C++ A robot is initially located at position (0; 0) in a grid [?5; 5] [?5; 5]. The robot can move randomly in any of the directions: up, down, left, right. The robot can only move one step at a time. For each move, print the direction of the move and the current position of the robot. If the robot makes a circle, which means it moves back to the original place, print "Back to the origin!" to the console and stop the program. If it reaches the boundary of the grid, print \Hit the boundary!" to the console and stop the program. A successful run of your code may look like:Down (0,-1)Down (0,-2)Up (0,-1)Left (-1,-1)Left (-2,-1)Up (-2,0)Left (-3,0)Left (-4,0)Left (-5,0)Hit the boundary! or Left (-1,0)Down (-1,-1)Right (0,-1)Up (0,0)Back to the origin! About: This program is to give you practice using the control ow, the random number generator, and output formatting. You may use <iomanip> to format your output. You may NOT use #include "stdafx.h".
C++
A robot is initially located at position (0; 0) in a grid [?5; 5] [?5; 5]. The robot can move randomly in any of the directions: up, down, left, right. The robot can only move one step at a time. For each move, print the direction of the move and the current position of the robot. If the robot makes a circle, which means it moves back to the original place, print "Back to the origin!" to the console and stop the
A successful run of your code may look like:
Down (0,-1)
Down (0,-2)
Up (0,-1)
Left (-1,-1)
Left (-2,-1)
Up (-2,0)
Left (-3,0)
Left (-4,0)
Left (-5,0)
Hit the boundary!
or
Left (-1,0)
Down (-1,-1)
Right (0,-1)
Up (0,0)
Back to the origin!
About: This program is to give you practice using the control ow, the random number generator, and output formatting. You may use <iomanip> to format your output.
You may NOT use #include "stdafx.h".
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 1 images