Review Conceptual Example 6 before working this problem. For water vapor in air a 293 K, the diffusion constant is D = 2.4 x 10-5 m²/s. As outlined in Problem 51(a), the time required for the first solute molecules to traverse a channel of length L is t = L²/(2D), according to Fick's law. (a) Find the time t for L = 0.0180 m. (b) For comparison, how long would a water molecule take to travel L = 0.0180 m at the translational rms speed of water molecules (assumed to be an ideal gas) at a temperature of 293 K? (a) Number Diffusion V. rms L Units (b) Number i Units
Review Conceptual Example 6 before working this problem. For water vapor in air a 293 K, the diffusion constant is D = 2.4 x 10-5 m²/s. As outlined in Problem 51(a), the time required for the first solute molecules to traverse a channel of length L is t = L²/(2D), according to Fick's law. (a) Find the time t for L = 0.0180 m. (b) For comparison, how long would a water molecule take to travel L = 0.0180 m at the translational rms speed of water molecules (assumed to be an ideal gas) at a temperature of 293 K? (a) Number Diffusion V. rms L Units (b) Number i Units
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter20: Kinetic Theory Of Gases
Section: Chapter Questions
Problem 37PQ
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Question
![Review Conceptual Example 6 before working this problem. For water vapor in air a 293 K, the diffusion constant is D = 2.4 x 10-5 m²/s.
As outlined in Problem 51(a), the time required for the first solute molecules to traverse a channel of length L is t = L²/(2D), according
to Fick's law. (a) Find the time t for L = 0.0180 m. (b) For comparison, how long would a water molecule take to travel L = 0.0180 m at
the translational rms speed of water molecules (assumed to be an ideal gas) at a temperature of 293 K?
(a) Number
Diffusion
V.
rms
L
Units
(b) Number
i
Units](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7b9c6d46-6086-4e4a-ba9e-28cab02908a3%2F762b2cf7-f6ad-47d8-8677-b311ab0a13e3%2F3g66i0a_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Review Conceptual Example 6 before working this problem. For water vapor in air a 293 K, the diffusion constant is D = 2.4 x 10-5 m²/s.
As outlined in Problem 51(a), the time required for the first solute molecules to traverse a channel of length L is t = L²/(2D), according
to Fick's law. (a) Find the time t for L = 0.0180 m. (b) For comparison, how long would a water molecule take to travel L = 0.0180 m at
the translational rms speed of water molecules (assumed to be an ideal gas) at a temperature of 293 K?
(a) Number
Diffusion
V.
rms
L
Units
(b) Number
i
Units
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