Instructions:(1) You may use your class textbooks, handouts, and notes as you work on this problem by yourself. Use ofany other resources should not be necessary, but use of any such resources without citation is an honorcode violation.(2) Please write your final answer neatly on your own paper and staple them to this page (or this page if itfits). I do not need any of your scrap work, though you may explain or annotate your answer if desired.V. Show a synthesis of the following mostly (Z)-alkene molecule starting from benzene (C6H6), any otheralkynes (R-C=C-R) or alcohols (R-OH) of four (4) carbons or fewer, and any other necessary reagentsand solvents that do not become part of the product. (20 pts)[reaction mechanisms are NOT required]HCH3C=COH-C-CH2CH2CH2CH2CH2CH3CH3O

The question asks for the synthesis of a specific molecule, which is a (Z)-alkene with a methoxy…

Answered: Instructions: (1) You may use your…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Typed solutions only please. No handwritten answers.
Could you please show what you get for these questions so I can compare my answers to yours. I would appreciate it!
This question must be finished in your tutorial and this Word document containing your answers submitted within 120 minutes of the end of your tutorial. You will receive feedback from your tutor in a few weeks. The answers will be available where you obtained this. There are no marks for this exercise but it counts towards participation. Draw your answers on a separate piece of paper, take an image and insert the image(s) into this Word document at the end. (a) Re-draw the following molecule with the CH2CH2CH3 group on the ladder 1. H H2 ОН H3C H2 CH2 H;C (b) Is the molecule in part (a) the same molecule or the enantiomer of the following. Circle your answer Explain your answer CH3 SAME MOLECULE H2C H2 -CH3 ENANTIOMER H2 ОН 3. What is the configuration (R or S) of the chiral carbon in this molecule. Label the ranking of each of the groups on the chiral carbon from 1 (highest) to 4 (lowest) Draw the representation of this molecule with the lowest ranked group (4) on the ladder and…
if you could please help! i submitted this previously and was told that it looks incomplete. the questions are complete and there is no additional information to upload with the questions. again there are 6 questions and i have done a majority of them. i really just need help with question 2 and 3, however, if you could look at my answers for the questions i did and tell me if they are correct i will gladly rate you! thank you so much. I apologize if it is small, i made the font smaller to fit everything on one picture
Please help me how to solve this problem in detail so i can understand it. Thank you very much.
So I went throught the material to re learn this question we had in class but I still don't get it. Maybe I don't understand my professors style of teaching as much. Can someone help me answer these questions and undertand them. Thank you
student found a bottle of unknown origin in the basement of an "CAUTION—contains С₁H₁O.” No other A old house. The bottle was labelled information was given, but inside the bottle were some white crystals. The student took the bottle to a chemistry laboratory, where she analyzed the crystals with the help of the laboratory staff. C₁2H₁6O reacted with Br₂ in CCl4 adding one mole of Br, and forming C₁₂H₁OB2₂. When a sample of C₁₂H₂O was reacted with O3 followed by Zn/H₂O, two different samples, J and K, were obtained. Compound J had a molecular formula of C.HgO₂, and its NMR is shown below. Compound K had a molecular formula of C₂H₂O, and it could be oxidized to compound L, with a molecular formula of C₂H₂O₂. The IR spectrum of L showed a very wide, strong band centred around 3000 cm*¹. The NMR spectrum of L showed only two different absorptions: a doublet (6H) at 0.9 ppm and a septet (1H) at 3.6 ppm. There was also a singlet (1H) off the scale at 11.8 ppm. students, deduce possible…
Can someone answer nos. 5 to 10? Thank you very much! If it's not too much, provide an explanation for each number. Thanks!
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This must be typed/digitally illustrated. It CANNOT be hand-drawn. (it will be marked as wrong if it is hand-drawn) Please answer 2C (see 2a and 2b for information supporting it)
i hope that you can fill up all the blanks. thank you!

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