Write an application that accepts any number of String values from a user until they enter zzz or have entered 15 strings, and display them in ascending order.
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Write an application that accepts any number of String values from a user until they enter zzz or have entered 15 strings, and display them in ascending order.
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- Write an application that counts by five from 5 through 500 inclusive, and that starts a new line after every multiple of 50 (50, 100, 150, and so on). public class CountByFives { public static void main (String args[]) { // Write your code here } }public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current stringThis is the question - Write an application that accepts any number of String values from a user until they enter zzz or have entered 15 strings, and display them in ascending order. This is the code I have but it is wrong becuase I didn't get a single check right - import java.util.*; public class StringSort2 { public static void main(String[] args) { // Write your code here Scanner sc = new Scanner(System.in); String s = ""; System.out.print(""); ///loop works until string input is zzz or string length is greater than 15 while (true){ String input = sc.nextLine(); if(input.equalsIgnoreCase("zzz") || input.length()>15) break; s=input; } } }
- public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string. This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is, str = new StringBuilder(str).reverse().tostring(); A bit convoluted, but does what is needed without fuss or muss. Maybe one day the Java strings will come with the reverse method built in, just like the string data types of all sensible…public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string.This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is,str = new StringBuilder(str).reverse().toString(); Here's the tester it must pass: @Test public void testPancakeScramble() throws IOException {// Explicit test casesassertEquals("", P2J3.pancakeScramble(""));assertEquals("alu",…Fix the errors and send the code please // Application allows user to enter a series of words // and displays them in reverse order import java.util.*; public class DebugEight4 { public static void main(String[] args) { Scanner input = new Scanner(System.in); int x = 0, y; String array[] = new String[100]; String entry; final String STOP = XXX; StringBuffer message = new StringBuffer("The words in reverse order are\n"); System.out.println("Enter any word\n" + "Enter + STOP + when you want to stop"); entry = input.next(); while(!(entry.equals(STOP))) { array[x] = entry; ++x; System.out.println("Enter another word\n" + "Enter " + STOP + " when you want to stop"); entry = input.next(); } for(y = x - 1; y > 0; ++y) { message.append(array[y]); message.append("\n"); } System.out.println(message) }
- // Application allows user to enter a series of words // and displays them in reverse order import java.util.*; public class DebugEight4 { publicstaticvoidmain(String[] args) { Scanner input =newScanner(System.in); int x =0, y; String array[] =newString[100]; String entry; finalString STOP =XXX; StringBuffer message =new StringBuffer("The words in reverse order are\n"); System.out.println("Enter any word\n" + "Enter + STOP + when you want to stop"); entry = input.next(); while(!(entry.equals(STOP))) { array[x] = entry; ++x; System.out.println("Enter another word\n" + "Enter "+STOP+" when you want to stop"); entry = input.next(); } for(y = x -1; y >0; ++y) { message.append(array[y]); message.append("\n"); } System.out.println(message) }Lab Task 04: Include the methods in the file KMP_Implementation.txt in a complete Java program that prompts for and reads a text string and then a text pattern to search for in the text. It then displays the result of the search. Sample program runs: Enter the text: ABABСАВАВАВСАВАВСАВАВСАВАВКККАВАВСАВАВ Enter the pattern to search for: ABABCABAB Pattern found at these text starting indexes: 0 Enter the text: A KFUPM STUDENT Enter the pattern to search for: KFE Pattern not in text. 7 12 17 29// Displays five random numbers between // (and including) user-specified values import java.util.Scanner; public class DebugSix4 { publicstaticvoidmain(String[] args) { int high, low, count =0; finalint NUM =5; Scanner input =newScanner(System.in); System.out.print("This application displays " + NUM + " random numbers"+ "\nbetween the low and high values you enter"+ "\nEnter low value now... "); low = input.nextInt() System.out.print("Enter high value... "); high = inputnextInt(); while(low < high) { System.out.println("The number you entered for a high number, " + high + ", is not more than " + low); System.out.print("Enter a number higher than " + low + "... "); high = input.nextInt(); while(count <NUM) { double result = Math.random(); int answer = (int) (result *10+ low); if(answer <= higher) { System.out.print(answer + " "); ++count; } } System.out.println("End of Application"); } }
- // Displays five random numbers between // (and including) user-specified values import java.util.Scanner; public class DebugSix4 { public static void main(String[] args) { int high, low, count = 0; final int NUM = 5; Scanner input = new Scanner(System.in); System.out.print("This application displays " + NUM + " random numbers" + "\nbetween the low and high values you enter" + "\nEnter low value now... "); low = input.nextInt() System.out.print("Enter high value... "); high = inputnextInt(); while(low < high) { System.out.println("The number you entered for a high number, " + high + ", is not more than " + low); System.out.print("Enter a number higher than " + low + "... "); high = input.nextInt(); while(count < NUM) { double result = Math.random(); int answer = (int) (result * 10 + low); if(answer <=…// DebugFive2.java // Decides if two numbers are evenly divisible import java.util.Scanner; public class DebugFive2 { publicstaticvoidmain(Stringargs[]) { int num; int num2; Scanner input =newScanner(System.in); System.out.print("Enter a number "); num = input.nextInteger() System.out.print("Enter another number "); num2 = inputnextInt(); if((num % num2 ==0) && (num2 % num) ==0) System.out.println("One of these numbers is evenly divisible into the other"); else System.out.println("Neither of these numbers is evenly divisible into the other"); } }class Output{public static void main(String args[]){byte a[] = { 65, 66, 67, 68, 69, 70 };byte b[] = { 71, 72, 73, 74, 75, 76 };System.arraycopy(a , 0, b, 0, a.length);System.out.print(new String(a) + " " + new String(b));}} The output of the above Java code is ?
