You want to use a random graph G(N, p) with N = 10¹¹ to best approximate a Poisson random graph with average degree (k) 100. Which p would you prefer to use? Select one: a. p = 10-11 P = 0.001 C. p = 0.00000001 Ob. O d. p= = 10-⁹
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- Peak heart rate was determined both during a shuttle run and during a 300-yd run for a sample of n=10 individuals with Down Syndrome. The following ordered pairs reveal the shuttle run heart rate (x) and the 300 yd run heart rate (y) for each individual. (168, 184) (168, 192) (188, 200) (172, 192) (184, 188) (176, 180) (192, 182) (172, 188) (188, 196) (180, 196) At the 5% level of significance, is there sufficient evidence to support the claim that there is no significant linear relationship between the two quantities?Identify sample (observed) proportion. This is P(Obs) in the z-formula. Identify population proportion. This is P(Pop) in the z formula. Compute a z score using the formula. Proportion of females among applicants: P(pop) = 43/109 = .39 Proportion of females among hired: P(obs) = 6/24 = .25 N = 24 My attempt but I think I am doing an order wrong. z = .25-.39/SR.39*((1-.39)/24) .25-.39 = -.14 1-.39 = .61 .61/24 = .025 .39*.025 = .00975 SR .00975 = .0987 -.14/.0987 = -1.42 Z = -1.42 z = .25-.39/SR.39*((1-.39)/24) .25-.39 = -.14 1-.39 = .61 .61/24 = .025 .39*.025 = .00975 SR .00975 = .0987 -.14/.0987 = -1.42 Z = -1.42A researcher collects data that represents the average number of hours of sleep in the last two nights by 8 depressed patients and 9 non-depressed patients. The researcher is interested in whether the two groups reliably differ in the amount of sleep they get. Use Jamovi to calculate t-obt and the p value.
- Pain: A recent survey asked 804 people how many days they would wait to seek medical treatment if they were suffering pain that interfered with their ability to work. The results are presented in the following table.. tab F =lock fn esc ➜ esign. Skip Part Ⓡ Part: 0/5 1 ? Number of Days 0 Consider these 804 people to be a population. Let X be the number of days for a person sampled at random from this population. Type here to search Q A H N hp 1 @ 2 3 Send data to Excel 2 4 5 Total Check W S (F3 ak # 3 X alt Frequency 25 429 260 65 E D $ 16 9 804 O V 4 O R % F 5 T no 40 G 6 & V C Y 99+ 7 H hp a U B N + 8 J © 2023 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center AODE S O 144 ( 9 M 111 > O " AMI FAR TOPY KL Save For Later Submit Assignment Accessibility 40 2/21/2023 9:22 PM { alt [ ? T Insert . ← 1 prt sc ctri pause olo A 9 backspace Espa 00 USE YOUR SMARTPHONE FOR Reviews Videos Features Specs Support E SCAN de (If n(A) = 61, n(B) = 18, and n(A N B) = 5, find n(A U B). %3D Need Help? Read It If n(A U B) = 97 and n(A) n(B) = 62, find n(A N B). %3D %3! 74 Need Help? Watch It Read It Viowing Sena. 5.One sample of scores has a mean of M = 40 and a sample size of n = 15 scores. A second sample of scores has M = 55 and n = 40. Find the weighted mean of the two samples.
- Match the value of the corelation to the data in the scatterplot. (a) (b) (c) Ar=-0.51 vScatterplot (a) vScatterplot (b) VScatterplot (c) vScatterplot (d) B.r= 0.89 C.r = 0.99 D.r= - 0.12Which z-score has the higher frequency? (a) z = +1.0 or z = +2.3; (b) z = −2.8 or z = −1.7; (c) z = −.70 or z = −.20; (d) z = 0.0 or z = −2.0.We used technology to simulate selecting 100 SRSS of size n = 50 from a population of pennies in which 13.2% are pre-1982 copper pennies. The dotplot shows p = the sample proportion of copper pennies for each of the 100 samples. 4. There is one dot on the graph at 0.22 (or 22%). Explain what this dot represents. 5.0% 10.0% 15.0% 20.0% 25.0% Simulated sample percent of Copper Pennies 30.0% 5. Assuming that 13.2% of pennies in circulation are pre-1982 copper pennies, is it surprising to randomly select 50 pennies for which p = 11/50 = 22% or greater? Justify your answer. 6. Based on your previous answers, is there convincing evidence that more than 13.2% of pennies in Jenna's container are pre-1982 copper pennies? Explain your reasoning.
- find p (-1<z<1) refer to the table of z-scoresThe sample variance, ² - Σ(x-x)² n-1 {14, 13, 16, 9, 3, 7, 11, 12, 11, 4} is I of the dataA simple random sample of 1,000 people is taken to estimate the percentage of Democrats in a large population. It turns out that 543 of the people in the sample are Democrats. The sample percentage is (543/1000) x 100% = 54.3%. The SE for the sample percentage of Democrats is 1.6%. (You don't need to check this calculation.)(a) TRUE or FALSE (circle one): (51.1%, 57.5%) is a 95%-confidence interval for the percentage of Democrats in the population.Explain your answer.(b) TRUE or FALSE (circle one): (51.1%, 57.5%) is a 95%-confidence interval for the percentage of Democrats in the sample.Explain your answer.(c) TRUE or FALSE(circle one): There are about two chances in three for the percentage of Democrats in the population to be in the range (52.7%, 55.9%). Explain your answer.