Using the Law of Sines to solve the triangle if ZA = 36°, ZC = 70°, b = 11: ZB is degrees; a = C = You may round to two decimal places. Assume ZA is opposite side a, ZB is opposite side b, and ZC is opposite side c.
Using the Law of Sines to solve the triangle if ZA = 36°, ZC = 70°, b = 11: ZB is degrees; a = C = You may round to two decimal places. Assume ZA is opposite side a, ZB is opposite side b, and ZC is opposite side c.
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter9: Real Numbers And Right Triangles
Section9.8: The Sine And Cosine Ratios
Problem 5E
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![Using the Law of Sines to solve the triangle if ZA = 36°, ZC = 70°, b = 11:
ZB is
degrees;
a =
;
C =
;
You may round to two decimal places.
Assume ZA is opposite side a, ZB is opposite side b, and ZC is opposite side c.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7d0ae169-4887-41ce-9cc3-198880517dc4%2Fcb6124b4-9c3a-4ad9-aa36-2e9850929f83%2F10itwhn_processed.png&w=3840&q=75)
Transcribed Image Text:Using the Law of Sines to solve the triangle if ZA = 36°, ZC = 70°, b = 11:
ZB is
degrees;
a =
;
C =
;
You may round to two decimal places.
Assume ZA is opposite side a, ZB is opposite side b, and ZC is opposite side c.
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