You have an array containing the heights of n vertical lines drawn such that the two endpoints of the ith line are (i, 0) and (i, height[i]). Your task is to find the maximum volume of liquid that can hold by these lines. Program Specification: Language: Java Time Complexity: O(n) Space Complexity: 0(1)
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- void deleteRange( int from, int to) { int i, j = 0; for (i = 0; i < counter; i++) { if (i <= from - 1 || i >= to + 1) { A[j] = A[i]; j++; } } for (int i = 0; i < j; i++) cout << A[i] << " "; } Above method deletes range of elements from an array. Please explain the logic of above code in simple english (algorithm and comments).void deleteRange( int from, int to) {int i, j = 0;for (i = 0; i < counter; i++) {if (i <= from - 1 || i >= to + 1) {A[j] = A[i];j++;}}for (int i = 0; i < j; i++)cout << A[i] << " ";} Above method deletes range of elements from an array. Consider array A[] globally declared and counter is its size. Please explain the logic of above code in simple english (algorithm and comments).code in java pls Summary: Given integer values for red, green, and blue, subtract the gray from each value. Computers represent color by combining the sub-colors red, green, and blue (rgb). Each sub-color's value can range from 0 to 255. Thus (255, 0, 0) is bright red, (130, 0, 130) is a medium purple, (0, 0, 0) is black, (255, 255, 255) is white, and (40, 40, 40) is a dark gray. (130, 50, 130) is a faded purple, due to the (50, 50, 50) gray part. (In other words, equal amounts of red, green, blue yield gray). Given values for red, green, and blue, remove the gray part. Ex: If the input is: 130 50 130 the output is: 80 0 80 Find the smallest value, and then subtract it from all three values, thus removing the gray.
- int sum, k, i, j; int x[4] [4]={5,6,7,8},{1,2,3,4},{9,8,7,3},{2,1,7,1}; sum=0; for (i=1; i x[i-1][j] ) sum++; Give the value of sum after the statements are executed.int functionC (int n) { int i, j, sumC = 0; for (i=n; i > 0; i=i-5) for (j=1; j 0) { if (functionC(n) % 2 == 0) { for (i=m; i > 0; i=i/3) sumE++; } else (10) Asymptotic runtime of functionE { for (i=m; i > 0; i=i-3) sumE--; } n--; } return sumE;In Python Programming Language: In the given array arr= [1,7,4,-6,2,18,9,16,13] find the sum of only even values and print it.
- int sum, k, i, j; int x[4] [4]={1,2,3,4}, {5,6,7,8},{9,8,7,3},{2, 1,7,1}; sum=x[0] [0]; for (k=1; k<=3;k++) sum+=x[k] [k]; Give the value in sum after the statements are executed:Write in python programming language: The Longest Subsequence Problem is a well-studied problem in Computer Science, where given a sequence of distinct positive integers, the goal is to output the longest subsequence whose elements appear from smallest to largest, or from largest to smallest. For example, consider the sequence S= [9,7,4,10,6,8,2,1,3,5]. The longest increasing subsequence of S has length three ([4,6,8] or [2,3,5]), and the longest decreasing subsequence of S has length five([9,7,4,2,1] or [9,7,6,2,1]). And if we have the sequence S = [531,339,298,247,246,195,104,73,52,31], then the length of the longest increasing subsequence is 1 and the length of the longest decreasing subsequence is 10. Question: Find a sequence with nine distinct integers for which the length of the longest increasing subsequence is 3, and the length of the longest decreasing subsequence is 3. Briefly explain how youconstructed your sequence. Let S be a sequence with ten distinct integers. Prove by…sum= 0; for (int i = 0; i 1) { sum++; i= 1/2; } = 2*log2 (n) We denote by Ta(n), Tb (n), Te(n) the running time of the three fragments. 1. Give evaluations for Ta(n), Tb (n), Te(n). 2. Is T(n) = O(Ta(n)) ? Answer YES or NO and justify your answer. 3. Is Te(n) = (Ta(n)) ? Answer YES or NO and justify your answer.
- Python Please. An interesting puzzler for chess buffs is the Knight’s Tour problem, originally proposed by the mathematician Euler. Can the knight piece move around an empty chessboard and touch each of the 64 squares once and only once? We study this intriguing problem in depth here. The knight makes only L-shaped moves (two spaces in one direction and one space in a perpendicular direction). Thus, as shown in the figure below, from a square near the middle of an empty chessboard, the knight (labeled K) can make eight different moves (numbered 0 through 7). A: Draw an eight-by-eight chessboard on a sheet of paper, and attempt a Knight’s Tour by hand. Put a 1 in the starting square, a 2 in the second square, a 3 in the third, and so on. Before starting the tour, estimate how far you think you’ll get, remembering that a full tour consists of 64 moves. How far did you get? Was this close to your estimate? B: Now let’s develop a script that will move the knight around a chessboard…Note: Answer the question using Java language only. Shaker is the first child who got scholarship into the village. He went to London to study where he finds it very interesting to calculate number of ways of going to point (c, d) from point (a, b) in co-ordinate plane. We can take horizontal and vertical steps only and cannot visit at a point twice. In a step, you can move one unit only. We have to reach to the point (c, d) from the point (a, b) using abs(a-c) + abs(b-d) steps only. Shaker has two sets of points. Set A contains points having X co- ordinate 0 and Y co-ordinates varying from 1 to N (both inclusive). Set B contains points having X co-ordinate K and Y co-ordinates varying from 1 to N (both inclusive). Both sets contain N number of integral points. He wants to calculate the sum of number of ways to going to each point of set B from each point of set A. Input 1 22 Output 81. Write a linear (0(n)) running time complexity program in Java to find all the dominant elements in the given array of n distinct integer elements. An element is a dominant element if it is greater than all the elements to its right side. The rightmost element in the array is always a dominant element. For example, in the array {16, 17, 4, 3, 5, 2}, dominant elements are 17, 5 and 2. 2. Prove that your algorithm takes (0(n)) running time to compute this task. Formulate the sum equation for this proof.