An electric field of intensity 4.05 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.350 m wide and 0.700 m long if the following conditions are true. (a) The plane is parallel to the yz-plane. N. m?/c • m (b) The plane is parallel to the xy-plane. N. m?/c (c) The plane contains the y-axis, and its normal makes an angle of 42.0° with the x-axis. N•m?/c Bookmark this tab

An electric field of intensity 4.05 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.350 m wide and 0.700 m long if the following conditions are true. (a) The plane is parallel to the yz-plane. N. m?/c • m (b) The plane is parallel to the xy-plane. N. m?/c (c) The plane contains the y-axis, and its normal makes an angle of 42.0° with the x-axis. N•m?/c Bookmark this tab

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter24: Gauss’s Law

Section: Chapter Questions

Problem 24.3OQ: In which of the following contexts ran Gausss law not be readily applied to find the electric field?...

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Similar questions

In which of the following contexts ran Gausss law not be readily applied to find the electric field? (a) near a long, uniformly charged wire (b) above a large, uniformly charged plane (c) inside a uniformly charged ball (d) outside a uniformly charged sphere (e) Gausss law can be readily applied to find the electric field in all these contexts.
A vertical electric field of magnitude 2.55 × 10* N/C exists above the Earth's surface on a day when a thunderstorm is brewing. A car with a rectangular size of 6.00 m by 3.00 m is traveling along a dry gravel roadway sloping downward at 17.4°. Determine the electric flux through the bottom of the car. N•m?/c
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Q/ For the three concentric spherical shells shown below, if ps1=200 µC/m², ps2= -50 µC/m², and ps3=px µC/m? respectively. Find (1) the electrical field at r= 6cm. (2) The value of px so that the electric field is zero at r=8.5 cm. a1=3 cm a2=5 cm Ps3 a3=7 cm Ps2 Ps1
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apv Q1-Derive the differential form of the continuity equation V.J+ = 0 using Maxwell's Equations. at Solution: From Ampere's law we have aD V x H = J+ at Taking the divergence of both sides V. (V x H) = V.J+V. 7 (210) = √ V.J + V. at Using the vector identity of V. (V x A) = 0 And Gauss law for electric field V.D = Pu We get that the left-hand side equals Zero and we arrange the right-hand side to apv 0 = V.J+ a at V.D = V.J+ at HW1- Derive the integral forms of Maxwell's equations and the continuity equation from the differential form. V.D
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