a gold re white o sets of the possible genotypes of the parental and the resulting F1 fish by filling in the table below. Sets P1 P2 F1 gold fish F1 white fish 1
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- You are studying three traits in a goldfish variety; body colour (A or a), tail length (B or b) and shape (C or c). Note: Use the uppercase letters for the alleles associated with the dominant phenotypes and the lowercase letters for the alleles associated with the recessive phenotypes. Assume that each of these traits is regulated by one gene. a) You mate a gold fish (P1) with a white fish (P2) and obtain 100 fish in F1, of which 50 are gold and 50 are white. Write two sets of the possible genotypes of the parental and the resulting F1 fish by filling in the table below.You are studying three traits in a goldfish variety; body colour (A or a), tail length (B or b) and shape (C or c). Note: Use the uppercase letters for the alleles associated with the dominant phenotypes and the lowercase letters for the alleles associated with the recessive phenotypes. Assume that each of these traits is regulated by one gene. a) You mate a gold fish (P1) with a white fish (P2) and obtain 100 fish in F1, of which 50 are gold and 50 are white. Write two sets of the possible genotypes of the parental and the resulting F1 fishTwo alleles of gene C control hair color in horses: C¹and C². Horses homozygous for allele C¹ are red, heterozygotes are yellow, and C² homozygotes are cream. In the offspring of matings between heterozygotes, what phenotypic ratio is expected? A) 2 yellow: 1 red B) 3 red: 1 cream C) 1 red: 2 yellow: 1 cream D) all red E) 9 red: 3 yellow: 4 cream
- You are studying three traits in a goldfish variety; body colour (A or a), tail length (B or b) and shape (C or c). Note: Use the uppercase letters for the alleles associated with the dominant phenotypes and the lowercase letters for the alleles associated with the recessive phenotypes. Assume that each of these traits is regulated by one gene. Photo credit https://www.petmd.com Part A. You mate a gold fish (P1) with a white fish (P2) and obtain 100 fish in F1, of which 50 are gold and 50 are white. Write two sets of the possible genotypes of the parental and the resulting F1 fish by filling in the table below. Sets P1 P2 F1 gold fish F1 white fish 1 2 Part B. You cross a true breeding gold fish having long curly tail (P3) with a true breeding gold fish having short and straight tail (P4). All of the resulting F1 fish have long straight tails. Write the genotype of the parental fish (P3 and P4) using the outlined nomenclature.…In Mexican hairless dogs, a dominant allele codes for hairlessness. However, inheriting two dominant alleles is lethal; the fetus dies before birth. Suppose a breeder mates two dogs that are heterozygous for the hair allele. What are the predicted genotype and phenotype ratios of the puppies that are born? A) Phenotype Ratio 1:2:1 Genotype Ratio: 1:2:1 B) Phenotype Ratio 2:1 Genotype Ratio: 0:2:1 C) Phenotype Ratio 3:1 Genotype Ratio: 1:2:1 D) Phenotype Ratio 1:2:1 Genotype Ratio: 3:1In the mouse, gene A is epistatic to gene B. Dominant allele A allows pigmentation to be transported into fur; recessive allele a prevents transport of pigment, resulting in albino fur. Dominant allele B gives agouti fur color; recessive allele b gives black fur color. What phenotype would you expect to see in a mouse with a genotype of aaBb? a) Agouti fur O b) Albino fur Oc) Black fur O d) Black and white fur
- Two brown bears have cubs in late spring. The mother bear has the phenotype for long front claws. The mother bear has the genotype (Aa), while the father has the same genotype as the mother. A) What percentage of the offspring will have long claws?In some cats, the gene for tail length shows incomplete dominance. When a cat with a long tail is bred to a cat with no tail, the resulting offspring have short tails. For each of the following, predict the types of offspring that would result: a) A long tail cat bred to a cat with no tail b) A long tail cat bred to a short tail cat c) Two short tail catsAssume that a single gene determines coat coloration in cats, with the B allele resulting in orange coloration, and b allele results in black coloration. This gene exists on the X chromosome (recall that cats have XX/XY system of sex determination). My cat Pepper is a female tortoiseshell, and my cat Hobbes is an orange male. (i) What is the probability that Hobbes and Pepper have three kittens, Hopper (male), Pepsi (female), and Hippie (female)? What is the probability that they have three kittens, and that Hopper (male), and Hippie (female) are both orange, and that Pepsi (female) is a tortoiseshell? (ii) Distribution of % of Barr Bodies in each body part 120 100 100 80 100 60 40 50 50 20 Head Body Tail Black Orange
- Eye color in chimpanzees is coded for by one gene with two alleles, "A" and "a". “A" is dominant and codes for dark black eyes. "a" is recessive and codes for light brown eyes. If a black eyed chimpanzee (Parent A) has offspring with a light brown eyed chimpanzee (Parent B), and ½ of their offspring are black eyed and the other 2 are light brown eyed, then what is Parent A's genotype? AA Aa aa AaaTwo distinct phenotypes are found in the salamander Plethodon cinereus: a red form and a black form. Some biologists have speculated that the red phenotype is due to an allele that is dominant over an allele for black. Unfortunately, these salamanders will not mate in captivity, so the hypothesis that red is dominant over black has never been tested. One day, a genetics student is hiking through the forest and finds 30 female salamanders, some red and some black, laying eggs. The student places each female with her eggs (about 20 to 30 eggs per female) in a separate plastic bag and takes them back to the lab. There, the student successfully raises the eggs until they hatch. After the eggs have hatched, the student records the phenotypes of the juvenile salamanders, along with the phenotypes of their mothers. Thus, the student has the phenotypes for 30 females and their progeny, but no information is available about the phenotypes of the fathers. Explain how the student can determine…As a geneticist, you have continued to study the genetics of Snorks. You witness a cross between a snork who is heterozygous for hairiness, has a square head, is heterozygous for blue, and has rounded floppy ears and a snork that is heterozygous for all four of the traits. Calculate the odds for every possible arrangement of phenotypes in the offspring. (HINT: There are 16 possibilities) H-hairy R-Round head B-blue S-Pointed standing up ears h-hairless r-square head b-red s-rounded floppy ears