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4 πR³ 3 (b) The volume of a sphere of radius R is V=- Simplify as much as possible. Solve for R in terms of π and V.

4 πR³ 3 (b) The volume of a sphere of radius R is V=- Simplify as much as possible. Solve for R in terms of π and V.

Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter4: Polynomials
Section4.8: Rate-time-distance Problems
Problem 1OE
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1. For the following questions, you do not need to understand the physics. Just focus on working with the equations: To enter subscripts, press the first right-facing arrow by the superscript button in the menu of the popup. (a) Two resistors R₁ and R₂ in an electric circuit are connected in parallel. The effective resistance of the circuit is given by: (Simplify as much as possible and express the answer as a fraction.) 1 R = 1 1 + R₁ R₂ Solve for R in terms of R₁ and R₂: 1 R= R₁ R₂ R₁+R₂ 1 4πR³ (b) The volume of a sphere of radius R is V = - 3 Simplify as much as possible. R = 3v 4π x√ Solve for R in terms of π and V.
Transcribed Image Text:1. For the following questions, you do not need to understand the physics. Just focus on working with the equations: To enter subscripts, press the first right-facing arrow by the superscript button in the menu of the popup. (a) Two resistors R₁ and R₂ in an electric circuit are connected in parallel. The effective resistance of the circuit is given by: (Simplify as much as possible and express the answer as a fraction.) 1 R = 1 1 + R₁ R₂ Solve for R in terms of R₁ and R₂: 1 R= R₁ R₂ R₁+R₂ 1 4πR³ (b) The volume of a sphere of radius R is V = - 3 Simplify as much as possible. R = 3v 4π x√ Solve for R in terms of π and V.
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