c)); { hasNum = true; } else if(Character.isUpperCase(c)) { hasCap = true; } else if(Character.isLowerCase(c)) { hasLow = true; } } return true; { return false; } }SEE MORE QUESTIONS