10) A solution is created by dissolving 14.2 grams of HCl (a strong acid) into water, making 2.63 Liters ofsolution. Calculate the Molarity of HCl, the [H+], and the pH of the solution. 10. M HCl = 0.148 M / [H+] = 0.148 M / pH = 0.829 Show step by step solutions 11) A basic solution is prepared to a measured pH of 12.45. Calculate the [OH-] and the [H+] of this solution [H+] = 3.548 x 10-13 M / [OH -] = 2.818 x 10-2 M Show step by step solutions
10) A solution is created by dissolving 14.2 grams of HCl (a strong acid) into water, making 2.63 Liters ofsolution. Calculate the Molarity of HCl, the [H+], and the pH of the solution. 10. M HCl = 0.148 M / [H+] = 0.148 M / pH = 0.829 Show step by step solutions 11) A basic solution is prepared to a measured pH of 12.45. Calculate the [OH-] and the [H+] of this solution [H+] = 3.548 x 10-13 M / [OH -] = 2.818 x 10-2 M Show step by step solutions
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter15: Solutions Of Acids And Bases
Section: Chapter Questions
Problem 15.112QE
Related questions
Question
10) A solution is created by dissolving 14.2 grams of HCl (a strong acid) into water, making 2.63 Liters of
solution. Calculate the Molarity of HCl, the [H+], and the pH of the solution.
10. M HCl = 0.148 M / [H+] = 0.148 M / pH = 0.829
Show step by step solutions
11) A basic solution is prepared to a measured pH of 12.45. Calculate the [OH-] and the [H+] of this solution
[H+] = 3.548 x 10-13 M / [OH -] = 2.818 x 10-2 M
Show step by step solutions
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