12. A consumer who conforms to the von Neumann-Morgenstern axioms is faced with four situations A, B, C, and D. She prefers A to B, B to C, and C to D. Experimentation reveals that the consumer is indifferent between B and a lottery ticket with probabilities of 0.4 and 0.6 for A and D respectively, and that she is indifferent between C and a lottery ticket with probabilities of 0.2 and 0.8 for B and D respectively. Construct a set of von Neumann- Morgenstern utility numbers for the four situations.

12. A consumer who conforms to the von Neumann-Morgenstern axioms is faced with four situations A, B, C, and D. She prefers A to B, B to C, and C to D. Experimentation reveals that the consumer is indifferent between B and a lottery ticket with probabilities of 0.4 and 0.6 for A and D respectively, and that she is indifferent between C and a lottery ticket with probabilities of 0.2 and 0.8 for B and D respectively. Construct a set of von Neumann- Morgenstern utility numbers for the four situations.

Microeconomic Theory

12th Edition

ISBN:9781337517942

Author:NICHOLSON

Publisher:NICHOLSON

Chapter7: Uncertainty

Section: Chapter Questions

Problem 7.3P

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Suppose that an individual is just willing to accept a gamble to win or lose $1000 if the probability ofwinning is 0.6. Suppose that the utility gained if the individual wins is 100 utils. How much utility does one lose if one loses the gamble?
1. Now, imagine that Port Chester decides to crack down on motorists who park illegally by increasing the number of officers issuing parking tickets (thus, raising the probability of a ticket). If the cost of a ticket is $100, and the opportunity cost for the average driver of searching for parking is $12, which of the following probabilities would make the average person stop parking illegally? Assume that people will not park illegally if the expected value of doing so is negative. Check all that apply. A. 9% B. 18% C. 17% D. 10% 2. Alternatively, the city could hold the number of officers constant and discourage parking violations by raising the fine for illegal parking. Suppose the average probability of getting caught for parking illegally is currently 10% citywide, and the average opportunity cost of parking is, again, $12. The fine that would make the average person indifferent between searching for parking and parking illegally is ____ , assuming that people will not…
4. Marvin is given a number of choices between various lotteries where the possible outcomes include a vacation, a motorbike, a pair of shoes and a round of applause, or X = {v,m, s, a}. It is known that, according to Marvin's preferences, v > m > s > a. In addition, he claims he would be indifferent between the motorbike and a lottery that results in a vacation with probability 0.4 and a pair of shoes with probability 0.6, and he would furthermore be indifferent between a pair of shoes and a lottery that results in a motorbike with probability 0.5 and a round of applause with probability 0.5. Marvin has a utility function u: X → R (in other words u maps each element in X to a real number) and he in an expected utility maximiser (in other words his preferences conform to the axioms G1 to G6). 4.1. Assuming Marvin's claims about indifference are correct, derive u(m) and u(s) in terms of u(v) and u(a). 4.2. Von Neumann-Morgenstern utility functions are only unique up to positive affine…
#3. Hannah gets 50 utils from visiting her family for Thanksgiving. But there is a 1% chance that she will get the coronavirus from them. If she gets the coronavirus, her utility is -6000 utils. Her total utility would be -5950 (i.e. 50 – 6000). She gets 0 utils from staying healthy (total utility = 50 + 0 = 50). If Hannah doesn't visit her family for Thanksgiving, then she gets -25 utils from eating turkey cold cuts alone in front of the TV. In that case, there is no risk of getting sick. What will Hannah do? a. Visit her family for Thanksgiving b. Not visit her family for Thanksgiving c. Visit her family if she is risk-loving, not visit if she is risk-averse d. Visit her family if she is risk-averse, not visit if she is risk-loving
#3. Hannah gets 50 utils from visiting her family for Thanksgiving. But there is a 1% chance that she will get the coronavirus from them. If she gets the coronavirus, her utility is -6000 utils. Her total utility would be -5950 (i.e. 50 – 6000). She gets 0 utils from staying healthy (total utility = 50 + 0 = 50). If Hannah doesn't visit her family for Thanksgiving, then she gets -25 utils from eating turkey cold cuts alone in front of the TV. In that case, there is no risk of getting sick. What will Hannah do?
