4NH3+502 → 4NO + 6H20 The standard enthalpies of formation for NH3, NO and H2O are 294.1 kj/mol, 90.250 kj/mol and -241.82 kj/mol, respectively. Calculate the enthalpy of reaction at 389 K using the specific heat capacity equations of the components depending on temperature. j j Cp(NH3 mol. R) = 33,573 - 0, 012581T + 0,0000889067 Cp(0, - 29,526 0,00889 2' mol. K K =
4NH3+502 → 4NO + 6H20 The standard enthalpies of formation for NH3, NO and H2O are 294.1 kj/mol, 90.250 kj/mol and -241.82 kj/mol, respectively. Calculate the enthalpy of reaction at 389 K using the specific heat capacity equations of the components depending on temperature. j j Cp(NH3 mol. R) = 33,573 - 0, 012581T + 0,0000889067 Cp(0, - 29,526 0,00889 2' mol. K K =
Chapter6: Thermochemistry
Section: Chapter Questions
Problem 104AE
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