Given a round column in compression. It is centrally loaded. What is the radius of gyration for buckling given the following information? • Diameter of column, d= 0.224 m Length of column, L = 1.1 m • Load, P = 441 State the radius of gyration in meters to 4 (four) decimal places.
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- Answer the image below. Also draw the FREE BODY DIAGRAM. Answer should be: PSTEEL = 15,000 lbs PBRONZE = 9,000 lbs PALUM = 3,000 lbs δTOTAL = 0.0224 inch < 0.08 inchIf the flexural rigidity of the column is doubled, and length of the simply supported column is halved, then the strength of the column is increased to how many timesExamine the rod below. It is fixed into a wall at the left hand end. From the wall to point B is 200mm. BC is 200mm long and CD is 200mm long. (Centreline to centreline distances). Point A lies on the positive Y-axis on a cross section halfway along BC. Three forces are applied at D. P=221.6, your individual load, is parallel to the z-axis. 400N is parallel to the y-axis and 200N is parallel to the x axis. The rod is a tube with an 80mm outer diameter and a wall thickness of 5mm. What is the net sigma (s) and the net tau (t) at Point A? Show all your working. Make sure you clearly indicate the direction/sign of each stress you calculate.
- Consider the bracket shown in Fig-3. If: F1 = 10 lb @ -90° • a - 2 ft • b = 4 ft • c= 1 ft then, what is the type of the internal force within member 'BD'? compressive tensileCS CamScanner ile tarandı M=500 kg Find the fpres in each 'member? (Draw free booly liograns)Required information Two cylindrical rods, one of steel and the other of brass, are joined at C and restrained by rigid supports at A and E. Given: P₁ = 65 kN and P2 = 40 kN. Take Es = 200 GPa and Eb = 105 GPa. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. -180- Dimensions in mum Steel B 120- P₁ 40-mm diam. 100 100 DI C Brass 30-mm diam. Determine the reactions at A and E. The reaction at A is The reaction at Eis P2 E KN (Click to select) ✓ KN (Click to select)
- QUESTION 3 Rod ABCD is connected to Rod DEFG at D and is also connected by rod BF by pins. A pulley is connected to end G with radius of 0.1m. The rope is hanging around the pulley to hold a mass M1 of 100 kg. The other end of the rope is connected to point C at rod ABCD. Another rod EH is also connected to point E by pin to hold the structure. Point A and point H are also by pin connections to the wall. Points A, B, C, D, H are vertically in-line. Find reactions at pins H and A. (AB = 0.2m, BC = 0.2m, CD = 0.1m, DE = 0.3m, EF = 0.15m, FG = 0.15m, EH = 0.5m, the mass of the rods are neglected). 0.2m B 0.2m Radius Pulley G- 0.Im 0. Im 0.15 D 0.3m E 0.15 0.5m MI- 100 kg HIn the given figure, support A is a roller and support B is a pin support. If P=15 kips, calculate the 1) vertical reaction at A, 2) vertical reaction at B, 3) horizontal reaction at B P 6 kips 6 kips В 6 ft – 3 ft 2 ft ' 2 ft2. Figure (a) shows the cross section of a column that uses a structural shape known as W8 x 67 (wide-flange beam, nominally 8 in. deep, weighing 67 Ib/ft). The American Institute of Steel Construction Structural Steel Handbook lists the following cross-sectional properties: A=19.7 in², Ix =272 in“, and ly =88.6 in4. Figure (b) shows the cross-sectional dimensions for the structural steel section known as C10 x 20 (channel with a nominal depth of 10 in., weighing 20 Ib/ft). The American Institute of Steel Construction Structural Steel Handbook lists the following properties for the cross section: A=5.88 in?, Ix =78.9 inª, and ly =2.81 in*. If a W8 x 67 section is joined to a C10 × 20 section to form a structural member that has the cross section shown in Figure (c), a. Locate the centroid of the built-up section in the Figure (c). b. Calculate the centroidal moments of inertia, Ix and ly for this cross section. 事士 0.606 in. 0.933 in. y Web in. --0.575 in. 10 in. - Flange -- 0.379in.…
- Calculate the reaction forces on the bearing near the pulley and bearing at the far end of the shaft. Include a free body diagram and coordinates. Given the shaft length is 1 meter= Mass=40Kg Static load = 8600N Dynamic (running load) = 8400N Some hints:1. This solution will require you to draw known forces and find unknown reactions in 2perpendicular planes and then add the horizontal and vertical reaction forces asvectors to find the reaction force (hypotenuse).2. Bearings are usually mounted as near as possible to the ends of the shaft withoutfouling the other machine elements. The bearing at the far shaft end can be mountedat the 1 meter point. The bearing at the pulley end should allow clearance to assemblethe pulley.3. Bearing reaction forces are typically simplified as a single point load through thebearing centre.A long, slender structural aluminum [E = 69 GPa] flanged shape is used as a l = 9.2-m-long column. The column is supported in the x direction at base A and pinned at ends A and C against translation in the y and z directions. Lateral support is provided to the column so that deflection in the x-z plane is restrained at mid-height B; however, the column is free to deflect in the x-y plane at B. Assume that b; = 102 mm, d = 122 mm, t; = 8 mm, and tw = 6 mm. Determine the maximum compressive load P the column can support if a factor of safety of 2.9 is required. In your analysis, consider the possibility that buckling could occur about either the strong axis (i.e., the z axis) or the weak axis (i.e., the y axis) of the aluminum column. bf C L Lateral B bracing L 2 AShown below is a picture of a Go-Kart which weighs 300# (with the rider), distributed with 60% of the weight on the rear axle and 40% on the front axle. The weight from the GoKart is applied to the rear axle at two bearings, as shown by the arrows below. The axle is fabricated from steel (E=30x106 psi) and has a 1.25" outer diameter with a .125" wall thickness. a. Draw the shear and moment diagrams for the axle. You may assume that the axle is simply supported. b. Determine the location (i.e., location on the axle) and magnitude of the maximum bending stress. Draw a cross-section of the axle, indicate the neutral axis, and mark the position of the maximum tensile stress on the cross-section. c. Using superposition, determine the deflection of the axle half way between the two bearings (i.e., 14" from one bearing, as shown). 10" 28" 10" 14" Bearing Bearing