Draw the major elimination and substitution products formed in this reaction. Use a dash or wedge bond to indicate the stereochemistry of substituents on asymmetric centers, where applicable. Ignore any inorganic byproducts.
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- ew fopics] Draw the major organic product of the reaction shown below. H2SO4 HO, • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. C opy aste [F ChemDoodle2) Predict the major product for each reaction. Indicate correct stereochemistry. a. b. H3C H3C HO ||||| HO ||||| CH3 ||||| Br H Br CH3 H NaOH NaOH thrive qode-tums ng uboiqyDetermine the mechanism of nucleophilic substitution of each reaction and draw the products, including stereochemistr CH₂CH3 CI Br + CN d. + CH3COOH a. acetone + -OCH3 e. DMF f. b. C. ||||| a ||||| Br H Br CH2CH2CH3 + CH3OH DMSO H CH3 CI Br + OCH₂CH3 + CH3CH₂OH
- Draw the organic product of the following reaction. CH3 m-CICgH,CO;H • Use the wedge/hash bond tools to indicate stereochemistry where it exists. • If the reaction produces a racemic mixture, just draw one stereoisomer. • If more than one product is possible, only draw the major product. opy asteDraw the alkene that would react with the reagent given to account for the product formed. ? + H₂O ● You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. 8 H₂SO4 // CH3 CH3CHCCH3 OH CH3 ? [F Previous Email InstructPlastic photochromic sunglasses are based on the following reversible rearrangement of a dye inside the lenses that occurs when the lenses are exposed to sunlight. The original dye absorbs UV light but not visible light and is thus colorless, while the rearrangement product absorbs visible light and is thus darkened. (a) Show the mechanism of the rearrangement. (b) Why does the rearrangement product absorb at a longer wavelength (visible light) than the original dye (UV)?
- Addition proceeds preferentially through the most stable carbocation intermediate. At high temperature, 10-20 °C or higher, products equilibrate; and the most stable product predominates (thermodynamic control). At low temperature, 0 °C or lower, there is kinetic control of reaction products. CI CI b Write a mechanism for the first step of this reaction using curved arrows to show electron reorganization. Consult the arrow-pushing instructions for the convention on regiospecific electrophilic attack on a double bond. Arrow-pushing Instructions n →XT H-CI:Zaitsev's Rule refers to: which alkene is favored in a product mixture O how resonance contributors stabilize cations/anions/radicals O the stereochemistry of reaction intermediates/transition states O the stability of carbocation intermediatesUse the References to access important values if needed for this question. Draw the structure of the product that is expected when the following compound is treated with concentrated H2SO4. он H2S04 ? heat CH3 You do not have to consider stereochemistry. • In cases where there is more than one answer, just draw one. ited opy Bste [F CH4 ChemDoodle Retry Entire Group 3 more group attempts remaining Submit Answer Previous Next Email Instructor Save and Exit Cengage Learning | Cengage Technical Support
- Draw the major product of this reaction. Include stereochemistry if applicable. Use a dash or wedge bond to indicate the stereochemistry of substituents on asymmetric centers, where applicable. Ignore byproducts. Br CH3CO₂H Select to DrawComplete the following oxidation reaction by drawing a structural formula for the product. CH3CH₂CHC-H H₂CHC-H CH₂CH3 → ? • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. MAVIL CH4 Sn [F ? ChemDoodleⓇ PreviousConsidering stereochemistry, draw the resulting E2 elimination product when H. is removed. H a Ho III.... H H₂ I jº ·*||||| H X Ś my è