Present X O Timpurtate O O Boteal Ca polean cavation у 0- 0110 'X Next State A = (so = 000) = x²0 y B = ( 5₁ = 0011=X6Y (= (5₂=010) = XOY D = (53=011) - XOY E = (sy=100) = X őY F=(56=101)=X0Y 'O "Y C Sutfólie B C E F of the circuit outpout
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i want drow the circuit in for this state table:
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- Evaluate: rect (@) exp (-jw) O exp (-ja) at w = T. ANSWER: -1.Point2D +Point20 (x: double, y: double) +diatance (N! double, y: double) : double Retums the distance between this point and the specified point (x. y). +diatance (p: Point20) : double +getX() double +getY(): double tmidpoint (p: Point20) : Point20 tdistance (el: Point2D, p2: Point20) = Constructs a Point2D object with the specified x- and y-coordinates. Retums the distance between this point and the specified point p. Retums the x-coordinate from this point. Retums the y-coordinate from this point. Retums the midpoint between this point and point p. Retums the distance between pl and p2. double The class is partially implemented below. Implement distance (Point2D pl, Point2D p2) and midpoint (Point2D p) : class Point2D { private double x; private double y: public Point2D (double x, double y) { this.x - x; this.y - y: public double distance (double x, double y) { return distance (new Point2D (x, y)); public double distance (Point2D p) { return distance (this, p): public static double…4 4 +SV U1 OSCMCLKIN OSCICLKOUT MCLROVepTHV RBONT RB1 RB2 RBSPOM RADIAND RB4 RA1IANI RAZIANZVREF- RASANIVREF+ RAAITOCKI RASIANAISS RBS ROUPGC RB7PGD RCOT10SO/T1CKI RC1/T1OSICCP2 RCZICCP1 REDIANSIRD RETANW REZIANTICS START STOP RCaSCKISCL RC4SDVSDA RCSDO RCBTCK RC7IRKDT 7330 Ohm 19 ROOPSPO RDIPSP1 ROOPSP2 ROSPSP3 RD4PSP4 ROSPSPS ROSPSPS ROTPSP7 PICF77 In the application where TMRO is used as timer, "START" in RAO wwww When button is pressed, the display will count continuously with 100 ms intervals between 0-F, It will stop when the "STOP" button is pressed. TMRO interrupt every 0.0256 seconds set to create an interrupt. Every 20 cuts in the cutting function www The number "0" will flash once on the display. Write the required program for 16f877. www ww m (Freguency divider 1/128, oscillator 4 MHz)
- CashOrNothingOption = function(S, k, Time, r, q, sigma) {d1 = (log(S / k) + (r - q + sigma ^ 2 / 2) * Time) / (sigma * sqrt(Time))d2 = d1 - sigma * sqrt(Time)if(k>S){return (k * exp (-r * Time) * (-d2))}elseprint("zero")}n=z2lgfiz=g8ncfzk+l1chfib)u8zmgbn-j7kafnb(g2lcaiu-z6dccil)j4jhdih+b3jzcci(z1dmcgu)l2ukbnh=m4nkfnl-m8ihclg-n7znfdl-z5ggdna-u8kigzk=k5jddil=z4hkaku?a8dzdii-u6jhcjz)z9mlfuu=b4bgdbk-k7hibzn=g9jcabm(d1ngdmj)u4ucfdk=f5zfanm+l1hkgcg?n1ghbfa+n2nigku=l7cacdd(g7mkddu+m6agbzc)i3ncbcb=f6dkgbz?u2kjgkz+j7anfbl(l2anfgb-u1zcdfg(b9cnddf-l1luabn+a3bugch-l9hgcfb+h2bbdjc=d8lbdhj=z8augfb-j8bhdud=d1zmaii-d8ghduh-a4icahd)u9giblz=f1alfkd(i6hjabd(a2lfbmh)k4zkcuz+l2lifhu+f3zhfuh+g3iicdu(j5kgamh+d5icack+k8cdgui?c5hhcfu(m4jnblm+i6clgbz+h2hggff)f3kjbhc=i2uugzl)j7fdghu=b5fffla?u3hggcn?f4aaajj+b7ndbbc-m1dmdzz=u5ngdkz?l1jcdfz-k7mlacz)m1hnbma=a5kmbhu+k3gggbd(b6nnbud=m9zifbf?a2auaad=b3hcdmb?g5kjdia?j8diadn+m8hzbcg?a7dmblb?n7gkakz)m5mkbzc(l3hibad+c2ajglz?d5mjfih(l6hifag?j1lccnz)i8kjgkh+d5dmgmj(m3fffdu(l1nabdm=m9acdml=h6gfffu)h9kfdzd)g7ijcmb+a5hnffg=i3aiahd-a5jnguk=b8jkfhh=h7chcaj(c4bzdjb=g4uccun(u2ducbf)c6lafuk+h2jbahk+l9bcfdz?n4bjffl)j8njbhg)g4dkdad-i5nafbf(f5ugczj=m6kdgdk?a2jidla-a7ubgdh)l2icauj)z7zngbu)j1fdbla=z3fidd…TM M = (Q, E, I, 6, 90, 9a, qr), where Q = {90, 91, 92, 9a, 9r}, Σ = {0, 1}, r = {0, 1, L}, and 8 is: 8(qo, U) = (qr, U, R) 8(90, 0) = 8(go, 1) (91, 0, R) (qo, 1, R) = 8(g1, L) = (ga, U, R) 8(91,0) = (91, 0, R) 8(91, 1) = (92, 1, R) = (92, U, R) 8(92, U) 8(92, 0) = (90, 0, R) 8(92, 1) = (92, 1, R) i. Prove that M is NOT a decider. ii. Mathematically describe the language A that M recognises. Prove that A ≤ L(M). iii. Prove A = L(M). iv. Is A Turing-decidable? [Give clear reasons for your answer. No need for a formal proof.]
