The equation of the tangent line to the curve x2 + y = 9, at (6,-16) is %3| 16 y = (x + 6) – 16 6 6 (x + 6) + 16 16 y = y = 16 16 y = (x - 6) + 16 6. 6 Y = (х — 6) — 16 - 16
The equation of the tangent line to the curve x2 + y = 9, at (6,-16) is %3| 16 y = (x + 6) – 16 6 6 (x + 6) + 16 16 y = y = 16 16 y = (x - 6) + 16 6. 6 Y = (х — 6) — 16 - 16
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter6: Applications Of The Derivative
Section6.CR: Chapter 6 Review
Problem 32CR
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Question
![The equation of the tangent line to the curve
x2 + y? = 9, at (6,-16) is
16
(x + 6) – 16
6.
(x + 6) + 16
16
6.
16
16
Y =
(x - 6) + 16
6.
(г — 6) — 16
16](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb165d4a0-04d2-4fd6-89e1-038549e32c7d%2F3505edd2-0c37-45e5-a3e9-55d6632aa070%2F393zolk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The equation of the tangent line to the curve
x2 + y? = 9, at (6,-16) is
16
(x + 6) – 16
6.
(x + 6) + 16
16
6.
16
16
Y =
(x - 6) + 16
6.
(г — 6) — 16
16
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