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1. A rectangular beam is 15 in. wide and 30 in. deep. For f= 4000 psi and f = 60,000 psi, determine the required spacing of No. 4 (No. 13) closed stirrups for a factored shear of 80 kips and factored torsional moment of 50 ft-kips. The stirrup centroid is located 1.75 in. from each concrete face. The effective depth is 26.5 in. Given parameters: B₁=0.85, E = 29000000 psi, E=57000fpsi=3604997 psi f, V:= 80 kip E $=0.90 E -0. = 0.002 T := 50 ft-kip $ = 0.75 λ=1.0 Tip: To estimate the required spacing, the required steel area due to torsion and due to shear must be combined. Therefore, 2A + Ay As No.4- Using the equations in the textbook, A+ shall be estimated in Av function of s. I.e., A₂ = xxx.yy x s. In principle, must be estimated from shear analysis, but to save S in² time it will be given as = 0.0355 in

1. A rectangular beam is 15 in. wide and 30 in. deep. For f= 4000 psi and f = 60,000 psi, determine the required spacing of No. 4 (No. 13) closed stirrups for a factored shear of 80 kips and factored torsional moment of 50 ft-kips. The stirrup centroid is located 1.75 in. from each concrete face. The effective depth is 26.5 in. Given parameters: B₁=0.85, E = 29000000 psi, E=57000fpsi=3604997 psi f, V:= 80 kip E $=0.90 E -0. = 0.002 T := 50 ft-kip $ = 0.75 λ=1.0 Tip: To estimate the required spacing, the required steel area due to torsion and due to shear must be combined. Therefore, 2A + Ay As No.4- Using the equations in the textbook, A+ shall be estimated in Av function of s. I.e., A₂ = xxx.yy x s. In principle, must be estimated from shear analysis, but to save S in² time it will be given as = 0.0355 in

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A rectangular beam is 15 in. wide and 30 in. deep. For f c′ = 4000 psi and fyt = 60,000 psi, determine the required spacing of No. 4 (No. 13) closed stirrups for a factored shear of 80 kips and factored torsional moment of 50 ft-kips. The stirrup centroid is located 1.75 in. from each concrete face. The effective depth is 26.5 in.
1. A rectangular beam is 15 in. wide and 30 in. deep. For f = 4000 psi and f = 60,000 psi, determine the required spacing of No. 4 (No. 13) closed stirrups for a factored shear of 80 kips and factored torsional moment of 50 ft-kips. The stirrup centroid is located 1.75 in. from each concrete face. The effective depth is 26.5 in. Given parameters: B₁=0.85, E = 29000000 psi, E57000fpsi=3604997 psi f, V:= 80 kip E $=0.90 E -0. = 0.002 T := 50 ft-kip $ = 0.75 λ=1.0 Tip: To estimate the required spacing, the required steel area due to torsion and due to shear must be combined. Therefore, 2A + A₂ = As No.4- Using the equations in the textbook, A+ shall be estimated in Av function of s. I.e., A₂ = xxx.yy x s. In principle, must be estimated from shear analysis, but to save S in² time it will be given as = 0.0355 in
Transcribed Image Text:1. A rectangular beam is 15 in. wide and 30 in. deep. For f = 4000 psi and f = 60,000 psi, determine the required spacing of No. 4 (No. 13) closed stirrups for a factored shear of 80 kips and factored torsional moment of 50 ft-kips. The stirrup centroid is located 1.75 in. from each concrete face. The effective depth is 26.5 in. Given parameters: B₁=0.85, E = 29000000 psi, E57000fpsi=3604997 psi f, V:= 80 kip E $=0.90 E -0. = 0.002 T := 50 ft-kip $ = 0.75 λ=1.0 Tip: To estimate the required spacing, the required steel area due to torsion and due to shear must be combined. Therefore, 2A + A₂ = As No.4- Using the equations in the textbook, A+ shall be estimated in Av function of s. I.e., A₂ = xxx.yy x s. In principle, must be estimated from shear analysis, but to save S in² time it will be given as = 0.0355 in
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