- Q4/Full the following blanks (1101 1010)BCD(5211) = ( )BCD(3321)=()EX-3=()16 * (1101 1010)BCD(5211) = (1110 1100)BCD(3321)=(1010110)EX-3= (A6)16 (1101 1010)BCD(5211) = (1110 0111)BCD(3321)=(1011001)EX-3= (56)16 (1101 1010)BCD(5211) = (1101 0111)BCD(3321)=(1011001)EX-3= (2B)16 (1101 1010)BCD(5211) = (1011 1110)BCD(3321)=(1000111)EX-3= (44)16 None of them IIMATLAB can solve differential equations using the dsolve command. dsolve symbolic solution of ordinary differential equations. Example: syms y(x) Dy(x)= diff(y) D2y(x) = diff(y,2) YGS1 = dsolve (D2y+2*Dy+y==0) YGS2 = dsolve (D2y+2*Dy+y==0, y(0)=-1, y(0)==2) Problems: Solve the following differential equations, using the initial conditions when applicable 1. yı" + 8y₁ + 16y₁ = 0, y₁ (0) = 1, y₁ (0) = 0 2. y2" - 3y₂ + 2y2 = 0, y2(1) = 1, y₂(1) = 4 3. y3" + 8y₂ + 17y3 = 0 4. y + 8y +16y₁ = 0 5. yy-729y5 = 0MATLAB can solve differential equations using the dsolve command. dsolve Symbolic solution of ordinary differential equations. Example: syms y(x) Dy (x) = diff(y) D2y (x) = diff(y,2) yGS1 = dsolve (D2y+2*Dy+y==0) yGs2 = dsolve(D2y+2*Dy+y==0, y(8)==1, y(8) ==2) Problems: Solve the following differential equations, using the initial conditions when applicable 1. yı"+8y, + 16y1 = 0, yı(0) = 1, y,(0) = 0 2. y2" – 3y, + 2y2 = 0, yz(1) = 1, y,(1) = 4 3. ys"+ 8y, + 17y3 = 0 4. y + 8y! + 16y4 = 0 5. y" – 729ys = 0 Script e A Save CReset E MATLAB Documentation 1 %solve the given Homogeneous Differential Equations with Constant Coefficients 2 %Initialize the variables 3 4 5 %solve the equation y"+8y'+16y=0, y(0)=1, y' (8)=0. Save your answer as y1; 7 %Solve the equation y"-3y'+2y=0, y_2(1)=1, y_2' (1)=4. Save your answer as y2; 9 %Solve the equation y"+8y'+17y=0. Save your answer as y3; 10 11 %solve the equation y^{IV} + 8y" + 16y=8. Save your answer as y4; 12 13 %Solve the equation…
- Create a transparent task of how many 1s each appear on a particular number. Lone means that a number does not appear twice or more in a row. Examples count LoneOnes (101) -2 count LoneOnes (1191) → 1 count LoneOnes (1111) countLoneOnes (462) → 0 Solution in java scriptimport matplotlib.pyplot as pltvtn = 0.7vtp = -0.7vdd = 5Bn = Bp = 380vout = [None]*26vin = [0.0,0.2,0.4,0.6,0.8,1.0,1.2,1.4,1.6,1.8,2.0,2.2,2.4,2.6,2.8,3.0,3.2,3.4,3.6,3.8,4.0,4.2,4.4,4.6,4.8,5.0]for i in range(0,26):if 0<=vin[i]<=vtn :vout[i] = vddelif vtn <= vin[i] <= vdd / 2:vout[i] = (vin[i] - vtp) + ((vin[i] - vtp) ** 2 - 2 * (vin[i] - vdd / 2 - vtp) * vdd - Bn/Bp * (vin[i] - vtn) ** 2) ** 0.5elif vin[i] == vdd / 2:vout[i] = vin[i]elif vdd / 2 < vin[i] <= vdd + vtp:vout[i] = (vin[i] - vtn) - ((vin[i] - vtn)** 2 - Bn/Bp * (vin[i] - vdd - vtp)** 2)** 0.5elif vin[i] > vdd + vtp:vout[i] = 0plt.plot(vin, vout, marker="o")plt.xlabel("Vin")plt.ylabel("Vout")plt.show() this code in python and out this picture each if statement represent different region I want colored each region in different color pleaseGiven A={1,2,3,4,56}, B= {2,4,5,6} and C= (1,6,7} 1. B' U C'=