92. You have sequenced a short piece of DNA (by chain termination sequencing) and produced the gel shown in Fig. 263. What is the sequence of the DNA (starting from the 5 end)? a) 5GACCTGACTGTA3 b) 5ATGTCAGTCCAG3 c) 5TACAGTCAGGTC3 d) none of the above « ddAddT ddcddG «<
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- (i) Indicate by drawing where the RNA of Telomerase binds to the telomeric region. W, X, Y, and Z are the ends of the DNA and RNA strands respectively. Identify ends of DNA’s X, Y, and Z shown in Figure 1(a) & (b). (ii) (a) Telomerase -AAUCCCAAU- TTAGGGTTAGGGTTAGGGTTAGGGTTAGGGTTAGGG-W’ AАТСССААТСССААТСССАА-Х" (b) Telomeric DNA Figure 1EcoRI recognizes G A-A-T-T-C sequence and cleave/ cut between G and A. How will the DNA fragments look like if EcoRI is used for the DNA below? How many fragments are produced? 5- AAAGATTTGAATTTCGAATTCAATTTAAGAATTCCCTTAGAATTTCC -¹3Below is a sample of a segment of DNA…(copy from left to right) 3’ TACAATGGGCGACGCGCTTCGTTTCAGATT 5’ 5’ ATGTTACCCGCTGCGCGAAGCAAAGTCTAA 3’ 1.Assume the 6th amino acid is changed from T to G on the DNA template strand. What type of mutation is this? What effect would this have on the protein? Look up an example for this type of mutation. 2, Assume the 5th and 6th amino acids are removed from the DNA template strand. What type of mutation is this? How would this affect the protein? Look up an example of this type of mutation. 3.Which mutation changes the protein more...a point mutation or a frameshift mutation. Explain your reasoning. 4.What would be the problem if ATT was inserted into the DNA template strand after the second codon? (Be sure to consult the coding chart for amino acids). 5. What if the second amino acid was repeated over 5Ox. What amino acid is repeated? What type of mutation is this? If this is on chromosome 4, what genetic disorder is this?…
- a. Replicate this sense strand to create a double-stranded DNA helix. Write your answers in CAPS LOCK with NO SPACES between the nucleotides - e.g. ATGCCGAG..... TGAGGATGAAACTCACACCGGGGCGCAGTTTGGCACTTAGATTCTTGTACACGACCTAGTATAACACAGTT complementary strand: b. Using this DNA double helix, express the gene – i.e. determine the resulting polypeptide sequence by using the correct reading frame. Write your answers using the three letter abbreviation for each amino acid. polypeptide sequence: does the sense strand DNA sequence have 5’ and 3’ UTR sequences? 5'UTR = 3'UTR =No drawings just writing the answer a) Replicate this sense strand to create a double-stranded DNA helix TGAGGATGAAACTCACACCGGGGCGCAGTTTGGCACTTAGATTCTTGTACACGACCTAGTATAACACAGTT b) Using this DNA double helix, express the gene – i.e. determine the resulting polypeptide sequence by using the correct reading frame. When you get to the stop codon – you may write an asterisk (i.e. a “*”) to denote the stop codon. c) Does the sense strand DNA sequence have 5’ and 3’ UTR sequences? If so – write them in the space below 5’ UTR: 3’ UTR:1c) Even in automated sequencing, where you can include all 4 ddNTPs in one reaction, you need to include "normal" dNTPs as well as the ddNTPs - why are these necessary? Why can't you just put in the ddNTPs, since you've got all four of them available to the DNA polymerase?
- In a standard procedire, when writing and reading base sequences for nucleic acids (both DNA and RNAs) always to specify base sequence in 5' > 3' direction unless otherwise directed 1. From the base sequence 5' A-T-G-C-C-A 3' in a DNA template strand, determine the base sequence in hnRNA synthesized from the DNA template strand 2. From the base sequence 5' T-A-A- C-C-T 3' in a DNA template strand, determine the base sequence in hnRNA synthesized from the DNA template strand5' GTGCTAGCGGGAATGAGCTGGGATACTAGTAGGGCT 3' 3' CACGATCGCCCTTACTCGACCCTATGATCATCCCGA 5' Template Strand: 9. Using the template strand, transcribe the DNA above, Be sure you write your sequence 5 - 5 a indicate the 5' and 3' ends of any nucleic acid molecule(s). 10. Use the codon chart below to translate your mRNA into an amino acid sequence. Begin at the first codon. Third First position (5' end) Second position position (3'end) UGU Cys UAU Tyr Cc UGC Cys UGA Stop UGG Trp UCU Ser -Y UAC Tyr UAA Stop UAG Stop UUU Phe - F UUC Phe UUA Leu UUG Leu FL UCC Ser -- UCA Ser UCG Ser CGU Arg CGC Arg ER CGA Arg CGG Arg CCU Pro CAU His CUU Leu CUC Leu -- CAC His CAA Gln CAG Gln CCC Pro -P A - CUA Leu CUG Leu CCA Pro CCG Pro AAU Asn AAC Asn AGU Ser AGC Ser AGA Arg ACU Thr AUU lle AUC lle AUA lle AUG Met M ACC Thr -T ACA Thr ACG Thr A. AAA Lys K AAG Lys -R AGG Arg A. GAU Asp -D GAC Asp GGU Gly GGC Gly GCU Ala GUU Val GUC Val GCC Ala A -G GGA Gly GGG Gly A -V GUA Val GUG Val GCA Ala GCG Ala GAA Glu -E…Image 1. Which 2 primers from the choices provided would work to amplify the DNA sequence given below ? 5’ACTGAGTCCATGCGATCATGACTAT 3’ 3’TGACTCAGGTACGCTAGTACTGATA 5’ this is a hypothetical example. In a real experiment Choose 5’ TGAC 3’ 5’ CTAT 3’ 5’ ACTG 3’ 5’ ATAG 3’ Image2. the template strand?The results of a gel-based sequencing experiment are shown below. What is the sequence, written Only include nucleotides (no spaces or numbers )
- this is the worst figure i have ever seen. Evidently A and B are different but the same color? From what I understand A would be a sliding clamp, and B is Primase? Is F rna primer (I think personally) or representing the SSBP? this is the worst diagram ever. the words that are for labeling are as follows: DNA polymerase III, sliding clamp, helicase, single-stranded binding protein (SSBPs), topoisomerase, RNA primer, newly synthesized DNA, primase, and DNA ligase.5' - ATG GGG CCC GTT TTC AAT ATG CAG GTC CAT CCG TAC GTA CAG GCC GGA ATT TGA - 3' There are two introns in this DNA sequence. Remember introns start with GT and end with AG. (a) How many base pairs are in intron 1 and intron 2.several options can be correct Consider the following segment of DNA, which is part of a linear chromosome: LEFT 5’.…TGACTGACAGTC….3’ 3’.…ACTGACTGTCAG….5’ RIGHT During RNA transcription, this double-strand molecule is separated into two single strands from the right to the left and the RNA polymerase is also moving from the right to the left of the segment. Please select all the peptide sequence(s) that could be produced from the mRNA transcribed from this segment of DNA. (Hint: you need to use the genetic codon table to translate the determined mRNA sequence into peptide. Please be reminded that there are more than one reading frames.) Question 6 options: ...-Asp-Cys-Gln-Ser-... ...-Leu-Thr-Val-... ...-Thr-Val-Ser-... ...-Leu-Ser-Val-... ...-Met-Asp-Cys-Gln-...