The results of a standard Proctor Test are tabulated as follows.Volume of Proctor Mold(ft³) Weight of Wet Soil in Mold(lb) Moisture Content(w%)1/303.69121/303.62141/303.88161/303.87181/303.87201/303.7721. a. Determine the moist unit weight (ymoist) and dry unit weight (yd). Plot the value of dry unitunit weight (yd) versus the value of moisture content (w%) and estimate the maximum dryunit weight (ydmax) and the corresponding optimum moisture content (w%)b. Determine the void ratio at the optimum moisture content if G s = 2.68c. Determine the degree of saturation at the optimum moisture content.Use the graph form below for plotting the compaction curve.COMPACTION CURVED 20.5R 20Y 19.5U 189N 1817.5T 1613W 16E 15.515 7 9 11 13 151719 212325 27293133 35 37 39Moisture Content (w%)HT (KN/m^3)

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1/30 1/30 3.88 3.87 1/30 3.87 1/30 3.77 . a. Determine the moist unit weight (ymoist) and dry unit unit weight (yd) versus the value of moisture content ( unit weight (ydmax) and the corresponding optimum n b. Determine the void ratio at the optimum moisture cont c. Determine the degree of saturation at the optimum mo Use the graph form below for plotting the compaction o COMPACTION CURV D 20.5 R 20 Y 19.5 U 189 N 18

1/30 1/30 3.88 3.87 1/30 3.87 1/30 3.77 . a. Determine the moist unit weight (ymoist) and dry unit unit weight (yd) versus the value of moisture content ( unit weight (ydmax) and the corresponding optimum n b. Determine the void ratio at the optimum moisture cont c. Determine the degree of saturation at the optimum mo Use the graph form below for plotting the compaction o COMPACTION CURV D 20.5 R 20 Y 19.5 U 189 N 18

