You should have observed that the general pattern using the fractional format is: 2n 8642 I(n) = 2 2n+1 9 7 5 23 5.1 Use this fractional pattern to show that: 22n+1 (n!)² I(n) = (2n+1)! . Recall that n! = n (n-1) (n-2)-4.3.2.1 4 • 60 00100 4 6 8 Hint: Multiply the fractional pattern by the newly formed expression to its final form. 2n 2n and modify

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter11: Rational And Irrational Numbers
Section11.2: Decimal Forms Of Rational Numbers
Problem 42WE
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You should have observed that the general pattern using the fractional
format is:
2n
8642
I(n) = 2
2n+1
975
23
5.1 Use this fractional pattern to show that:
22n+1 (n!)²
I(n) =
(2n+1)!
Recall that n! = n (n-1) (n-2)...4.3.2.1
Hint: Multiply the fractional pattern by
44
.
60
8
2n and modify
00100
4 6 8
the newly formed expression to its final form.
2n
Transcribed Image Text:You should have observed that the general pattern using the fractional format is: 2n 8642 I(n) = 2 2n+1 975 23 5.1 Use this fractional pattern to show that: 22n+1 (n!)² I(n) = (2n+1)! Recall that n! = n (n-1) (n-2)...4.3.2.1 Hint: Multiply the fractional pattern by 44 . 60 8 2n and modify 00100 4 6 8 the newly formed expression to its final form. 2n
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