TITRATION PROBLEM-SOLVING: 74.5 ml of 2.61 M sodium hydroxide is added to 99.2 ml of acetic acid, and the resulting solution is found to be basic. It required 12.7 ml of 1.25 M sulfuric acid to reach neutrality. What is the molarity of the original acetic acid solution?

TITRATION PROBLEM-SOLVING: 74.5 ml of 2.61 M sodium hydroxide is added to 99.2 ml of acetic acid, and the resulting solution is found to be basic. It required 12.7 ml of 1.25 M sulfuric acid to reach neutrality. What is the molarity of the original acetic acid solution?

Introductory Chemistry: An Active Learning Approach

6th Edition

ISBN:9781305079250

Author:Mark S. Cracolice, Ed Peters

Publisher:Mark S. Cracolice, Ed Peters

Chapter16: Solutions

Section: Chapter Questions

Problem 37E

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Question

TITRATION PROBLEM-SOLVING:
74.5 ml of 2.61 M sodium hydroxide is added to 99.2 ml of acetic acid, and the resulting solution is found to be basic.
It required 12.7 ml of 1.25 M sulfuric acid to reach neutrality. What is the molarity of the original acetic acid solution?

1.
Look for the final equivalent solution. If a 1 ml of HCI is equivalent to 2.5 ml of 0.2 N NaOH the volume of the
alkali would be consumed by 15 ml of acid.

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