Hello, can you please help me do parts 5, 6 and 8.I also attached a pic of the graph X. Calculate average (mean) At (s) of the three readings.2. Get the period T=4t (s)/10 (because you timed 10 periods!).3. Calculate period squared T² (s²) by squaring the period T.T (s)M (g)M (kg) At₁ (s)At₂ (s)Δt (s)At3 (s)1001502002500.050.10.150.20.25X6.378.09.8011-0111-228.109.7611.2412.46T² =6-318.149.9111.1911.166-28ms (measured value)=_8.13Q.811-1511.60.620.810.981.111.16477²kT² (S²)0.391.34YA. Graph T2 (s²) (on vertical axis) vs. M (kg) (horizontal axis). Perform a best fit line,read from your graph the intercept.5. By squaring eq. (3) you get:0.650.961.2347² (M + ² ms)k6.) Equation (4) states that T² is proportional to M withthe intercept.7. From your graph, read where the best-fit line intersects Y-axis, this value is yourintercept.Intercept=(4)m, asas the slope and47²3k125 15²0.19(unit?)47²3kms and solve for the8. Equate the value of the intercept determined in Step 7 tovalue of the ms. In this evaluation consider the value of k obtained from previousgraph. Show your calculation to get credit!(unit?) (calculated from intercept) Slope1.521-2310-960.650-SP(5²)0390-2D-20-₁15206-100.15Free Multi-Width Graph Paper from http://incomp10.200.25igraphpaper multwidth0.305⁰ M (kg)

Answered: Image /qna-images/answer/a08cbe5a-2a45-4f61-ac61-a13454a012aa.jpg

X Graph T² (s²) (on vertical axis) vs. M (kg) (horizontal axis). Perform a best fit line, read from your graph the intercept. 5. By squaring eq. (3) you get: (4) as the slope and -m, as 477² 3k 7² = 4² (M + ¹m₂) k 47² 6.) Equation (4) states that T2 is proportional to M with the intercept. k 7. From your graph, read where the best-fit line intersects Y-axis, this value is your intercept. Intercept= ms (measured value)=_ 0.19 15/5² (unit?) and solve for the ms 8. Equate the value of the intercept determined in Step 7 to value of the ms. In this evaluation consider the value of k obtained from previous graph. Show your calculation to get credit! 47² 3k (unit?) (calculated from intercept)

X Graph T² (s²) (on vertical axis) vs. M (kg) (horizontal axis). Perform a best fit line, read from your graph the intercept. 5. By squaring eq. (3) you get: (4) as the slope and -m, as 477² 3k 7² = 4² (M + ¹m₂) k 47² 6.) Equation (4) states that T2 is proportional to M with the intercept. k 7. From your graph, read where the best-fit line intersects Y-axis, this value is your intercept. Intercept= ms (measured value)=_ 0.19 15/5² (unit?) and solve for the ms 8. Equate the value of the intercept determined in Step 7 to value of the ms. In this evaluation consider the value of k obtained from previous graph. Show your calculation to get credit! 47² 3k (unit?) (calculated from intercept)

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter1: Physics And Measurement

Section: Chapter Questions

Problem 1.29P

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