Betty is looking for a job. She considers job opportunities intwo cities. Bettyís utility is given by y- x, where y is the lifetime income andx is the amount spent on buying a house. The income from City 1 fluctuatesalthough the house price is stable. On the contrary, the income from City2 is stable while the house price fluctuates. If she moves to City 1, Bettycan earn a lifetime income y1 with probability alpha and 1 + y1 with probability1-alpha . The house price in City 1 is x1. Moving to City 2 means that Bettycan earn an income of y2. However, the house price is x2 with probabilitygamma and 1 + x2 with probability 1-gamma . Do the following: (a) Write down theexpected utilities associated with living in the two respective cities, i.e., V1and V2. (b) Derive the condition under which Betty chooses City 1.
To go from Location 1 to Location 2, you can either take a car or take transit. Your utility function is: U= -1Xminutes -5Xdollars +0.13Xcar (i.e. 0.13 is the car constant) Car= 15 minutes and $8 Transit= 40 minutes and $4 What is your probability of taking transit given the conditions above? What is your probability of taking transit if the number of buses on the route were doubled, meaning the headways are halved? Remember to include units.
Gary likes to gamble. Donna offers to bet him $31 on the outcome of a boat race. If Gary's boat wins, Donna would give him $31. If Gary's boat does not win, Gary would give her $31. Gary's utility function is p1x^21+p2x^22, where P₁ and p2 are the probabilities of events 1 and 2 and where x₁ and x₂ are his wealth if events 1 and 2 occur respectively. Gary's total wealth is currently only $80 and he believes that the probability that he will win the race is 0.3. Which of the following is correct? (please submit the number corresponding to the correct answer). 1. Taking the bet would reduce his expected utility. 2. Taking the bet would leave his expected utility unchanged. 3. Taking the bet would increase his expected utility. 4. There is not enough information to determine whether taking the bet would increase or decrease his expected utility. 5. The information given in the problem is self-contradictory.
Gary likes to gamble. Donna offers to bet him $31 on the outcome of a boat race. If Gary’s boat wins, Donna would give him $31. If Gary’s boat does not win, Gary would give her $31. Gary’s utility function is p1x^21+p2x^22, where p1 and p2 are the probabilities of events 1 and 2 and where x1 and x2 are his wealth if events 1 and 2 occur respectively. Gary’s total wealth is currently only $80 and he believes that the probability that he will win the race is 0.3. Which of the following is correct? (please submit the number corresponding to the correct answer). Taking the bet would reduce his expected utility. Taking the bet would leave his expected utility unchanged. Taking the bet would increase his expected utility. There is not enough information to determine whether taking the bet would increase or decrease his expected utility. The information given in the problem is self-contradictory.
Consider IC1. Good X • B • D E Good Y If given a choice between A and D the person will always choose D If given a choice between A and E the person will always choose E O If given a choice between A and G the person will always choose G If given a choice between A and B the person will always choose B Moving from B to D, the person is giving up Good X and getting Good Y. It is uncertain if the person prefers B over D because it's uncertain if he values the extra Y he gets give more enjoyment than the enjoyment he loses from having less X.
#2. Hannah gets 50 utils from visiting her family for Thanksgiving. But there is a 1% chance that she will get the coronavirus from them. If she gets the coronavirus, her utility is -6000 utils. Her total utility would be -5950 (i.e. 50 – 6000). She gets 0 utils from staying healthy (total utility = 50 + 0 = 50). What is her expected utility? a. 50 utils b. -6 utils c. -10 utils d. -5999.5 utils e. -6000 utils f. None of these #3. Hannah gets 50 utils from visiting her family for Thanksgiving. But there is a 1% chance that she will get the coronavirus from them. If she gets the coronavirus, her utility is -6000 utils. Her total utility would be -5950 (i.e. 50 – 6000). She gets 0 utils from staying healthy (total utility = 50 + 0 = 50). If Hannah doesn't visit her family for Thanksgiving, then she gets -25 utils from eating turkey cold cuts alone in front of the TV. In that case, there is no risk of getting sick. What will Hannah do? a. Visit her family for Thanksgiving b. Not visit her…
4. Kate has von Neumann-Morgenstern utility function U(x1,x2) = m7. She currently has $2025. a. Would she be willing to undertake a gamble that involves a gain $2875 with probability + and a loss of $1125 with probability ? Show your work and explain your answer. b. Would she be willing to undertake a gamble that involves a gain $2599 with probability and a loss of $800 with probability ? Show your work and explain your answer.