Your task is simply to draw a box given an integer N, but there are catches to consider 1. The size of the box that you will draw will be size V where [N/10] (known as floor(N/10)). 2. The border of the box, draw the tens digit of the value of N 3. Inside the box, fill it with the remainder obtained from dividing N by 10.

Your task is simply to draw a box given an integer N, but there are catches to consider 1. The size of the box that you will draw will be size V where [N/10] (known as floor(N/10)). 2. The border of the box, draw the tens digit of the value of N 3. Inside the box, fill it with the remainder obtained from dividing N by 10.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

This challenge is based on the classic videogame "Snake". Assume the game screen is an n * n square, and the snake starts the game with length 1 (i.e. just the head) positioned on the top left corner. For example, if n = 7 the game looks something like this: BEGINNING In this version of the game, the length of the snake doubles each time it eats food (e.g. if the length is 4, after eating it becomes 8). Create a function that takes the siden of the game screen and returns the number of times the snake can eat before it runs out of space in the game screen. Examples FIRST MOVE snakefill (3) snakefill (6) - 5 snakefill (24) → 9 3
This method returns a string with a number of vertical bars that correspond to the bars parameter. The method most not rely on System.out.println(). No arrays. For example calling DrawingApp.getVerticalBars(10, 12, 3, ‘A’, ‘B’, ‘C’);
You have N boxes in Samosas, where each box is a cube. To pack the box, you need to use a rubber band (pseudo-circular, elastic band) by placing it next to the box (4 faces of a cube). The rubber band A (R1, R2) has an initial radius of R1 and can be expanded in size up to R2 without breaking. You can pack a cubic box of side length L using a 4 * L round rubber band (see Notes for clarity). Given the M-band bands and their first radius and the main radius, we need to match (provide) some rubber bands and boxes. The box needs at least one rubber band to pack and of course, each rubber band can be used to pack at least one box. Find the maximum number of boxes we can pack. Answer this in java programming language. Input Output 2 1 4 10 20 34 55 4 714 7 21 14 21 7 35
Add a new method to ArrayTools with filter. Make this method accept a String array. Change all the Strings that are longer than 5 characters to uppercase. Write in Java and use test cases 1 & 2 as a result.
You have N boxes in Samosas, where each box is a cube. To pack the box, you need to use a rubber band (pseudo-circular, elastic band) by placing it next to the box (4 faces of a cube). The rubber band A (R1, R2) has an initial radius of R1 and can be expanded in size up to R2 without breaking. You can pack a cubic box of side length L using a 4* L round rubber band (see Notes for clarity). Given the M-band bands and their first radius and the main radius, we need to match (provide) some rubber bands and boxes. The box needs at least one rubber band to pack and of course, each rubber band can be used to pack at least one box. Find the maximum number of boxes we can pack. Answer this in python programming language. Input Output 2 1 4 10 20 34 55 4 714 7 21 14 21 7:35
Use the Iterator Pattern: Create a class called Exercise, and then, in its main method, create an ArrayList called stringArrayList. Add the following five strings to stringArrayList: “one”, “two”, ”three”, ”four”, ”five”. Then, use a for loop and the index of stringArrayList to print all these five strings out to the console. 2. For stringArrayList above, can you use an iterator to traverse the five strings inside, without using the index? 3. If change stringArrayList into a TreeSet, how do you traverse the five strings use an iterator? Implement an Iterator: 4. Create a class called StringArray that is able to store a number of String objects. Create an instance variable, String[] values, (internal data storage) of StringArray to store all the strings. 5. Create a constructor for StringArray, which is able to build an object of StringArray using the parameter. public StringArray(String[] values) 6. Make the class StringArray implements Iterable So that it…
Write a method that calculates and prints both the maximum humidity and maximum temperature values from the abq_weather_cleaned.csv data set. You should write your method in the data Visualization class we have been working on in lecture. Your method should use all of the variables that are already part this program. In particular, you will need to use the data array variable. Your method should return nothing and take no input parameters; it's signature should be void max (). Your print outs should look like this: The max humidity is: 58 The max temperature is: 70
Complete the recursive drawBoxes() method so that it will draw all of the boxes in the image below. It currently only draws the first and smallest Box. Feel free to use a different shape if you do not like boxes.
Write a method that calculates and prints both the maximum humidity and maximum temperature values from the abq_weather_cleaned.csv data set. You should write your method in the dataVisualization class we have been working on in lecture. Your method should use all of the variables that are already part of this program. In particular, you will need to use the data array variable. Your method should return nothing and take no input parameters; it's signature should be void max (). Your print outs should look like this: The max humidity is: 58 The max temperature is: 70
For any element in keysList with a value greater than 100, print the corresponding value in itemsList, followed by a space. Ex: If keysList = {42, 105, 101, 100} and itemsList = {10, 20, 30, 40}, print:20 30 Since keysList.at(1) and keysList.at(2) have values greater than 100, the value of itemsList.at(1) and itemsList.at(2) are printed. #include <iostream>#include <vector>using namespace std; int main() { const int SIZE_LIST = 4; vector<int> keysList(SIZE_LIST); vector<int> itemsList(SIZE_LIST); unsigned int i; for (i = 0; i < keysList.size(); ++i) { cin >> keysList.at(i); } for (i = 0; i < itemsList.size(); ++i) { cin >> itemsList.at(i); } /* Your solution goes here */ cout << endl; return 0;}
For any element in keysList with a value greater than 100, print the corresponding value in itemsList, followed by a space. Ex: If keysList = {42, 105, 101, 100} and itemsList = {10, 20, 30, 40}, print: 20 30 Since keysList.at(1) and keysList.at(2) have values greater than 100, the value of itemsList.at(1) and itemsList.at(2) are printed. #include <iostream>#include <vector>using namespace std; int main() {const int SIZE_LIST = 4;vector<int> keysList(SIZE_LIST);vector<int> itemsList(SIZE_LIST);unsigned int i; for (i = 0; i < keysList.size(); ++i) {cin >> keysList.at(i);} for (i = 0; i < itemsList.size(); ++i) {cin >> itemsList.at(i);} /* Your solution goes here */ cout << endl; return 0;} Please help me with this problem using c++.
You are required to write a JApplet that produces a picture similar to the illustration below, and whose top-left corner is at (0,0).