5' UTR OP This region is specific sequence surrounding the start codon. OK OS OT 5' and 3' UTR LEU2 KSTP 2μm plasmid DNA Gene of interest 2μm plasmid DNA GAPDI GAPDP SC Cu/Zn-SOD cDNA Amp oriE gene What is selectable gene in this vector? 3' UTR
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- BM4_DNA AND PROTEIN S X /1FAIPQLSDP_g5B-629FSHNpGnTMIEppLS4A71zBd4vcUBqNUILubXONw/formResponse 4. What is the nitrogen base pair of Adenine in transcription? O Cytosine O Uracil O guanine O thymine 5. The central dogma of Molecular Biology states that There are four nitrogen bases in DNA, two purines (adenine and guanine) and two pyrimidines (cytosine and thymine). Which process is not included in the central dogma? duplication transcription translation O translocation LeadpleAlternative splicing Template strand S F yIGUide1,mq00:c-00: Replisome Transforming principle Origin of replication (or)eleb al msxS ain Coding strand Transcription factors Leading strand Single nucleotide polymorphism Okazaki fragment Telomerase M Nucleoside RNA Polymerase I RNA Polymerase II RNA Polymerase IIIon & of qu 9ven UoY Insertion mutagenesis Spliceosome Transcription Unit SNP Reverse transcriptase 1 Seminal work by Oswald Avery and colleagues demonstrated that DNA is what Frederick Griffiths called this etniog OS dotsM bioW 1-2kb of newly synthesized DNA strands are called this ainiog PS Assembly of the replisome is an orderly process that begins at these precise sites Snoiteeu 4 Transcribes ribosomal RNA genes in eukaryotes 5. A large nucleoprotein complex that coordinates activity at the replication fork Single base pair differences between homologous genomic regions isolated from different members of a population Complex of proteins and snRNAs catalyzing the removal of…Figure 1 is a bacterial gene (1-180). The first base to be transcribed is the base located at position 77. 45 5' TTGGT CTTGG TCGGA TTCCA GAGGA TGAAG TGTTG ACAGC GCATT 3' 3 AACCA GAACC AGCCT AAGGT CTCCT ACTTC ACAAC TGTCG CGTAA 5' 46 5 AATTG ACCTT GCTGT ATTAT AGCCA AGGAC AGATC TACGA GCATG 3' 3 TTAAC TGGAA CGACA TAATA TCGGT TCCTG TCTAG ATGCT CGTAC 5' 91 5 TGCGA ACCGC AAGCA TTCGT TCTCC TAGGC TACTC GATCC CGTAA 3' 3 ACGCT TGGCG TTCGT AACCA AGAGG ATCCG ATGAG CTAGG GCATT 5 77 90 110 135 136 5 TGATG TAGCT GATTC TGTTG AAAGG CTCCT TTTGG AGCCT TTTTT 3 3' ACTAC ATCGA CTAAG ACAAC TTTCC GAGGA AAACC TCGGA AAAAA 5 156 180 Figure 1. Illustrate how termination of transcription occurs in the gene above. (Hint: position from 156 to 180)
- What would the amino acid sequence be for the following DNA Transcript? 5’AAGCCATTTAAAGGC 3’ 3’ TTCGGTAAATTTCCG 5’ Phe Gly Lys Phe Pro Phe Leu Lys Phe Val Lys Phe Phe Lys Pro Lys Pro Phe Lys Gly More information is neededFigure 1 is a bacterial gene (1-180). The first base to be transcribed is the base located at position 77. 