4. Given the following data definitions, the address of the first variable varl is given at Ox1001 1000 (hexadecimal). Using little endian, show the memory dump below. Fill each box below with a byte of the allocated memory in hexadecimal. You may use the ASCII table provided. .data varl: .byte 3, -2, 'A' var2: half 1, 256, 0xFFFF var3: strl: .word 0x3DE1C74, 0xFF .align 3 .asciiz "CPS2390" ADDRESS Data Segment: 4

icon
Related questions
Question

Please help me with this question.Thank you.

4. Given the following data definitions, the address of the first variable varl is given at
Ox1001 1000 (hexadecimal). Using little endian, show the memory dump below. Fill each box
below with a byte of the allocated memory in hexadecimal. You may use the ASCII table
provided.
.data
varl:
.byte 3, -2, 'A'
var2:
half 1, 256, 0xFFFF
var3:
strl:
.word 0x3DE1C74, 0xFF
.align 3
.asciiz "CPS2390"
Transcribed Image Text:4. Given the following data definitions, the address of the first variable varl is given at Ox1001 1000 (hexadecimal). Using little endian, show the memory dump below. Fill each box below with a byte of the allocated memory in hexadecimal. You may use the ASCII table provided. .data varl: .byte 3, -2, 'A' var2: half 1, 256, 0xFFFF var3: strl: .word 0x3DE1C74, 0xFF .align 3 .asciiz "CPS2390"
ADDRESS
Data Segment:
4
Transcribed Image Text:ADDRESS Data Segment: 4
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer