If a 3- Ø, Y-connected system has a line-to-line voltage of 1103Sin(377t) V, then the line-to-neutral (RMS) voltage would be:
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If a 3- Ø, Y-connected system has a line-to-line voltage of 1103Sin(377t) V, then the line-to-neutral (RMS) voltage would be: |
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- Q1. For the system shown in Figure Q1, draw an impedance diagram in per unit, by choosing 100 kVA to be the base kVA and 2400 V as the base voltage for the generators. 10 KVA 2400 V G₁ Z=j0.2pu 20 KVA 2400 V Z=j0.2pu G₂ T₁ Transmission Line Z= (50+j200) 40 KVA 2400/9600 V Z=j0.1pu Fig Q1 T₂ 80 KVA 10/5 kV Z=j0.1pu M 25 KVA 4 kVProblem 1 - Series en Parallel AC networks [19] Look at the circuit in Figure 1 and determine the following: (a) Total Admittance. (b) Total Impedance. (c) Total Current (l:). (d) Current (I1) through impedance Z2. (e) Current (12) through impedance Z3. (f) Current (I3) through impedance Z4. (g) Is this an inductive or capacitive circuit? A. B Zs 220V;50HZ Figure 1 (h) Voltage across Z1. (i) Voltage across A and B. G) Voltage across Zs. Z1 = 3 + j5 ohm Z2 = 10 + jo ohm Z3 = 5 + j15 ohm Z4 = 10 – j30 ohm Zs = 20 – j30 ohm Admittance and Impedance in rectangular notation. All currents and voltage in polar notation. Take voltage as reference.The three-phase power and line-line ratings of the electric power system shown in Figure-1 are given below: G,:(first and Last digit of SAP ID) MVA T:(G,rating-10) MVA T(G,rating-10) MVA M:((T,rating-10)) MVA 30 kV X=10% 30/300 kV X=11% 300/30 kV X=11% 25 kV X=9% Line: 30 kV Z=First two digits of SAP ID + j (2× first two digits of SAP ID) T1 T2 Vm Line 2 G M Figure 1 • Apply the knowledge of per unit system on above network and draw an impedance diagram showing all impedances in per unit when S, = 100 MVA and V, = 30 kV
- The three-phase power and line-line ratings of the electric power system shown in Figure-1 are given below: G1:82 MVA 30 kV X=10% T1:72MVA 30/300 kV X=11% T2:72MVA 300/30 kV X=11% M:62MVA 25 kV X=9% 300 kV Z= 89+j179 Apply the knowledge of per unit system on above network and draw an impedance diagram showing all impedances in per unit when Sb =100MVA and Vb = 30 kvDraw an impedance diagram for the electric power system shown in Figure 3.32 showing all impedances in per unit on a 100-MVA base. Choose 20-kV as the voltage base for generator. The three-phase power and line-line ratings are given below. G1; 90 MVA 20 kV T1: 80 MVA T2: 80 MVA 90 MVA G2: Line: Load: G₁ T₁ 38 1 20/200 kV 200/20 kV 18 kV 200 kV 200 kV Load FIGURE 3.32 One-line diagram for Problem 3.13 Line X = 9% X = 16% X = 20% X = 9% X = 120 Ω S = 48 MW + j64 Mvar T₂ 38 2 G₂Consider the three single-phase two-winding transformers shown in Figure 3.37. The high-voltage windings are connected in Y. (a) For the low-voltage side, connect the windings in , place the polarity marks, and label the terminals a, b, and c in accordance with the American standard. (b) Relabel the terminals a, b, and c such that VAN is 90 out of phase with Va for positive sequence.
- Consider a single-phase electric system shown in Figure 3.33. Transformers are rated as follows: XY15MVA,13.8/138kV, leakage reactance 10 YZ15MVA,138/69kV, leakage reactance 8 With the base in circuit Y chosen as 15MVA,138kV determine the per-unit impedance of the 500 resistive load in circuit Z, referred to circuits Z, Y, and X. Neglecting magnetizing currents, transformer resistances, and line impedances, draw the impedance diagram in per unit.Consider two interconnected voltage sources connected by a line of impedance Z=jX, as shown in Figure 2.27. (a) Obtain expressions for P12 and Q12. (b) Determine the maximum power transfer and the condition for it toWith generator conyention, where the current leaves the positive terminal of the circuit element, if P is positive then positive real power is delivered. (a) False (b) True
- Three single-phase transformers, each rated 10MVA,66.4/12.5kV,60Hz, with an equivalent series reactance of 0.1 per unit divided equally between primary and secondary, are connected in a three-phase bank. The high-voltage windings are V-connected and their terminals are directly connected to a 115-kV three-phase bus. The secondary terminals are all shorted together. Find the currents entering the high-voltage terminals and leaving the low-voltage terminals if the low-voltage windings are (a) Y-connected and (b) - connected.The rating of generator is expressed in terms of kVA Select one: True FalseA- A 3-ph, double circuit O.H.T.L, 320 kV, 340 km, 50 Hz has a configuration as shown in the figure below where each phase in the double circuit has a double bundle with a spacing of d cm between the two conductors in the bundle where d is the last two digits (from right) of your registration number (i.e for the student that has a registration mumber 202112396, d= 96). Each conductor in the bundle has a diameter of 0.135 ft and a geometric mean radius (Ds = 1.6 cm). Calculate: 1- Inductance per phase per km. 2- Total inductive reactance. 3- This T.L. is required to supply 240 MVA at 0.86 lag P.f. at 320 kV, assuming that this load is divided equally between these two circuits, find the voltage drop across this T.L (ignore capacitive effect in the calculation). 4- What may happen if we replace the location of a' and c' bundles. Discuss your answer. 5- Suggest a way to ređuce the value of the inductance. Verify your suggestion. -8 m 3m 3m 8 m 11 m