Concept explainers
If a restriction enzyme cuts between G and A whenever it encounters the sequence GAATTC, how many fragments will be produced when the enzyme digests DNA with the following sequences?
TGAGAATTCAACTGAATTCAAATTCGAATTCTTAGC
a. | Two |
b. | Three |
c. | Four |
d. | Five |
Introduction:
Restriction enzyme finds the specific sequence of interest and cut the DNA sequence. It results in the fragments of specific DNA sequence.
Answer to Problem 1MCQ
Correct answer:
GAATTC occurs three times in the given sequence. Thus, the restriction enzyme will cut three times, which will produce four fragments. Hence, the correct answer is option c.
Explanation of Solution
Reason for correct answer:
Option c. is given as, “Four.”
Restriction enzyme will cut the sequence where it will find the GAATTC and this sequence is present three times in the given sequence; TGAG/AATTCAACTG/AATTCAAATTCG/AATTCTTAGC. Hence, it will produce four fragments of the given sequence.
Reason for incorrect answer:
Option a. is given as, “Two.”
GAATTC is present three times in the sequence of interest, which will generate four fragments, not two. Hence, option a. is incorrect.
Option b. is given as, “Three.”
When restriction enzyme will cut the sequence three times, then four fragments will be produced. Hence, option b. is incorrect.
Option d. is given as, “Five.”
GAATTC occurs three times in the given sequence; thus, it will generate four fragments, not five. Hence, option d. is incorrect.
Hence, the options a., b., and d. are incorrect.
GAATTC is present three times in the sequence of interest. The restriction enzyme will cut the sequence three times and will generate four fragments. Thus, the correct option is c.
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Chapter 11 Solutions
BIOLOGY:THE ESSENTIALS (LL) W/CONNECT
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- Look at the amino acid chart below that the proctor placed on a board at the front of the classroom before asking the students questions. Help Arcel characterize the DNA mutation (HbS) according to its amino acid and position. a The disease is caused by GAG20→GTG20. b The disease is caused by val6→gln6. c The disease is caused by glu6→ val6. d The disease is caused by glu20→ val20.arrow_forwardWhat are the sticky ends of the restriction fragments? Select one: a. The surfaces of sticky ends contain matching base pairs, allowing fragments to splice. b. The surfaces of sticky ends have glue like substance that allow fragments to splice. c. The surfaces of sticky ends contain the exact same nucleotides, allowing fragments to bond. d. The surfaces of sticky ends have velcro like structure, allowing fragments to bond.arrow_forwardWhich of the following is not a DNA sequence? a. TAG b. AUGAUUCT d. AAAAAAAAAA e. CGGarrow_forward
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- in Cohen-Boyer's recombinant DNA procedure _______ must be used for both the bacterial DNA and the amphibian DNA _______. a. the same restrictions enzyme, so that the the restriction site are identical in the DNA of each species b. different restriction enzymes, so that the genes outside the restriction site are maintained c. the same restriction enzymes, to ensure that the newly formed DNA can replicate d. different restriction enzymes, to ensure that the newly introducted genes are maintained in the bacterial DNAarrow_forwardThe double stranded DNA sequence of a restriction enzyme cut site is typically complementary, antiparallel, and palindromic. Given these criteria, which one of the following single stranded sequences represents a restriction enzyme cut site when made double stranded? a. None of these sequences satisfy the given criteria b. 5' – GTCCTG – 3' c. 5' – GTCGTC – 3' d. 5' – GTCGAC – 3' e. 5' – GGTTCC – 3'arrow_forwardFeatures of restriction enzymes include the following, except __________ . a. They are produced by both prokaryotes and eukaryotesb. may be type IIc. make single and double stranded breaks in DNAd. operate at a single temperaturee. Are used in nature to destroy bacteriophage DNAarrow_forward
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