By reference to the reacting ratio of NaOH and Ch3COOH, deduce the number of moles of CH3COOH required to reach equivalence. AnalysisCalculate the number of moles of NaOH required to reach equivalence.Concentration Of Acetic Acid= The volume of NaOH x The concentration of NaOH/ The concentration ofVinegar42.366 cm x 0.10mol dm/5.00cmTo find the molarity of Acetic acid (Assuming Vinegar has 100% acetic acid)No.of moles of Acetic acid = Molarity x Volume in L= 0.85 mol/L x 5.00 x 103 L= 4.3 x 103 molCH,СООН + NaОН %3D СH,СОONa + H.O1 mole of Acetic acid reacts with 1 mole of NaOH.the no. of moles of NaOH = the no, of moles of Acetic acidThe reacting ratio of NaOH: Acetic acid = 1: 1So, the no. of moles of NaOH is also 4.3 x 103 mol%3D• By reference to the reacting ratio of NaOH and CH,COOH, deduce the number of moles of CH,COOH requiredto reach equivalence.田 2.Titration of sodium hydroxide and vinegarMethodFill a burette with the solution of NaOH(aq) standardized in part 1.2Pipette 5.00 cm' of vinegar onto a clean conical flask.3Add a few drops of the indicator phenolphthalein solution to the conical flask and stand it on a white tile orwhite paper.4Titrate the NaOH against the vinegar, until the endpoint of the indicator is observed, and record the volumeadded from the burette.Repeat the titration until values within 0.05 cm³ are obtained.ResultsVolume NaOHTitration 1Titration 2Titration 3end volume / cm³ +0.0542.442.542.2start volume / cm + 0.05titre / cm' + 0.1042.442.542.2average titre / cm³ ± 0.10 = 42.366%3D

Reaction between CH3COOH and NaOH is as follows: CH3COOH (aq) + NaOH (aq) -------> CH3COONa (aq)…

Answered: By reference to the reacting ratio of…

By reference to the reacting ratio of NaOH and Ch3COOH, deduce the number of moles of CH3COOH required to reach equivalence.

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter16: Applications Of Neutralization Titrations

Section: Chapter Questions

Problem 16.48QAP

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

By reference to the reacting ratio of NaOH and Ch3COOH, deduce the number of moles of CH3COOH required to reach equivalence.

Analysis
Calculate the number of moles of NaOH required to reach equivalence.
Concentration Of Acetic Acid= The volume of NaOH x The concentration of NaOH/ The concentration of
Vinegar
42.366 cm x 0.10mol dm/5.00cm
To find the molarity of Acetic acid (Assuming Vinegar has 100% acetic acid)
No.of moles of Acetic acid = Molarity x Volume in L
= 0.85 mol/L x 5.00 x 103 L
= 4.3 x 103 mol
CH,СООН + NaОН %3D СH,СОONa + H.O
1 mole of Acetic acid reacts with 1 mole of NaOH.
the no. of moles of NaOH = the no, of moles of Acetic acid
The reacting ratio of NaOH: Acetic acid = 1: 1
So, the no. of moles of NaOH is also 4.3 x 103 mol
%3D
• By reference to the reacting ratio of NaOH and CH,COOH, deduce the number of moles of CH,COOH required
to reach equivalence.
田

2.
Titration of sodium hydroxide and vinegar
Method
Fill a burette with the solution of NaOH(aq) standardized in part 1.
2
Pipette 5.00 cm' of vinegar onto a clean conical flask.
3
Add a few drops of the indicator phenolphthalein solution to the conical flask and stand it on a white tile or
white paper.
4
Titrate the NaOH against the vinegar, until the endpoint of the indicator is observed, and record the volume
added from the burette.
Repeat the titration until values within 0.05 cm³ are obtained.
Results
Volume NaOH
Titration 1
Titration 2
Titration 3
end volume / cm³ +0.05
42.4
42.5
42.2
start volume / cm + 0.05
titre / cm' + 0.10
42.4
42.5
42.2
average titre / cm³ ± 0.10 = 42.366
%3D

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