A 2.2 gram sample of Pb₂O3 containing only inert impurities is treated with 20.0 mL of 6 N H₂SO4 and 41 mL of oxalic acid solution (containing 0.0126 grams of H₂C2O4-2 H₂O per milliliter) is added. After reaction is complete, the solution requires 20.00 mL of 0.100 N KMnO4. Calculate the purity of the sample in terms of the percentage of Pb₂O3. Balance the following chemical equations: Pb₂O3 + C₂O4²- + H+ → CO₂ + Pb²+ + H₂O
A 2.2 gram sample of Pb₂O3 containing only inert impurities is treated with 20.0 mL of 6 N H₂SO4 and 41 mL of oxalic acid solution (containing 0.0126 grams of H₂C2O4-2 H₂O per milliliter) is added. After reaction is complete, the solution requires 20.00 mL of 0.100 N KMnO4. Calculate the purity of the sample in terms of the percentage of Pb₂O3. Balance the following chemical equations: Pb₂O3 + C₂O4²- + H+ → CO₂ + Pb²+ + H₂O
Chemistry by OpenStax (2015-05-04)
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Chapter4: Stoichiometry Of Chemical Reactions
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![A 2.2 gram sample of Pb₂03 containing only inert impurities is
treated with 20.0 mL of 6 N H₂SO4 and 41 mL of oxalic acid solution
(containing 0.0126 grams of H₂C₂O4-2 H₂O per milliliter) is added.
After reaction is complete, the solution requires 20.00 mL of 0.100 N
KMnO4. Calculate the purity of the sample in terms of the
percentage of Pb₂O3.
Balance the following chemical equations:
Pb₂O3 + C₂O4²- + H+
→ CO₂+ Pb ²+ + H₂O](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F951dd416-9e85-4ee1-823a-94d34d579e9a%2F8b36c1fe-5a57-4416-a914-4d7443e1d6f4%2Fsbrgria_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A 2.2 gram sample of Pb₂03 containing only inert impurities is
treated with 20.0 mL of 6 N H₂SO4 and 41 mL of oxalic acid solution
(containing 0.0126 grams of H₂C₂O4-2 H₂O per milliliter) is added.
After reaction is complete, the solution requires 20.00 mL of 0.100 N
KMnO4. Calculate the purity of the sample in terms of the
percentage of Pb₂O3.
Balance the following chemical equations:
Pb₂O3 + C₂O4²- + H+
→ CO₂+ Pb ²+ + H₂O
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