Consider the fructose-1,6-bisphosphatase reaction. Calculate the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 21.7 and the temperature is 37.0°C? AG' for the reaction is -16.7 kJ/mol. AG = kJ/mol
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- G6P(ag) F6P(aq) AG°=+1.7kJ/mol at 25 °C Consider the reaction: Estimate the fraction of F6P (Fructose 6 Phosphate) in equilibrium with G6P (Glucose 6 Phosphate) at 25 °C, where the fraction is defined as [F6P]/([F6P]+[G6P]). Show ALL your work.The standard free energy change for the reaction catalyzed by phosphoglucomutase is -7.1 kJ/mol. Calculate the equilibrium constant for the reaction. Calculate AG at 37°C when the concentration of glucose-1-phosphate is 1-mM and the concentration of glucose-6-phosphate is 25-mM. Is the reaction spontaneous under these conditions? HOCH, -20;POCH, H H H H H H ОН Н НО ОН Н H НО ОН H ОН H. ОН Glucose-l-phosphate Glucose-6-phosphateConsider the following phosphoryl group transfer reaction which is the first step in glucose catabolism by glycolysis: Glucose + ATP + Glucose 6-phosphate + ADP The AG for the reaction is -16.7 kJ/mol. (R= 8.314 J/(K. mol) (a) Calculate Keq for the reaction at 25°C (b) What is the ratio of [Glucose 6-phosphate] to [Glucose] if the ratio of [ADP] to [ATP] is 10?
- Glucose 1-phosphate is converted into fructose 6-phosphate in two successive reactions. Reaction 1: Glucose 1-phosphate → glucose 6-phosphate AG'° = -7.3 kJ/mol Reaction 2: Glucose 6-phosphate → fructose 6-phosphate AGʻ° = +1.7 kJ/mol Using the values given, calculate the standard free-energy change, AGʻ°, ,for the sum of the two reactions: sum > Sum: Glucose 1-phosphate → fructose 6-phosphate AG'°, kJ/mol sum Calculate the equilibrium constant, K', eq > for the sum of the two reactions. K'e eq IIInside cells, the AG value for the hydrolysis of ATP to ADP + Pi is approximately -50 kJ/mol (-12 kcal/mol). Calculate the approximate ratio of [ATP] to [ADP][Pi ] in cells at 37°C. AG = AG + RT InKe R= 8.315 x 10³ kJ mol deg T= 298 K Table 15.1 Standard free energies of hydrolysis of some phosphorylated compounds Compound kJ mol- kcal mol- Phosphoenolpyruvate 1,3-Bisphosphoglycerate Creatine phosphate ATP (to ADP) -61.9 -14.8 -49.4 -11.8 -43.1 -10.3 -30.5 - 7.3 - 5.0 Glucose 1-phosphate Pyrophosphate Glucose 6-phosphate -20.9 -19.3 -4.6 -13.8 3.3 Glycerol 3-phosphate - 9.2 2.2 biochemistryThe standard free energy change for this reaction in the direction written is +23.8 kuimol. The tabie shows the concentrations of the three intermediates in the hepatocyte of a mammal. Intermediate Concentration (M) Fructose 1.0-bisphosphate 0.000028 Gyoeraldehyde 3phosphate 0.0000068 Ditydroxyacetone phosphate 0.000032 At body temperature (37 "C). what is the actual free energy change for the reaction (in kimol) ?
- What terms would best describe the above coupled reaction? (If the DGo for ATP hydrolysis into ADP + inorganic phosphate is -7.3 kcal/mole, and the DGo for maltose synthesis from glucose + glucose is +3.7 kcal/mole, calculate the standard free energy change for the combined reaction of ATP + glucose + glucose g ADP + maltose + inorganic phosphate.) it is non-spontaneous and endothermic (because the overall DGo is negative) it is spontaneous and exothermic (because the overall DGo is negative) it is non-spontaneous and endothermic (because the overall DGo is positive) it is spontaneous and exothermic (because the overall DGo is positive) it is non-spontaneous and exothermic (because the overall DGo is negative)Assume that in a certain cell, the ratio of products/reactants or Keg = 809.5 (Keq is dimensionless) for the reaction Glucose + 2ATP > Glucose-1,6-diP + 2ADP, at a particular instant, the concentrations of each compound were Glucose =2.4M, ATP =11.1M, ADP -12.8M and G-6-P -28.4M. Calculate the difference (dimensionless) between Keq and the ratio of products/ractants at this instance, in this cell, to five decimal placesConsider the following reaction: Glucose 6-phosphate + Glucose 1-phosphate After reactant and product were mixed and allowed to reach equilibrium at 25C, the concentration of each compound was measured: (Glucose 1-phosphate] - 0.002 M [Glucose 6-phosphate 0.05 mM Calculate the Keg and the AG knot prime (e.g. standard free energy change). O Keg- 40: AG knot prime 9.14 kJ/mol O Ken- 19: AG knot prime -7.3 kJ/mol O Keg" 0.04: AG knot prime-7.98 kJ/mol Kea 4: AG knot prime -914 kJ/mol O Keg 40: AG knot prime - 9.14 k/mol
- The turnover number of the enzyme fumarase that catalyzes the reaction, Fumarate + H20 ===→ L-malate, is 2.5 x 103 S - l and Km = 4.0 X 10- 6 mol/L. Calculate the rate of conversion of fumarate to L-malate if the fumarase concentration is 1.0 x 1 0 - 6 mol/L and the fumarate concentration is 2.04 x 10- 4 mol/L.The enzyme aldolase catalyzes the reaction shown in the glycolytic pathway: Fructose 1,6-bisphosphate dihydroxyacetone phosphate + glyceraldehyde 3-phosphate The AG" for the reaction is +23.8 kJ mol¯¹ (+5.7 kcal mol−¹), whereas the AG in the cell is −1.3 kJ mol¯¹ (−0.3 kcal mol¯¹). Calculate the ratio of products to reactants under standard (equilibrium) conditions at 37°C. [products] [reactants] 7 x10-5 [products] [reactants] Incorrect Aldolase ===== Calculate the ratio of products to reactants under intracellular conditions at 37°C. 4 ×10-5 Incorrect Complete the statement using your results. under standard conditions under intracellular conditions A reaction that is endergonic under standard conditions can be converted into an exergonic reaction by maintaining the ratio of products to reactants below the equilibrium value.The hydrolysis of ATP has an enthalpy and entropy of -24.3 kJ/mol and +21.6 J.K-1.mol-1, respectively, at 37 o C. What is the free energy change for the hydrolysis of 5 mols of ATP? Explain what contributes to the negative enthalpy change and positive entropy change in this reaction. What physical characteristics of the reaction would change if an ATP hydrolase enzyme is added to the solution?