Step 1: The volume of the quarter-sphered tank rounds up to 478,676. You use the condition to find the volume. Volume of Sphere: V=4/3(3.14)R^3 V=4/3(3.14)(70)^3 V=4/3(1,077,020) V=478675.5555555556 – I ran this through plag checker I don’t know if it’s saying plagiarized because others have used this answer or not so if there is another way to write this answer change it. Step 2: The volume of both tanks is equivalent to 84,780. You utilize the recipe, and module the numbers to get the answer. Volume of Cylinder: V=(3.14)R^2H V=(3.14)(15)^2(120) V=(3.14)(225)(120) V=84,780 – Same here I ran this through plag checker I don’t know if it’s saying plagiarized because others have used this answer or not so if there is another …show more content…
Using the right formula, and module the numbers for the answer. D=mass/volume D=0.000011142 V=478675.5555555556 M=(0.000011142)(478675.5555555556) M= 5.33340304 Check step 3 cause open study says: The last calculation where you calculated the volume of the sphere is off, my calculator says it is 1436026.66667, and your number got smaller by multiplying by 4/3. Somehow xD and if it is quarter sized does that mean 1/4 of a sphere Below is the rest of the questions you will have to finish. I have paraphrased all the rest You must show all steps and provide any evidence needed in your solution to receive full credit. 4. The theme park company is building a scale model of the killer whale stadium main show tank for an investor's presentation. Each dimension will be made 6 times smaller to accommodate the mock-up in the presentation room. How many times smaller than the actual volume is the volume of the mock-up?You can discover the answer by partitioning the old volume by the new volume. So first we locate the new volume of the tank by taking its measurements (it's span) and partitioning it by six. new span = (old range)/6 new span = 70/6 new span = …show more content…
Using the information from #4, answer the following question by filling in the blank: The volume of the actual tank is ____% of the mock-up of the tank.In step 1, you found the volume (in cubic feet) of the principle tank. In the event that the greatest thickness of executioner whales per cubic foot is 0.000011142, what is the most extreme number of executioner whales permitted in the primary show tank at any given time? You should clarify your answer utilizing words, and you should demonstrate all work and figurings to get credit. 1. 4/3*3.14 (70*70*70) = 1,436,026.67 ft 2. 1436026.67.4= 359,006.6675 3.14*15^2*120
47. The first container has 3 gallons 3 quarts 1 pint of diesel fuel, the second container has 5
56.78 g 60.33 g 56.78 g Initial measurement of water in the graduated cylinder 60.7 mL 62.3 mL 58.5 mL 57.2 mL Measurement of the graduated cylinder after metal #8 is added 67.3 mL 68.9 mL 65.3 mL 64.1 mL Volume 6.6 mL 6.6 mL 6.8 mL 6.9 mL Density 9.1 g/mL 8.6 g/mL 8.9 g/mL 8.2 g/mL IV. Calculations: 96.3 mL of water were in the Styrofoam cup.
The height of the water was measured in centimeters. The water height was measured using a ruler. The height of the water was recorded. Next, 19 mL of water were measured in a graduated cylinder. The 19 mL were poured into the bottle.
For question (2) he again used mental math and came to the conclusion that it was 4 feet/ounce of water. His rationale was the same as for (1b), to get back down to the base height. At this point, it
Avaneesh: This is the cylinder vase. It has the greatest volume. To solve for the volume, you first find the area of the base, which is 25. Then you multiply that by the height, which is 40, to get 1000. After that, you do 1000 times pi, or 3.14, which is 3140. Finally label in cubic centimeters.
1. Planet X has a radius 3 times larger than the earth’s radius. How does this planet’s volume compare to Earth’s volume?
The process that we will use for the water in the cylinder is we will fill a 100 ml mark and pour the contents in a dry 100ml flask about twice and we will find the percent difference. And to find the percent difference we will have to use the equation right here. For the Cube we will weigh six stoppers but once at a time and compare the results so that we could find the average of all six cubes.
This again perfectly matches the predicted volume that was calculated for the conical section of the External Tank.
The volume of the cube was easy to calculate by measuring its length, width, and height to multiply them altogether. The cubical object provided for lab was measured 2.5 cm in all the measurements. It was multiplied (2.5 cm)³ to be 16 cm³ as the volume for the cube.
For the square prism I had to find make it hold 0.5KL which is the same as 0.5m3. I made the length of the prism 1.5 and the Hight 1.5 but I needed to find the width so I put it as A. The equation is 0.5m3 = 1.5x1.5xA so I took the a out and it equals 2.25. Which made the equation 0.5m3 =2.25xA. I then divide 2.25 by 2.25 and it cancelled out but what you do to one side you do to the other so 0.5 divided by 2.25 = 0.22 which gave me the answer for a. In The equation I can now put 0.22 for a and then it would be, 1.15x1.15x0.22 = 0.495cm. Now for the square prism its basically the exact same but with the different measurements. Volume=LxWxH, the length is 2.5cm, the width is 2.2cm but we don’t know what the hight is. We need to fill 0.5m3, I don’t know a so I take it out and then it becomes 2.5x2.2 and that equals 5.5, so then we can do 0.5=5.5xA and if I divide 5.5x5.5 it cancels out and if you divide one side you divide the other so it would be 0.5 divided by 5.5 = 0.09. So we can now go to the equation and but the answer in, 2.5x2.2x0.09=0.495. I think the square would be better for a water feature because it would fit better and not be as wide, it would also be a good size, if I chose the rectangular prism it would be a lot wider and longer but not that tall which is pretty annoying I chose the square because it would be the easiest to build and it would be easier to get the measurements but a circle would be super hard. For my part b I have chosen the square prism because it would fit better, be easier to get measurements and it would be taller that
A sample of an unknown gas (gas A) has a volume of 3.2 m3 at a temperature of 10 °C. Another sample of an unknown gas (gas B) has a volume of 4.5 m3 at a
The results were recorded and the data was analysed with the calculations produced and double checked. RESULTS AND CALCULATIONS: Size of the cube Surface area(cm^2) Volume(cm^3) Surface area to volume ratio 1cm 6 1 6:1 s2cm 24 8 3:1 3cm 54 27 2:1 Cube size(cm) Dimensions of coloured section remaining(cm) Volume of coloured section remaining(cm^3) Initial volume of the cube (cm^3) Volume diffused(cm^3) %volume diffused 1 .5 .52 1 .48 48 2 1.6 4.096 8 3.904 48.8 3 2.5 15.625 27 11.375 42.1
Inflow from the tank was calculated using the known internal dimensions of the tank, the % full reading, and the time step which the data was collected.
The method of finding the volume of a solid with a known cross section is, very straightforward. We will
4. A car travels 12 kms with a 4/5th filled tank. How far will the car travel with 1/3 filled tank?