You start your experiments with the eyeless mutation on chromosome IV. You cross the reciprocal translocation strain to the eyeless pure line to generate F, flies that are both translocation heterozygotes and Ee heterozygotes. You decide to testcross F, males and females in two separate experiments to take advantage of the fact that crossing over does not occur in male Drosophila. F, males x pure eyeless females (Note: There is no crossing over F, females x pure eyeless males (Note: Crossing over in the F, males.) Cross may occur in the F, females.) 4 eyeless, fully fertile 4 wild-type, semi-sterile 4 eyeless, semi-sterile 4 wild-type, fully fertile % eyeless, fully fertile 4 wild-type, semi-sterile 4 eyeless, semi-sterile 4 wild-type, fully fertile F, Progeny What can you conclude from these results? Select the two correct statements. > View Available Hint(s) O The F2 progeny in both experiments contain recombinants. O The F2 progeny contain recombinants only when F, females are testcrossed. None of the F2 progeny classes require crossing over. O Chromosome IV is one of the chromosomes involved in the reciprocal balanced translocation.

You start your experiments with the eyeless mutation on chromosome IV. You cross the reciprocal translocation strain to the eyeless pure line to generate F, flies that are both translocation heterozygotes and Ee heterozygotes. You decide to testcross F, males and females in two separate experiments to take advantage of the fact that crossing over does not occur in male Drosophila. F, males x pure eyeless females (Note: There is no crossing over F, females x pure eyeless males (Note: Crossing over in the F, males.) Cross may occur in the F, females.) 4 eyeless, fully fertile 4 wild-type, semi-sterile 4 eyeless, semi-sterile 4 wild-type, fully fertile % eyeless, fully fertile 4 wild-type, semi-sterile 4 eyeless, semi-sterile 4 wild-type, fully fertile F, Progeny What can you conclude from these results? Select the two correct statements. > View Available Hint(s) O The F2 progeny in both experiments contain recombinants. O The F2 progeny contain recombinants only when F, females are testcrossed. None of the F2 progeny classes require crossing over. O Chromosome IV is one of the chromosomes involved in the reciprocal balanced translocation.

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter13: Genes, Chromosomes, And Human Genetics

Section: Chapter Questions

Problem 8TYK: Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene...

