1. The example in the previous chapter, National Homebuilders, Inc. evaluated cut-and-finish equipment from vendor A (6-year life) and vendor B (9-year life). The PW analysis used the LCM of 18 years. Consider only the vendor A option now. The cash diagram shows the cash flows for all three life cycles (first cost $-15,000; annual M&O costs $-3500; salvage value $1000). Demonstrate the equivalence at i= 15% of PW over three life cycles and AW over one cycle. In previous example, present worth for vendor A was calculated as PW = $-45,036. cost (A) income year net cash flow 0 -15000 0 -15000 1 -3500 0 -3500 2 -3500 0 -3500 3 -3500 0 -3500 4 -3500 0 -3500 5 -3500 0 -3500 6 -18500 1000 -17500 7 -3500 0 -3500 8 -3500 0 -3500 9 -3500 0 -3500 10 -3500 0 -3500 11 -3500 0 -3500 12 -18500 1000 -17500 13 -3500 0 -3500 14 -3500 0 -3500 15 -3500 0 -3500 16 -3500 0 -3500 17 -3500 0 -3500 18 -3500 1000 -2500 ($45,036.36) annual W ($7,349.32)

1. The example in the previous chapter, National Homebuilders, Inc. evaluated cut-and-finish equipment from vendor A (6-year life) and vendor B (9-year life). The PW analysis used the LCM of 18 years. Consider only the vendor A option now. The cash diagram shows the cash flows for all three life cycles (first cost $-15,000; annual M&O costs $-3500; salvage value $1000). Demonstrate the equivalence at i= 15% of PW over three life cycles and AW over one cycle. In previous example, present worth for vendor A was calculated as PW = $-45,036. cost (A) income year net cash flow 0 -15000 0 -15000 1 -3500 0 -3500 2 -3500 0 -3500 3 -3500 0 -3500 4 -3500 0 -3500 5 -3500 0 -3500 6 -18500 1000 -17500 7 -3500 0 -3500 8 -3500 0 -3500 9 -3500 0 -3500 10 -3500 0 -3500 11 -3500 0 -3500 12 -18500 1000 -17500 13 -3500 0 -3500 14 -3500 0 -3500 15 -3500 0 -3500 16 -3500 0 -3500 17 -3500 0 -3500 18 -3500 1000 -2500 ($45,036.36) annual W ($7,349.32)

Managerial Economics: Applications, Strategies and Tactics (MindTap Course List)

