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- The results of a tensile test are shown in Table 1.5.2. The test was performed on a metal specimen with a circular cross section. The diameter was 3 8 inch and the gage length (The length over which the elongation is measured) was 2 inches. a. Use the data in Table 1.5.2 to produce a table of stress and strain values. b. Plot the stress-strain data and draw a best-fit curve. c. Compute the, modulus of elasticity from the initial slope of the curve. d. Estimate the yield stress.A tensile test was performed on a metal specimen with a diameter of 1 2 inch and a gage length (the length over which the elongation is measured) of 4 inches. The dam were plotted on a load-displacement graph. P vs. L. A best-fit line was drawn through the points, and the slope of the straight-line portion was calculated to be P/L =1392 kips/in. What is the modulus of elasticity?The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.
- A tensile test was performed on a metal specimen having a circular cross section with a diameter of 1 2 inch. The gage length (the length over which the elongation is measured) is 2 inches. For a load 13.5 kips, the elongation was 4.6610 3 inches. If the load is assumed to be within the linear elastic rang: of the material, determine the modulus of elasticity.A steel specimen is tested in tension. The specimen is 25 mm wide by 5 mm thick in the test region. By monitoring the load dial of the testing machine, it was found that the specimen yielded at a load of 55 kN and fractured at 78 kN.a. Determine the tensile stresses at yield and at fracture.b. Estimate how much elongation would occur at 60% of the yield stress in a 50-mm gauge length.3. A steel specimen is tested in tension. The specimen is 1.0 in. wide by 0.25 in. thick in the test region. By monitoring the load dial of the testing machine, it was found that the specimen yielded at a load of 12.5 kips and fractured at 17.5 kips. а. Determine the tensile stresses at yield and at fracture. b. Estimate how much increase in length would occur at 60% of the yield stress in a 2-in. gauge length
- A load applied to a machine component results in the state of plane stress ?x=80 MPa, ?y=100 MPa, ?xy=60 MPa. The component is made of a brittle high-strength steel that follows the maximum normal stress criterion with ?u=200 MPa. If increasing the load increases each stress component proportionally, determine the percentage increase that can be applied before the component fails.A steel specimen is tested in tension. The specimen is 25 mm wide by 12.5 mm thick in the test region. By monitoring the load dial of the testing machine, it was found that the specimen yielded at a load of 160 kN and fractured at 214 kN. a. Determine the tensile stress at yield and at fracture. b. If the original gauge length was 100 mm, estimate the gauge length when the specimen is stressed to 1/2 the yield stress.(b) (i) A tensile test specimen made from 0.4% C steel has a circular cross section of diameter d mm and a gauge length of 25 mm. When a load of 4500 N is applied during the test, the gauge length of the specimen extends to 25.02 mm. If the Young's Modulus of the steel is 199 GPa, calculate the diameter of the tensile test specimen used. 4
- A steel specimen is tested in tension. The specimen is 1 in. wide by 0.5 in. thick in the test region. By monitoring the load dial of the testing machine, it was found that the specimen yielded at a load of 36 kips and fractured at 48 kips.a. Determine the tensile stress at yield and at fracture.b. If the original gauge length was 4 in., estimate the gauge length when the specimen is stressed to 1/2 the yield stress.A steel specimen is tested in tension. The specimen is 1.0 in. wide by 0.25 in. thick in the test region. By monitoring the load dial of the testing machine, it was found that the specimen yielded at a load of 12.5 kips and fractured at 17.5 kips. a. Determine the tensile stresses at yield and at fracture. b. Estimate how much increase in length would occur at 60% of the yield stress in a 2-in. gauge length. Step-by-step solution: Step 1 of 4 Given that: Width of the specimen, b = 1 in Thickness of the specimen, t = 0.25 in Yield load on the specimen, Py = 12.5 kips Fracture load on the specimen, Pf = 17.5 kips Gauge length, L = 2 in Percentage of yield stress = 60%A steel specimen is tested in tension. The specimen is 1.0 in. wide by 0.25 in. thick in the test region. By monitoring the load dial of the testing machine, it was found that the specimen yielded at a load of 12.5 kips and fractured at 17.5 kips.a. Determine the tensile stresses at yield and at fracture.b. Estimate how much increase in length would occur at 60% of the yield stress in a 2-in. gauge length.
