At a certain temperature, the equilibrium constant K for the following reaction is 677.: N₂(g) + O₂(g) ⇒ 2 NO(g) Use this information to complete the following table. Suppose a 31. L reaction vessel is filled with 1.3 mol of N₂ and 1.3 mol of O₂. What can you say about the composition of the mixture in the vessel at equilibrium? What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. 2 NO(g) N₂(g) +0₂(9) What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. 2 N₂(g)+20₂(g) 4 NO(g) There will be very little N₂ and 0₂. There will be very little NO. Neither of the above is true. K = 0 K = 0
At a certain temperature, the equilibrium constant K for the following reaction is 677.: N₂(g) + O₂(g) ⇒ 2 NO(g) Use this information to complete the following table. Suppose a 31. L reaction vessel is filled with 1.3 mol of N₂ and 1.3 mol of O₂. What can you say about the composition of the mixture in the vessel at equilibrium? What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. 2 NO(g) N₂(g) +0₂(9) What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. 2 N₂(g)+20₂(g) 4 NO(g) There will be very little N₂ and 0₂. There will be very little NO. Neither of the above is true. K = 0 K = 0
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 61QRT
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Transcribed Image Text:At a certain temperature, the equilibrium constant K for the following reaction is 677.:
N₂(g) + O₂(g) → 2NO(g)
Use this information to complete the following table.
Suppose a 31. L reaction vessel is filled with 1.3 mol of N₂ and
1.3 mol of O₂. What can you say about the composition of the
mixture in the vessel at equilibrium?
What is the equilibrium constant for the following reaction?
Round your answer to 3 significant digits.
2 NO(g)
N₂(g) + O₂(g)
What is the equilibrium constant for the following reaction?
Round your answer to 3 significant digits.
2 N₂(g)+20₂(g)
4 NO(g)
There will be very little N₂ and 0₂.
There will be very little NO.
Neither of the above is true.
K = 0
K = 0
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