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter6: Soil Compaction

Section: Chapter Questions

Problem 6.9P

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Problem (6) The laboratory test data for a standard Proctor test are given below. Volume of Proctor mold Mass of wet soil in the mold (kg) Moisture conient (%) (ст3) 943.3 943.3 1.65 10 1.75 12 943.3 1.83 1.81 14 943.3 16 943.3 1.76 18 943.3 1.70 20 a) Find the maximum dry unit weight and optimum moisture content. b) Calculate the zero-air-void unit weights for a soil with G, =2.68 at moisture content of 5, 10, 15, 20, and 25%. Plot a graph of Yrav versus moisture content.
The results of a Standard Proctor test are given in the following table. Moist Weight of Wet Sol Moisture Content in the mold (Ib) Trial (%) 26 4.08 28 4.12 30 4 4,18 32 Determine: 1. Maximum dry unit weight in Ib/ft^3 (4 decimal places) 2. Optimum water content in % (4 decimal places)
2. The results of the standard proctor test are given in the following table. Test Number Volume of Proctor Moist Weight of Wet Soil in the mold(kg) Moisture Content Mold (cm³) w% 1 943.3 1.68 9.9 943.3 1.71 10.6 3 943.3 1.77 12.1 4 943.3 1.83 13.8 943.3 1.86 15.1 6 943.3 1.88 17.4 7 943.3 1.87 19.4 943.3 1.85 21.2 Determine the following: Note: Plot moisture content versus dry unit weight. a. The maximum dry unit weight of compaction. b. The optimum moisture content. c. The moisture content to achieve 95% of ydmax
6. The results of a standard Proctor Test are tabulated as follows. Volume of Proctor Mold(ft³) Weight of Wet Soil in Mold(lb) Moisture Content(w%) 1/30 3.69 12 1/30 3.62 14 1/30 3.88 16 1/30 3.87 18 1/30 3.87 20 1/30 3.77 21 a. Determine the moist unit weight (ymoist) and dry unit weight (yd). Plot the value of dry unit unit weight (yd) versus the value of moisture content (w%) and estimate the maximum dry unit weight (ydmax) and the corresponding optimum moisture content (w%) b. Determine the void ratio at the optimum moisture content if G s = 2.68 c. Determine the degree of saturation at the optimum moisture content. Use the graph form below for plotting the compaction curve. COMPACTION CURVE D 20.5 R 20 Y 19.5 U 189 18 | 17.5 T 16.3 W 16 15.5 15 7 9 11 13 151719 212325 27293133 35 37 39 G Moisture Content (w%) T (KN/m^3)
A Standard Proctor test has yielded the values shown below. Determine the maximum dry unit weight and its OMC; remember V = 1/30 ft3. No Weight of wet soil (lb) Moisture % 1 3.26 8.24 4.15 10.20 4.67 12.30 4 4.02 14.60 3.36 16.80 2.
3. A soil sample was taken with a cylindrical metal core having a volume of 300cm³. The soil was saturated with water and then drainage water was allowed to drip. Meanwhile, evaporation of water from the soil was prevented. The drained soil sample weighed 500 g before oven drying and 350 g after oven drying. Calculate the following: a. bulk density (p6) b. moisture content by mass(%0m) and by volume (%0v) c. porosity (assume ps = 2.65 g/cm³) d. cm of water per 100 cm depth of soil %3D
1. The results of a standard Proctor test are given in the following table. Trial No. Weight of Moist Soil in the Mold (kg) Moisture Content (%) 1 1.68 9.9 1.71 10.6 12.1 2 3 1.77 4 1.83 1.86 1.88 13.8 15.1 17.4 6 7 1.87 1.85 19.4 21.2 8 a) Determine the maximum dry unit weight of compaction and the optimum moisture content. Given: mold volume = 943.3 cm3 b) Determine the void ratio and the degree of saturation at the optimum moisture content. Given: Gs = 2.7.
Problem A liquid limit test conducted on a soil sample in the cup device gave the following results: N 10 19 23 27 40 w (%) 60.0 45.3 39.8 36.5 25.2 The plastic limit test and natural water content. Plastic Limit Natural Water Content Test Test No. Weight of Container + Lid (g) 2 1 2 13.07 13.18 7.84 7.5 Weight of Container + Lid + Wet Soil (g) 22.12 21.84 17.53 16.97 Weight of Container + Lid + Dry Soil (g) 20.59 20.35 15.45 14.93 The shrinkage limit test. Weight of Dish with petroleum jelly (g) Weight of Dish with petroleum jelly+ Wet Soil (g) Weight of Dish with petroleum jely + Dry Soil (g) Volume of Shrinkage Dish (cm³) Volume of Oven-Dried Soil Pat (cm?) 11.3 38.51 32.81 15.26 12.83 8. Determine the liquid limit. b. 39% 9. Determine the plastic limit. a. 38% C. 37% d. 40% b. 21.20% 10. Determine the shrinkage limit. 20.55% C. 21.85% d. 20.20% a. a. 15.20% b. 22.40% C. 18.59% d. 16.45%
1. The following data shows the results of the liquid limit and plastic limit test using Casagrande cup method. Calculate the following: (Hint: Solve the moisture content of each test) a. Liquid Limit b. Plasticity Index c. Liquidity Index Liquid Limit Test: TEST NO. No. of Blows Wt. of Wet Soil + Container Wt. of Dry Soil + Container Wt. of Container Plastic Limit Test: TEST NO. Wt. of Wet Soil + Container Wt. of Dry Soil + Container Wt. of Container Natural Water Content: TEST NO. Wt. of Wet Soil + Container Wt. of Dry Soil + Container Wt. of Container 1 35 22.46 g 19.44 g 12.76 g 1 22.10 g 20.42 g 13.07 g 1 17.94 g 14.84 g 7.84 g 2 21 21.33 g 18.75 g 13.06 g 2 21.77 g 20.19 g 13.28 g 2 17.39 g 14.36 g 7.50 g 3 16 21.29 g 18.78 g 13.26 g
Problems 5.1 The results of a standard Proctor test are given below. Determine the mar imum dry unit weight of compaction and the optimum moisture content. Weight of wet soil Volume of Moisture in the mold (N) Proctor mold content (cm') (%) 943 14.5 8.4 943 18.46 10.2 943 20.77 12.3 943 17.88 14.6 943 16.15 16.8 5.2 For the soil described in Problem 5.1, if G. = 2.72, determine the void ratio and the degree of saturation at optimum moisture content.
The data from a standard Proctor test are shown in the table below.a. Determine the maximum dry unit weight and the optimum water content.b. Plot the zero air voids line.c. Determine the degree of saturation at the maximum dry unit weight.Diameter of mold 101.4 mmHeight of mold 116.7 mmMass of mold 4196.50 gramsSpecific gravity, Gs 2.722
5.5 The modified Proctor test (ASTM D 698, method C) was performed for a soil with G, = 2.70, and the results are as follows: Moist Weight in Mold, gf Water Content, % 6.5 3250 9.3 3826 12.6 4293 14.9 4362 17.2 4035 18.6 3685 (a) Plot the Ya versus w relation. (b) Determine Ya,max and wopt- (c) Calculate S and e at the maximum dry unit weight point. (d) What is Y, at Wopt? What is the range of water content if the relative compaction (R.C.) is required to be 95% of the modified Proctor Ya.max?