You would like to develop a new galvanic cell and decide to use two very toxic electrode materials, mercury and cadmium. But because they are toxic, you decide to use a low concentration of each material. Cd I Cd²+ (0.20M) 1. The ◆ electrode is the anode, and the 2. Write the two half equations and the balanced overall equation: The half reaction for chromium (hint written as a reduction): The half reaction for mercury (hint written as a reduction): Overall reaction balanced equation is: Eºcell = Ecell = ◆ Has the voltage improved? is the cathode + 3. What is the Eºcell and the Ecell of this reaction? Have you improved your battery by reducing the concentration? Hint: use the Nerst equation E = E° -RT/nF x(InQ) || Hg²+ (0.10M) I Hg

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Chapter19: Electrochemistry
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Problem 19.43QP: A voltaic cell is constructed from the following half-cells: a chromium electrode in chromium(III)...
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You would like to develop a new galvanic cell and decide to use two very toxic electrode materials, mercury and cadmium.
But because they are toxic, you decide to use a low concentration of each material.
Cd I
Cd²+ (0.20M)
1. The
electrode is the anode, and the
2. Write the two half equations and the balanced overall equation:
The half reaction for chromium (hint written as a reduction):
The half reaction for mercury (hint written as a reduction):
Overall reaction balanced equation is:
Eºcell
+
Ecell =
◆ is the cathode
Has the voltage improved? ◆
||
3. What is the Eºcell and the Ecell of this reaction? Have you improved your battery by reducing the concentration? Hint: use the Nerst equation E = E° -RT/nF x(InQ)
Hg²+ (0.10M) |
Hg
Transcribed Image Text:You would like to develop a new galvanic cell and decide to use two very toxic electrode materials, mercury and cadmium. But because they are toxic, you decide to use a low concentration of each material. Cd I Cd²+ (0.20M) 1. The electrode is the anode, and the 2. Write the two half equations and the balanced overall equation: The half reaction for chromium (hint written as a reduction): The half reaction for mercury (hint written as a reduction): Overall reaction balanced equation is: Eºcell + Ecell = ◆ is the cathode Has the voltage improved? ◆ || 3. What is the Eºcell and the Ecell of this reaction? Have you improved your battery by reducing the concentration? Hint: use the Nerst equation E = E° -RT/nF x(InQ) Hg²+ (0.10M) | Hg
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