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Concept explainers
A camera obscura is used to form an image of a distant object. If the object is 10.0 m away from the aperture and the magnification of the image is –0.15, what is the image distance?
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The distance of the image.
Answer to Problem 1PQ
The image distance is
Explanation of Solution
Write the expression for the magnification.
Here,
From the above equation we get,
Conclusion:
Substitute
Therefore, the image distance is
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Chapter 37 Solutions
Physics for Scientists and Engineers: Foundations and Connections
- A lamp of height S cm is placed 40 cm in front of a converging lens of focal length 20 cm. There is a plane mirror 15 cm behind the lens. Where would you find the image when you look in the mirror?arrow_forwardIn Figure P35.30, a thin converging lens of focal length 14.0 cm forms an image of the square abed, which is he = hb = 10.0 cm high and lies between distances of pd = 20.0 cm and pa = 30.0 cm from the lens. Let a, b, c. and d represent the respective corners of the image. Let qa represent the image distance for points a and b, qd represent the image distance for points c and d, hb, represent the distance from point b to the axis, and hc represent the height of c. (a) Find qa, qd, hb, and hc. (b) Make a sketch of the image. (c) The area of the object is 100 cm2. By carrying out the following steps, you will evaluate the area of the image. Let q represent the image distance of any point between a and d, for which the object distance is p. Let h represent the distance from the axis to the point at the edge of the image between b and c at image distance q. Demonstrate that h=10.0q(114.01q) where h and q are in centimeters. (d) Explain why the geometric area of the image is given by qaqdhdq (e) Carry out the integration to find the area of the image. Figure P35.30arrow_forwardThe end of a solid glass rod of refractive index 1.50 is polished to have the shape of a hemispherical surface of radius 1.0 cm. A small object is placed in air (refractive index 1.00) on the axis 5.0 cm to the left of the vertex. Determine the position of the image.arrow_forward
- What will be the angular magnification of a convex lens with the focal length 2.5 cm?arrow_forwardYou view an object by holding a 2.5 cm-focal length magnifying glass 10 cm away from it. How far from your eye should you hold the magnifying glass to obtain a magnification of 10 ?arrow_forwardWhat is the angular size of the Moon if viewed from a binocular that has a focal length of 1.2 cm for the eyepiece and a focal length of 8 cm for the objective? Use the radius of the moon 1.74106 m and the distance of the moon from the observer to be 3.8108m .arrow_forward
- An unknown planet at a distance of 1012 m from Earth is observed by a telescope that has a focal length of the eyepiece of 1 cm and a focal length of the objective of I m. If the far away planet is seen to subtend an angle of 105 radian at the eyepiece, what is the size of the planet?arrow_forwardA nearsighted man cannot see objects clearly beyond 20 cm from his eyes. How close must he stand to a mirror in order to see what he is doing when he shaves?arrow_forwardWhat is the focal length of a magnifying glass that produces a magnification of 3.00 when held 5.00 cm from an object, such as a rare coin?arrow_forward
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