A spring made from music wire ASTM 228 steel has the following data: Free length=1.75" Wire diameter=0.055" Outside diameter=0.561" Applied load= 14 lb Ends=square and ground both ends hinged Number of coils=10 G=11.85 x 106psi E= 30 Mpsi Find Mean diameter, spring index, deflection, spring rate, force at solid length, check for buckling,coil clearance and hole diameter
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- A spring made from music wire ASTM 228 steel has the following data:Free length=1.75” Outside diameter=0.561”Wire diameter=0.055” Applied load= 14 lbEnds=square and ground both ends hingedNumber of coils=10 G=11.85 x 106psi E= 30 Mpsi Findspring rate, force at solid length,check for buckling,coil clearance and hole diameterDesign a helical spring to be used in spring balance with a wire diameter of 6mm and the outside diameter should be limited to 66mm. if the permissible shear stress of the spring material is 325 N/mm? and the Modulus of rigidity is 85kN/mm?. a) Compute the deflection of spring per active turn and the axial load on the spring considering the effect of curvature, take Wahl's factor as Kw= 1.1 b) Calculate the value of axial load neglecting the effect of stress factor. **Note: Please upload your handwritten working/solution to the link provided. The value of Mean diameter of the spring in mm . The Spring Index is. Shear stress factor, neglecting curvature effect . Deflection per active turn in mm Axial Load W in N .. Axial Load W in N. considering effect of curvature .1. Design a compression helical spring to cary a load of 500 N with a deflection of 25 mm. The spring index may be taken as 8. Assume the following values for the spring material: Permissible shear stress 350 MPa Modulus of rigidity = 84 kN/mm2 4C – 1 + 4C – 4 0.615 Wahl's factor -, where C= spring index. [Ans. d= 5.893 mm; D=47.144 mm; n 6]
- Design a compression helical spring to carry a load of 500 N with a deflection of 25 mm. The spring index may be taken as 8. Assume the following values for the spring material: Permissible shear stress 350 MPa Modulus of rigidity = 84 kN/mm? 4С -1 0.615 Wahl's factor 4C – 4 where C= spring index. C [Ans. d= 5.893 mm; D= 47.144 mm;n=6| %3D1. Design a compression helical spring to carry a load of 500 N with a deflection of 25 mm. The spring index may be taken as 8. Assume the following values for the spring material: Permissible shear stress = 350 MPa Modulus of rigidity = 84 kN/mm2 4С - 1 0.615 Wahl's factor where C-spring index. 4С - 4A Helical Compression Spring is made of A232 Chrome-vanadium with squared and ground ends has wire diameter 5 mm, outer diameter 81.5 mm, free length 246.3 mm and total 10 turns. Do the analysis if the spring is safe and if not, what is the largest free length to which it can be wound using ns=1.2? Attach File Browse My Computer
- The material is a spring wire has a shear modulus of 1.2 x 107 lbf/in2. The maximum allowable stress under design conditions is 50,000 lbf/in2. The spring index is 7. Assume the maximum stress is experienced when a 700 lbm objects falls from a height of 46 in above the tip of the spring, impacts squarely on the spring, and deflects the spring 10 in. Determie: 1. The minimum wire diameter is most nearly A. 0.58 in B. 0.88 in C. 1.4 in D. 1.8 in 2. The mean coil diameter is most nearly A. 8.6 in B. 10 in C. 13 in D. 16 in 3. The number of active coils is most nearly A. 8 B. 11 C. 12 D. 14The free end of a torsional spring deflects through 90° when subjected to a torque of 4 N-m. The spring index is 6. Determine the coil wire diameter and number of turns with the following data : Modulus of rigidity 80 GPa ; Modulus of elasticity = 200 GPa; Allowable stress = 500 MPa.A helical compression spring is wound using 0.12-in-diameter phosphor-bronze B159 wire. The spring index C = 10 and the total number of coils is N = 14. You may assume that the spring has both ends squared and ground and is supported between fixed ends. Also, Sgy = 0.45 · Sut- a. Estimate the spring rate. b. Estimate the static load corresponding to the yield strength. c. What should the free length of the spring be to ensure that when it is compressed solid the torsional stress does not exceed the yield strength? d. Calculate the critical value of the free length of the spring to avoid buckling.
- Define the rigid body used in statics. According to this; rigidity of bolt-nut connected elementBased on the value, the bolt diameter is 20 mm and the safe value of the bolt material.Calculate the stiffness values of the bolt and the intermediate element plate. (Note: Bolt's9x10 ^ 2 times as stress value ??? / cm ^ 2take as.). Strain gaugeElongation in bolt length measured with 250 ??, shortening amount in intermediate element platesIt was measured at 125 ??.The load on a helical spring is 1282 lb and the corresponding deflection is to be 3.4 inches. Rigidity modulus is 11 x 106 psi and the maximum intensity of safe torsional stress is 60,000 psi. If the wire diameter and the mean diameter are 0.5 in. and 3 in., respectively. Determine the number of active coils. Don't round your answer to preferred size. Round your answer to 4 significant figures2. A helical valve spring is to be designed for an operating load range of approximately 90 to 135 N. The deflection of the spring for the load range is 7.5 mm. Assume a spring index of 10. Permissible shear stress for the material of the spring 480 MPa and its modulus of rigidity 80 kN/mm. Design the spring. %23 4C - 1 0.615 Take Wahl's factor C being the spring index. 4C - 4 |Ans. d-2.74 mm; D 27.4 mm; n 6|