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You continue your experiments with the black mutation on chromosome II. You cross the reciprocal translocation strain to the black pure line to generate F, flies that are both translocation heterozygotes and Bb heterozygotes. As before, you testcross F¡ males and females in two separate experiments. F1 males x pure black females (Note: There is no crossing over in the F1 males.) F, females x pure black males (Note: Crossing over may occur in the F, females.) Cross 424 black, fully fertile 426 wild-type, semi-sterile 73 black, semi-sterile 77 wild-type, fully fertile 1/2 black, fully fertile 1/2 wild-type, semi-sterile F2 Progeny What can you conclude from these results? Select the three correct statements. The F2 progeny in both experiments contain recombinants. The F2 progeny contain recombinants only when F, females are testcrossed. None of the F2 progeny classes require crossing over. Some of the F2 progeny classes require crossing over; others do not. Chromosome Il is one of the…
EC1. In drosophila the cw (curly wings) gene and eb (ebony body) genes are found on the same chromosome 20 map units apart. A cross was made between an ebony bodied parental strain and a curly winged parental strain and the F1’s were test crossed. a) What are the genotypes of the parental strains? b) What are the genotypes of the F1’s? c) What is the genotype of the tester strain? d) What progeny phenotypes and genotypes do you expect, and in what proportions? For phenotypes use the mutant phenotype for any that the flies have, and wild-type if they have none. EC2. Here is a tetrad produced by mating a H Y strain to an h y strain. a) What is the tetrad type? b) What has recombined with what? EC3. In corn, a dihybrid for the recessive genes a and b is test-crossed. The distribution of the phenotypes is as follows: A B 122A b 118a B 81a b 79 a) Do the genes appear to be sorting independently? Look at map units here. b) Test your hypothesis with a chi-squared test.
Females of wild-type Strain A and males of mutant Strain B, as well as females of mutant Strain B and males of wild-type Strain A, make reciprocal crosses. Explain why reciprocal crosses are needed in genetics experiments involving Drosophila fruit flies.
Part A A cross in Drosophila melanogaster involved the recessive X-linked genes for white eye (w), yellow body (y), and cut wings (c). A wild-type tri-hybrid female was crossed with wild-type males and only the male offspring were tallied. On the basis of the results shown below, which of the choices shown best represents the genetic map of the three loci on the X-chromosome? Phenotype Male Offspring + y ct 63 W + + 60 w y ct 16 + + + 11 + + ct w y + 2 +у + 247 w + ct 197 5.5 mu 21.5 mu ct 5.5 mu 21.5 mu ct 21.5 mu 5.5 mu y w ct 4.5 mu 20.5 mu ct 20.5 mu 4.5 mu y ct
You are given a Drosophila female that looks wild-type but is heterozygous for mutations intan body (t), miniature wings (m), and white eyes (w). You test cross this female with a tanbodied, miniature winged, and white-eyed homozygous mutant male, and you obtain thefollowing 1400 progeny: Phenotype : number+ + + : 608t m w : 516+ m w : 2t + + : 6+ m + : 39t + w : 46+ + w : 81t m + : 102 Calculate the distance between each pair t-m, m-w, and t-w only using the number ofrecombinants between them (i.e. ignoring the gene in the middle). Draw a linear map with thedistances between genes.
While working with Drosophila, you discover a mutant with green eyes. You first create a strain of fliesthat are pure-breeding for this mutation (but wild-type for everything else). You name the mutant genegrn and set out to discover which chromosome it is on and begin to map its location. In one experiment,you cross grn flies with min flies (miniature wings) to create flies that are hybrid for both traits (F1 flies).Then, you cross the F1 flies with each other to generate F2 flies.1.) What chromosome is the gene called “miniature wings” on? (Use the genetic map from thetextbook, also found in the PPT presentation for chapter 4.)2.) What percentage of the F2 flies will be double-mutant (green eyes and miniature wings)?Next, you perform another experiment. This time, you first take the F2 double-mutant flies from the firstcross and cross them with double wild-type flies to create a new batch of double-hybrids (F1).3.) Give the genotypes of the P1 cross described above.4.) Give the…
In Drosophila, Dichaete (D) is a mutation on chromosome III witha dominant effect on wing shape. It is lethal when homozygous.The genes ebony body (e) and pink eye (p) are recessive mutations on chromosome III. Flies from a Dichaete stock were crossed to homozygous ebony, pink flies, and the F1 progeny with a Dichaete phenotype were backcrossed to the ebony, pink homozygotes. Question: a.) Using the results of this backcross shown in the following table, diagram the cross, showing the genotypes of the parents and offspring of both crosses. b.) What is the sequence and interlocus distance between thesethree genes? Phenotype NumberDichaete 401ebony, pink 389Dichaete, ebony 84pink 96Dichaete, pink 2ebony 3Dichaete, ebony, pink 12wild type 13
Cat fur coat color genetics is interesting. Orange fur is dominant (''B'') to black fur (''b'') and piebald, which is white spotting, is dominant (''S'') to non-white-spotted (''s''). Both of those genes are located on the X chromosome. In addition, in cats, somatic cells exhibit X-inactivation randomly, which explains why there are tortoiseshell cats (when heterozygous, have orange and black spots) as well as calico cats (orange and black but also with white spots). An orange and white spotted male is mated with a tortoiseshell female. Draw a dihybrid Punnet square to show the possible offspring:
Cat fur coat color genetics is interesting. Orange fur is dominant (''B'') to black fur (''b'') and piebald, which is white spotting, is dominant (''S'') to non-white-spotted (''s''). Both of those genes are located on the X chromosome. In addition, in cats, somatic cells exhibit X-inactivation randomly, which explains why there are tortoiseshell cats (when heterozygous, have orange and black spots) as well as calico cats (orange and black but also with white spots). An orange and white spotted male is mated with a tortoiseshell female. State the genotype of the male and the female.
4) You design Drosophila crosses to provide recombination data for gene (A), which is located somewhere on the chromosome shown below: Short aristae Long aristae (appendages on head) III Black body Gray body Mutant phenotypes Cinnabar eyes 48.5 57.5 Red eyes 67.0 Vestigial wings Normal wings Brown eyes 104.5 Red eyes Wild-type phenotypes Gene (A) has a recombination frequency of 14% with the vestigial-wing locus and 23% with the brown- eye locus. Where is gene (A) located on this chromosome?
In Drosophila, the wildtype eye color is black. In the laboratory, you screened for mutants than when homozygous results to different eye phenotypes. You found two mutants 1) red eye (re) and 2) white eye (we). You performed a complementation test and the resulting eye phenotype was gray. From the results, what conclusion can you make? A. There was complementation, thus the two mutations are alleles of different genes. B. There was no complementation, thus the two mutations are alleles of different genes. C. The two mutations failed to complement, thus they are alleles of different genes. D. The two mutations failed to complement, thus they are alleles of the same genes. E. The two mutations complemented, hence they are likely controlled by different genes.
In Drosophila, Dichaete (D) is a mutation on chromosome III with a dominant effect on wing shape. It is lethal when homozygous. The genes ebony body (e) and pink eye (p) are recessive mutations on chromosome III. Flies from a Dichaete stock were crossed to homozygous ebony, pink flies, and the F1 progeny, with a Dichaete phenotype, were backcrossed to the ebony, pink homozygotes. Using the results of this backcross shown in the table, (a) Diagram this cross, showing the genotypes of the parents and offspring of both crosses. (b) What is the sequence and inter locus distance between these three genes?