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Calorimetry Percent Yield

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The percent yield of this experiment is calculated to be 33.9% thus making this experiment not very reliable and the product, not very pure. This may be due to a number of different reasons. First of all, some transfer residue could have remained on the conical vial after the sample was transferred into the pre-weighed vial. Another possible source of this low percent yield, may have been from adding too much drying agent. If too much of the anhydrous sodium sulfate is added, some of the product will be dried out of the solution. The idea of the drying agent is to take out the excess water in the product, however, if left in the vial for too long or too much was added, the water may have all been absorbed, but now some of the product has as well. One final reason that could contribute to this low percent yield is when, after extracting the bottom layer in the conical vial with the sodium bicarbonate, perhaps too much product was removed along with that bottom layer. By taking out some of the product that would have contributed to the overall percent yield calculation, the yield will automatically be lowered. Next time, avoiding …show more content…

One thing shown through this graph is the functional group present in the product tested. Different functional groups absorb light at different frequencies. When placed into the infrared spectrometer, the energy bands given off by the compound identified the sample as an ester. There are some obvious unique spikes in the graph that indicate the presence of an ester. The first is a fairly short and broadened spike around 3000 that results from a C-H bond. Another spike is a tall, narrow spike located around 1750 that represents the C=O bond of the ester. A somewhat shorter spike is seen around 1300, which indicates the C-O bond from where the alcohol joined with the acetic acid to allow the formation of the

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