Calculate free energy change at 298 K for the reaction below: 2 Pb (g)  +  N2 (g)  →  2 PbN (s) ΔG° = –180.8 kJ PPb  =  0.025 atm,  PN2  =  0.037 atm Group of answer choices -146.0 kJ +207.0 kJ -154.4 kJ -26.5 kJ -162.5 kJ

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
Section18.5: Entropy Changes And Spontaneity
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Calculate free energy change at 298 K for the reaction below:

2 Pb (g)  +  N2 (g)  →  2 PbN (s)

ΔG° = –180.8 kJ

PPb  =  0.025 atm,  PN2  =  0.037 atm

Group of answer choices
-146.0 kJ
+207.0 kJ
-154.4 kJ
-26.5 kJ
-162.5 kJ
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