45 5 TTGGT CTTGG TCGGA TTCCA GAGGA TGAAG TGTTG ACAGC GCATT 3' 3 AACCA GAACC AGCCT AAGGT CTCCT ACTTC ACAAC TGTCG CGTAA 5 46 77 90 5' AATTG ACCTT GCTGT ATTAT AGCCA AGGAC AGATC TACGA GCATG 3' 3 TTAAC TGGAA CGACA TAATA TCGGT TCCTG TCTAG ATGCT CGTAC 5' 91 110 5 TGCGA ACCGC AAGCA TTCGT TCTCC TAGGC TACTC GATCC CGTAA 3' 3 ACGCT TGGCG TTCGT AACCA AGAGG ATCCG ATGAG CTAGG GCATT 5' 135 136 5 TGATG TAGCT GATTC TGTTG AAAGG CTCCT TTTGG AGCCT TTTTT 3 3 ACTAC ATCGA CTAAG ACAAC TTTCC GAGGA AAACC TCGGA AAAAA 5 156 180 Figure 1. (i) Identify both the hexameric sequences of the promoter region in the coding strand above.Cynt Classifying mutations A certain section of the coding (sense) strand of some DNA looks like this: $-ATGTATATCTCCAGTTAG-3" It's known that a very small gene is contained in this section. Classify each of the possible mutations of this DNA shown in the table below. mutant DNA 5- ATGTATCATCTCCAGTTAG-3' S-ATGTATATCTCCAGTTAG-3 5- ATGTATATATCCAGTTAG-3' type of mutation (check all that apply) insertion deletion point silent noisy insertion O deletion point silent noisy insertion O deletion point silent Onoisy X G
- 40 Shown below is the antisense strand of DNA. What is the amino acid sequence that corresponds to this code? 5' AAAGCATACCGG 3' Second letter G. UUU Phe UCU UAU) Tyr UGC Cys UGU UUC UCC UAC Ser UAA Stop UGA Stop A UAG Stop UGG Trp UUA UCA UUG Leu UG CAU His CGU CGC CGA CGG CU CUU CUC CUA CUG CAC Pro Leu Arg CCA CAA) Gin CCG CAG AAU AUU AUC lle AUA AUG Met ACG ACU AGU AAC Asn AGC Ser ACC ACA Thr AAA1 AGA AAG Lys AGG Arg GAU) Asp GGC GAC Ala GAA GGU GUU GUC GUA Val GCU GCC Gly GCA GGA Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a PRO-VAL-SER-PHE PHE-ARG-MET-ALA GLY-HIS THR-LYS d LYS-ALA-TYR-ARG First letter Third letter48 Second letter If any single nucleotide is deleted from the DNA sequence shown below, what type of mutation is this? UUU U UUC UUA UCU Phe UCC UAU UGU Cys ANTISENSE 5' GGACCCTAT3' UAC Tyr UGC UAA Stop UGA Stop UAG Stop UGG Trp Ser UCA Leu UUGL" UCG CUU CU CAU) His CAC) CGU CGC CGA Arg CUC C Leu Pro CAA1 Gin CAG) CUA CCA CUG CG CGG AAU AAC Asn AGC AAA AAG Lys AGG Arg AUU ACU AGU Ser AUC lle ACC Thr AUA ACA AGA AUG Met ACG GCU GCC GUU GAU] GGU GUC Val GAC Asp GGC Ala Gly GUA GCA GAA GGA Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a FRAMESHIFT SILENT NONSENSE MISSENSE Third letter First letteran opening reading frame is defines by _ 1 absence of highly repetitive sequence 2homology with other species 3a start and stop codon 4placement on a genome map
- Table 1 shows a list of restriction endonucleases with their recognition sequence and the sites of cleavage indicated by arrows. Table 1 Enzyme name Recognition sequence and position of cut 5'GIAATTC3 5'G!GATCC3' 5'GIGTACC3 5'GCIGGCCGC3' 5'IGATC3' 5'GGTACIC3' 5'ALGATCT3 EcoRI ВатHI Аcс651 Notl Sau3A Kpnl BglII (i) Which restriction enzyme(s) produce blunt ends? (ii) Are there any pair of neoschizomers in the list? Explain. (iii) Are there any pair of isocaudomers in the list? Explain.15/doc.aspx?sourcedoc={dac0ebeb-b019-4578-911c-98.. Search (Option + Q) Review View Help Table O Editing er Av A =Hello, I would really appiarte help appreciate help. This is a blank question so I am unsure why it was rejected immeditely the first time. Thank you in advance. Identify the type of mutation and how it would affect the protein made (amino acid) if the following changes occurred in the DNA antisense strand First codon change from TAC to TAT. Third codon change from ACG to ACA. Ninth nucleotide changes from G to T. Nucleotide with adenine (A) base inserted between 3rd and 4th nucleotide. Types of Mutation Changes in the Amino Acid 1. 2. 3. 4.SEE MORE QUESTIONS