14th Edition

ISBN:9781305506381

Author:James R. McGuigan, R. Charles Moyer, Frederick H.deB. Harris

Publisher:James R. McGuigan, R. Charles Moyer, Frederick H.deB. Harris

Chapter17: Long-term Investment Analysis

Section: Chapter Questions

Problem 10E

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5.24 You and your partner have become very interested in cross-country motorcycle racing and wish to purchase entry-level equipment. You have identified two alternative sets of equipment and gear. Package K has a first cost of $160,000, an operating cost of $7000 per quarter, and a salvage value of $40,000 after its 2-year life. Package L has a first cost of $210,000 with a lower operating cost of $5000 per quarter, and an estimated $26,000 salvage value after its 4-year life. Which package offers the lower present worth analysis at an interest rate of 8% per year, compounded quarterly?
Given the following two alternatives and using the repeatability assumption and MARR=15%/year, the equation for computing the present worth of vendor B is Vendor A First Cost, $ -15,000 Annual cost, $ per year -3500 Salvage Value, $ 1000 Life, years 3 Vendor B -18000 -3100 2000 4 OPW=18000-18000(P/F,15%, 4)-18000(P/F,15%, 8)+2000(P/F, 15%, 4)+2000(P/F, 15%, 8) +2000 (P/F, 15%, 12)-3100(P/A, 15%, 12) PW=18000-18000(P/F, 15%, 12)+2000(P/F, 15%, 4)+2000 (P/F, 15%, 8)+2000(P/F, 15%, 12)-3100(P/A, 15%, 12) O PW=-18000-18000(P/F,15%, 4) - 18000(P/F,15%, 8) +2000(P/F, 15%, 4)+2000(P/F, 15%, 8) +2000 (P/F, 15%, 12)-3100(P/A, 15%, 12) O PW=-18000(P/F,15%, 4) -18000(P/F,15%, 8) +2000(P/F, 15%, 4)+2000(P/F, 15%, 8) +2000(P/F, 15%, 12)-3100(P/A, 15%, 12)
These data were derived from a forest inventory and are to be used to calculate the best (most revenue return) rotation. The manager wishes to maximize net income and has the following information: Establishment Costs: $175/acre Thinning and burning at age 17 cost: $75 Stumpage sells for: $41/unitvol MAR: 6.7% Annual Expenses: $8/acre Inventory Data over Life of the Forest Stand (Ages 0-60 years) Stand age (vol/acre) 15 5.13 20 13.98 25 25.22 30 35.11 35 44.19 40 51.85 45 56.79117447 50 63.03092644 55 68.76322479 60 74.05934015
Determine the present worth, future worth, and annual worth of the following engineering project when the MARR is 15% per year. Is the project acceptable? Investment cost $10,000Expected life 5 yearsMarket (salvage) value $1,000Annual receipts $8,000Annual expenses $4,000
3. As supervisor of a facilities engineering department, you consider mobile cranes to be critical equipment. The purchase of a new, medium-sized truck-mounted crane is being evaluated. The economic estimates for the two best alternatives are shown in the following table. MARR is at 15% per year. You can use the assumption of repeatability in this case. Alternative B A Capital investment $272.000 $346.000 Annual expenses Useful life (years) | Salvage value 28.800 19,300 6. 25,000 40.000 Show that the same selection is made for the following methods: a. RORAI method
3. As supervisor of a facilities engineering department, you consider mobile cranes to be critical equipment. The purchase of a new, medium-sized truck-mounted crane is being evaluated. The economic estimates for the two best alternatives are shown in the following table. MARR is at 15% per year. You can use the assumption of repeatability in this case. Alternative B A Capital investment $272.000 $346.000 Annual expenses Useful life (years) | Salvage value 28.800 19,300 6. 25,000 40.000 Show that the same selection is made for the following methods: a. RORAI method b. AWC method c. EUAC method
Company X has $ 928203 in annual fixed costs. The primary product generates $ 7.79 in revenue per unit and has variable costs of $5.50. The annual breakeven quantity is units.
Given the following pertinent data for four alternatives, what is the best alternative using the incremental ROR method given MARR=10% Initial Cost Annual CF, $ Life, years 30 O Alt. A Alt. B O Alt. C A O Alt. D B +22,000 +35,000 с -200,000 -275,000 -190,000 -331,350 30 D +19500 +42,000 30 30
period of 5 years. Salvage value is estimated at 10% of its first cost. The interest rate is 12% per at $ 150,000. Labor and other operating costs are estimated to be $35,000 per year over the study high-use component can be purchased (bought) for S 25 per unit with a quick delivery. QWA Electronics is considering between two alternatives for their electronic components' needs. A Mestion #6 (20 points) cost of $ 5 per unit. For this option of making the product, QWA needs to purchase equipment today Alternatively, QWA can make the components in-house and have it already available at a variable year. Determine the breakeven quantity based on annual worth of cash flows. 0. Indicate whether to buy or make the components at the expected usage level of 5000 units per year. Explain your answer. a.
The Briggs and Stratton Commercial Division designs and manufacturers small engines for golf turf maintenance equipment. A robotics-based testing system with support equipment will ensure that their new signature guarantee program entitled "Always Insta-Start" does indeed work for every engine produced. Pull System Push System First cost of equipment $-1,300,000 $-2,400,000 AOC per Year $-720,000 $-520,000 Salvage Value $110,000 $100,000 Estimated Life 8 years 8 years Compare the annual worth of the two systems at MARR = 14% per year. Select the better system. The (Click to select) pull system push system is determined to be the better system.
Marmara Processing Technologies Company wants to buy milling cutters in order to meet its increasing production needs. As a result of the studies, the data in the table below were found. According to these data, what will be the current cost of the annual operating expense parameter of alternative B? A Purchase Cost 10.000 12.000 Annual Operating Expense 1.500 1.700 Scrap Values 2.000 3.000 Economic Life 4 4 Capital Cost 10% 10%
5. The physical life is always greater than all the other "life" factors under replacement analysis. 6. If breakeven analysis is conducted with PW analysis for different MEAS, it doesn't guarantee that the fastest alternative to reach its breakeven point has also the highest equivalent worth.