Concept explainers
An electron moving with velocity
Answer to Problem 1FTD
Explanation of Solution
Write the equation to find the force acting on a particle in magnetic field.
Here,
From the equation we can see that both velocity vector and magnetic field vector are perpendicular to each other and they are both perpendicular to the force.
Therefore all the three vectors are perpendicular to each other.
Conclusion:
Therefore, vectors
Want to see more full solutions like this?
Chapter 26 Solutions
Essential University Physics
Additional Science Textbook Solutions
University Physics with Modern Physics (14th Edition)
Sears And Zemansky's University Physics With Modern Physics
College Physics: A Strategic Approach (4th Edition)
Conceptual Physics (12th Edition)
Conceptual Physical Science (6th Edition)
University Physics (14th Edition)
- An ion with charge q but with unknown mass is accelerated through a potential difference V , and enters a magnetic field B. After following the semicircular path shown, it lands a distance x from where it entered the magnetic field. Find an expression for the mass of the ion.arrow_forwardA particle with charge 5nC initially moves with velocity v=(11i +4.22j) m/s.If this particle encounters a magnetic field B=1.20k T Sketch the particles path in the presence of the magnetic field. Include labelled velocity, magnetic field, and magnetic force vectors. Find the magnetic force vector on the particle. Include both magnitide and the direction. Find the radius if the particles circular path, if the mass of the particle is 1.67 milligramsarrow_forwardAt an instant in time, an electron has velocity, v = 100i - 300j + 200k km/s while it is in a magnetic field, B = 2i - 3j + 4k T. Find the acceleration of the electron at this instant. Use the vector table below to show any important vectors. Show only numerical results in the table. (m = 9.109 x 10*3" kg, q = -1.6 X 10*1º C) Vector i karrow_forward
- (unrealistic) E/M Forces 6. A particle of charge q = 0. 25C and mass m = 1.0kg is moving with a velocity of v = (2,0,0)m/s. The charged particle finds itself in an electric field of E = (8,8,8)N/C and a magnetic field of B = (0,0, -2)T. What will be the initial vector acceleration of the particle?arrow_forwardA neutral particle is at rest in a uniform magnetic field of magnitude |B|. At time t = 0 it decays into two charged particles each of mass m. a) If the charge of one of the particles in +q, what is the charge of the other? b) The two particles move off in separate paths, both of which lie in the plane perpendicular to B. At a later time the particles collide. Express the time from decay in terms of m, |B| and q.arrow_forward= A particle with a mass of 8.52 kg and a charge of 5.3 C is projected into a uniform magnetic field of 2.62 T that is directed along the z-axis. At t=0, the particle has velocity components of vox = 5.95 m/s, voy = 0 m/s, and voz 0.47 m/s. Only the magnetic force acts on the particle. Find the period (in s) of the particle per revolution.arrow_forward
- This positively charged particle has a charge of +25 nC and a velocity of 5300 m/s. It enters a region that has an electric field E = 140 N/C and magnetic field B = 0.29 T, directed as shown in the figure (the dots represent a field directed toward you). Note that 1 nC = 10-9 C and that 1μN = 10-6 N. What force will the particle feel due to the electric field? UN in the following direction: Select an answer What force will the particle feel due to the magnetic field? FB What is the net force on the particle? |F| uN in the following direction: Select an answer UN in the following direction: Select an answerarrow_forwardA charged particle having charge 4x1018 C and mass 20 g moves with a velocity of i = (î – 2j ) in a region in which the magnetic field is B = (-î+ 4ĵ + k ) T and electric Q3- %3D field is Ē = (4î – 2ĵ – K) V /m . Find %3D (a) the electric force this particle experiences, (b) the magnetic force this particle experiences, (c the acceleration this particle experiences.arrow_forwardtwo particles with the same charge, but with different masses m2 = 2m1 describe circular trajectories with the same radius in the magnetic field. The impulse of the first particle is: a) twice smaller than the second b) twice as large as the second c) equal to the momentum of the second particlearrow_forward
- Near the surface of the earth, a magnet is made to levitate above another magnet, which is on a table, due only to magnetic force. The levitating magnet has a mass of 150 g with its north pole facing the magnet on the table and its south pole facing upwards. A stream of electrons is shot between the magnets, perpendicular to the field. Describe, in general, what will happen to the electrons, ignoring the effects of gravity on the electrons. Sketch the magnetic field between the two magnets.arrow_forwardA particle is launched from the origin on the ground with an initialvelocity? = (2.40 m/s) ? + (2.00 m/s) ?. The particle falls freely under earth’sgravitational field.arrow_forwardA particle with charge 9.78 x 10^-6 C moves at 8.62 x 10^6 m/s through a magnetic field of strength 1.18 T. The angle between the particle s velocity and the magnetic field direction is 40.5 degrees and the particle undergoes an acceleration of 16.0 m/s^2. What is the particle s mass?arrow_forward
- Classical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage LearningGlencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-Hill