Calculation: For center Loading: MR = 3PL / 2bd? Where: MR- modulus of rupture, psi (MPa) P= maximum load applied as indicated by testing machine, in Ib (N) L= span length, in inches (mm) b= average width of specimen in inches (mm) d= average depth of specimen, at the fracture, in inches (mm) Note: The weight of the beam is not included in the above calculation. Tabulated Data and Result Sample No. L (mm) В (mm) D (mm) P (N) MR (MPa) 1 450 150 150 23000 450 150 150 21000 3 450 150 150 19000

Calculation: For center Loading: MR = 3PL / 2bd? Where: MR- modulus of rupture, psi (MPa) P= maximum load applied as indicated by testing machine, in Ib (N) L= span length, in inches (mm) b= average width of specimen in inches (mm) d= average depth of specimen, at the fracture, in inches (mm) Note: The weight of the beam is not included in the above calculation. Tabulated Data and Result Sample No. L (mm) В (mm) D (mm) P (N) MR (MPa) 1 450 150 150 23000 450 150 150 21000 3 450 150 150 19000

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter1: Introduction

Section: Chapter Questions

Problem 1.5.3P: A tensile test was performed on a metal specimen having a circular cross section with a diameter 0....

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The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.
A tensile test was performed on a metal specimen having a circular cross section with a diameter 0. 510 inch. For each increment of load applied, the strain was directly determined by means of a strain gage attached to the specimen. The results are, shown in Table: 1.5.1. a. Prepare a table of stress and strain. b. Plot these data to obtain a stress-strain curve. Do not connect the data points; draw a best-fit straight line through them. c. Determine the modulus of elasticity as the slope of the best-fit line.
A tensile test was performed on a metal specimen with a diameter of 1⁄2 inch and a gage length (the length over which the elongation is measured) of 4 inches. The data were plotted on a load-displacement graph, P vs. ∆L. A best-fit line was drawn through the points, and the slope of the straight-line portion was calculated to be P y∆L 5 1392 kips yin. What is the modulus of elasticity?
1.5-7 The data shown in the table were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2 in.² in area and a gage length (the length over which the elongation is measured) of 2.000 inches. d. Estimate the value of the proportional limit. e. Use the 0.2% offset method to determine the yield stress. Load (kips) 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 ܩܙ ܘ 5.5 6.0 6.5 Elongation × 10³ (in.) 0 0.160 0.352 0.706 1.012 1.434 1.712 1.986 2.286 2.612 2.938 3.274 3.632 3.976 Load (kips) 7.0 7.5 8.0 8.5 9.0 9.5 10.0 10.5 11.0 11.5 12.0 12.5 13 Elongation × 10³ (in.) 4.386 4.640 4.988 5.432 5.862 6.362 7.304 8.072 9.044 11.310 14.120 20.044 29.106
A hot rolled steel tension test sample has a diameter of 6 mm and the original gage length of 30 mm. In a test to fracture, the stress and strain data below were obtained. Determine Generic Strain Value, %0.2 offset strain, and Calculated stress at %0.2 offset. Original diameter - 6mm Original Length - 30 mm Fracture diameter - 4.54 mm
1 a. During a tensile test on a specimen the following results were obtained: Load (kN) 15 |30 40 50 55 60 Extension 1.03 2.00 2.73 3.42 3.80 4.10 (mm) Diameter of gauge length =19mm Gauge length = 150mm Load at fracture = 80kN Diameter at fracture =16.5mm Gauge length at fracture = 170mm Ultimate load = 120kN Plot the load/extension graph to an appropriate scale. Hence determine the Modulus of elasticity ii. Percentage elongation iii. Percentage reduction in area iv. The nominal stress at fracture v. The actual stress at fracture vi. Ultimate tensile strength i.
The (G-E) diagram obtained in the tensile test performed on a metal sample with a diameter of 16 mm is as follows. The loads at points A, B and C and the elongation measured on l. 16 cm gauge length were determined as follows: B A B C Load (kgf) 4800 8400 7200 Elongation (mm) 0.192 28.8 38.4 c) Calculate the fracture work and the maximum elastic energy the metal rod can store. d) Find the cross-sectional area of a 6 m long rod made of this metal such that it can carry 12 tons of load with 2 times the safety of yield strength. How long does the rod extend under this load?
Q1- The followving data was obtained tensile test on a specimen of 6 mm diameter and gauge length Lo=30 mm: 92.7 160.4 155 4.06 142 124.7 5.1 5.84 0| 38 load(KN) elongation(mm) 0 0.02 Using the graphic paper supplied, Plot engineering stress-strain curves, then determine the 76.2 107 149 0.12 0.25 0.50 2.03 3.55 (gy sy), (gu, cu), (of, sf), modulus of elasticity, then detected in the draw ((strain hardening (n)), (Necking), (uniform plastic region and non-uniform plastic region) and (elastic & plastic) region))?
4. Sample of steel bar has 50 mm length after performing tension test the final length was 50.2 mm, strain of this sample equal to * 0.04% 0.4% 4% 0.004% O All above are not correct
a. Assuming the computer and the printer are turned on, what will be the next step to do when trying to perform a test?b. What part of the UTM will you use to remove the tensile test specimen from the grips?c. In what direction does the lower crosshead move during a tensile test?d. In what direction does the lower crosshead move during a compression test?e. In what direction does the lower crosshead move during a bending test?
A tension test was performed on a specimen having an original diameter of 12.76 mm and a gage length of 56.97 mm.The data are listed in the table. Plot the stress-strain diagram, and determine approximately the modulus of elasticity, the ultimate stress, and the fracture stress. Use a scale of 20 mm = 50 MPa and 20 mm = 0.05 mm/mm. Redraw the linear-elastic region, using the same stress scale but a strain scale of 20 mm = 0.001 mm/mm. Also, determine the 0.2% yield stress.
The following observations were made during a tensile test on a mild steel specimen 40 mm in diameter and 200 mm long. Elongation is with 40 kN load (with in limit of proportionality) 8=0.0304mm, yield load = 161 kN, Maximum load = 242 kN Length of specimen at fracture = 249mm Find: 1) Young's Modulus of elasticity ; E 2) Yield point stress Ultimate stress 3) 4) Percentage elongation