Yeast cells has been cultured on glucose (Table 1). The growth data follows the Monod Equation Table 1: Growth data for yeast cells Glucose concentration (mg/L) Specific growth rate (h*¹) Observed yield, Y'x/s (g/g) 7 10 15 40 200 0.066 0.088 0.12 0.2 0.304 0.294 0.330 0.364 0.419 0.451 1000 0.340 0.458 a) Calculate the maximum specific growth rate (max) and the substrate constant (Ks)
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- Yeast cells are added to a 3.0 L batch bioreactor so that the initial cell concentration is [X]. = 1.3 g cells / L. The growth mediğim in the reactor, which is well-mixed so the cells have access to all nutrients, contains 150 g CELL DATA ribose (C5H10O5, MW 150), 75 g ammonia (NH3, MW 17), and 85 g oxygen (O2, MW 32). A-10. Determine the maximum concentration of cells, [X], that will form in the bioreactor when the limiting nutrient is consumed. Search Yx/ribose YX/02 YX/NH3 Specific growth rate on limiting nutrient, u Lag phase duration Deceleration phase duration 0.48 g/g 0.87 g/g 0.23 g/g 0.51 h 30 minutes NegligibleA culture consisting of 100 litres of nutrient medium containing 12 g l-1 of growth limiting substrate is inoculated with 10g of bacteria in a batch fermenter. The yield of biomass from substrate is 0.05 g g-1 . The maintenance coefficient is 2.0 g g-1 h -1 . The specific rate of product formation due to maintenance is 1.0 h-1 . The maximum specific growth rate of the organism is 0.3 h -1 . YPX= 7.7 and product formation is directly linked with metabolism. a) What is the time required to produce 15 g of biomass? !!!!! ANS IS 3.07 HRS!!!! STEPS on how to reach this pleaseWhy is the colony diameter of the yeast culture grown on potato dextrose agar is larger than those grown on acetate agar? Give and discuss the reasons for this different in growth.
- For an exponentially growing culture that increases from 5 *106cells/ml to 5 * 108cells/ml in 8 h, calculate g, n, and k forthis culture.Table 3 - Determination Tube # Potato Expt. Temp. 2c 3c 4c 5c extract (mL) 2 2 2 2 room temp 20 °℃ 40 °℃ 75 °℃ Boiling 100 °C of the optimum temperature of catechol oxidase enzyme. 1st Absorbance 0 min. at Expt. Temp. dH₂O Catechol (mL) (mL) 0 0 0 0 13 13 13 13 Start Time: 4:20 Absorbance: 0.072 Start Time: 4:25 Absorbance: 0.114 Start Time: 4:25 Absorbance: 2nd Absorbance after 10 min. in Expt Temp. Absorbance: 0.097 Time for reading: 4:30 Absorbance: 0.128 Time for reading: 4:33 Absorbance: Subtract 1st from 2nd absorbance 0.056 0.137 Time for reading: 4:35 Absorbance: 0.132 0-193 Start Time: 4:27 Time for reading: 437 Absorbance: 0-126 0.023 0.061 0.029 3rd Absorbance after 10 more min. at Room Temp. Time for reading: 4:40 Absorbance: Based on the data from Table 2 answer these questions: Q10) What is the enzyme's optimum temperature? Answer: Q11) Use the difference between 2nd and 1st absorbance to support your conclusion for the optimum temperature. 0.159 Time for reading: 4:43…Table 3-Determination Tube # Potato Expt. Temp. 2c 3c 4c 5c extract (mL) 2 2 2 2 room temp 20 °C 40 °C 75 °C of the optimum temperature of catechol oxidase enzyme. 1st Absorbance 0 min. at Expt. Temp. Boiling 100 °C dH₂O Catechol (mL) (mL) 0 0 0 0 13 13 13 13 Start Time: 4:20 Absorbance: 0.072 Start Time: 4:25 Absorbance: 0.114 Start Time: Absorbance: 25 0.132 Start Time: 4:27 Absorbance: 0.097 2nd Absorbance after 10 min. in Expt Temp. Time for reading: 4:30 Absorbance: 0.128 Time for reading: 4:33 Absorbance: 0.036 0-137 Time for reading: 4:35 Absorbance: Subtract 1st from 2nd absorbance 0.193 Time for reading: 4:37 Absorbance: 0-126 0.023 0.061 0.029 Based on the data from Table 2 answer these questions: Q10) What is the enzyme's optimum temperature? Answer: Q11) Use the difference between 2nd and 1st absorbance to support your conclusion for the optimum temperature 3rd Absorbance after 10 more min. at Room Temp. Time for reading: 4:40 Absorbance: 0.159 Time for reading: 4:43…
- Laboratory Report Sheet – ENZYMES Potato Peroxidase OBSERVATIONS: RESULT boiled potato extract + phenol + H2O2 boiled potato extract + catechol + + H2O2 boiled potato ex tract + Guiac + H2O2Which growth condition shown above has the largest doubling time? How would you explain the observed growth data based on information about metabolism and oxygen requirements? Definitely take into consideration the relative growth of all three growth conditions. Surprisingly, cultures grown in anerobic conditions are non-motile, whereas cultures grown in normal O2 saturation have several peritrichous flagella and swim motility. Explain briefly the mechanism of flagellar motility in terms of energy source for flagellar motility and why it may be lower in anaerobic conditions for L. monocytogenes.continuous disc stack centrifuge is operated at 5000 rpm for separation of tukers' yeast. At a feed rate of 60 min21, thirty of the cells are recovered. For operation at constant centrifuge speed, solids recovery is inversely proportional to the flow rate. (a) What flow rate is required to achieve 90% cell recovery if the centrifuge speed is maintained at 5000rpm thi What operating speed is required to achieve 90% recovery at a feed rate of 60 min211).
- Consider the desired phenotype pattern of candidates that we wish to advance into experiments in Week 5 and beyond. If the growth patterns illustrated below are observed in your Week 4 results, which of the candidates would you select for further analysis? Select all that apply. Candidate A B A B C с = vigorous growth on this medium = impaired/slow growth on this medium = no growth on this medium SC-H B SC-K A B YP GalSydney Brenner isolated Salmonella typhimurium mutants that were implicated in the biosynthesis of tryptophan and would not grow on minimal medium. When these bacterial mutants were tested on minimal medium to which one of four compounds (indole glycerol phosphate, indole, anthranilic acid, and tryptophan) had been added, the growth responses shown in the following table were obtained. Mutant Minimal medium Anthranilic Indole glycerol acid Indole Tryptoph phosphate trp-1 trp-2 trp-3 trp-4 trp-6 trp-7 trp-8 trp-9 trp-10 trp-11 - Give the order of indole glycerol phosphate, indole, anthranilic acid, and tryptophan in a biochemical pathway leading to the synthesis of tryptophan. Indicate which step in the pathway is affected by each of the mutations. + 1 + 1 IIE. coli has a doubling time of 0.345 hours at 37 0C. Starting with 1 milligram of cells, assuming a lag phase of 30 minutes and a stationary phase of 30 minutes, what number of cells would you expect at the end of 13h, assuming that besides the lag and stationary phases the culture is continuously in exponential phase. Assume that ln (2) = 0.69 and that the mass of a single cell is 10^(-12) g.