• accepts two sequences, and • return a list whose elements are in ascending order and from the intersection of the given li For example:
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- The function interleave_lists in python takes two parameters, L1 and L2, both lists. Notice that the lists may have different lengths. The function accumulates a new list by appending alternating items from L1 and L2 until one list has been exhausted. The remaining items from the other list are then appended to the end of the new list, and the new list is returned. For example, if L1 = ["hop", "skip", "jump", "rest"] and L2 = ["up", "down"], then the function would return the list: ["hop", "up", "skip", "down", "jump", "rest"]. HINT: Python has a built-in function min() which is helpful here. Initialize accumulator variable newlist to be an empty list Set min_length = min(len(L1), len(L2)), the smaller of the two list lengths Use a for loop to iterate k over range(min_length) to do the first part of this function's work. On each iteration, append to newlist the item from index k in L1, and then append the item from index k in L2 (two appends on each iteration). AFTER the loop…1. a function that takes in a list (L), and creates a copy of L. note: The function should return a pointer to the first element in the new L. [iteration and recursion]. 2. a function that takes in 2 sorted linked lists, and merges them into a single sorted list. note: This must be done in-place, and it must run in O(n+m).Write a function that takes in n ADT Lists in an array. The function is going to be called Intersection, and it will return a new list with the elements common to all the n lists. Determine the time complexity
- Write a Python Code for the given function and conditions: Given function: def insert(self, newElement) Pre-condition: None. Post-condition: This method inserts newElement at the tail of the list. If an element with the same key as newElement already exists in the list, then it concludes the key already exists and does not insert the key.Merge2AscListsRecur that combines the nodes in X-list and Y-list into Z-list such that, after calling the function, Z-list is a sorted list (in non-decreasing order) containing all the nodes initially contained in X-list and Y-list – X-list and Y-list should both be empty after the call. The function should: ► Have only three parameters (each a pointer-to-Node) and no return value (be a void function). ► Not use any global variables or static local variables. ► Not use any looping constructs (for, while, do-while, ...). ► Be directly (not indirectly) recursive. ► Not create any new nodes, destroy any existing nodes or copy/replace the data item of any node. ► Not make temporary copies of the data involved using any other storage structures (arrays, stacks, queues, etc.). ► Use (if ever needed) no more than a small number of pointers to hold certain link addresses. ○ Not make temporary copies of the…Write a function sum_alt that takes a list of numbers zand calculates their alternating sum, defined as n-1 Σ(-1)+1 zk. k=0 Here Zo, Z1, Zn-1 denote the individual elements of the list.
- Ocaml Map functions left Writeafunctionmap_fun_left : (’a -> ’a) list -> ’a list -> ’a list = that is given a list of functions and a list of elements. For each element apply all functions from left to it and keep the result. Return the results as a list. examples map_fun_left [((+)1);( * )2;fun x->x-10] [1;2;3;4];; - : int list = [-6; -4; -2; 0] map_fun_left [(fun x->int_of_char x|> (+) 32 |> char_of_int);(fun x->char_of_int ((int_of_char x) +1))] [’A’;’B’;’C’;’D’];; - : char list = [’b’; ’c’; ’d’; ’e’]Max Absolute In List Function Lab Description Implement function max_abs_val(lst), which returns the maximum absolutevalue of the elements in list.For example, given a list lst: [-19, -3, 20, -1, 0, -25], the functionshould return 25. The name of the method should be max_abs_val and the method should take one parameter which is the list of values to test. Here is an example call to the function print(max_abs_val([-19, -3, 20, -1, 0, -25])) File Name maxabsinlst.py Score There are three tests each worth 2 points Note: You do not need any other code including the main method or any print statements. ONLY the max_abs_val method is required. Otherwise, the autograder will fail and be unable to grade your code. (I.e., do not include the above example in your code.) The above example should be used be test your code but deleted or comment out upon submission. PYTHON LABWrite a program that implements the doubly linked list clearly explain the steps for the following functions: a) Insert an element to doubly linked b) Delete an element from doubly linked list
- Write a function sort_and_return_in_pairs_list for example:[12, 13, 11, 15] return =>(11.12) and (12,13)[14,19,16,18,17,15] return =>(14.15) (16.17) (18.19)Sort-by-Length Write a function sort_by_length(words:List[str]) -> List[str] that returns a list of words, sorted by the length of each word and if some words have the same length, sort them alphabetically. For example, sort_by_length(['this', 'is', 'a', 'test', 'for', 'sorting', 'by', 'length']) == ['a', 'by You can see that the given list is sorted by the length of each word. The shortest word 'a' is in the first position. The by and is have the same length but b comes before i. How do you implement this function? Here are some steps you can follow: 1. Start with an empty list length_word_tuples 2. For each word, create a tuple where its first element is the length of the word and the second argument is the word itself e.g. (4, 'this'). Append the tuple into length_word_tuples. 3. Sort the list length_word_tuples using sorted() function. What is the type of each element of length_word_tuples? How is this different from calling sorted (words)? 4. Create another empty list called ans.…5. The following function indexCounter aims to find and return all the indices of the element x in a list L. if x is not in the list L, return an empty list. However, the implementation has a flaw, so that many times it will return error message. Can you fix the flaw? def indexCounter(L, x): indexList [] startIndex = 0 while startIndex < len(L): indexList.append (L.index (x, startIndex)) startIndex = L.index (x, startIndex) + 1 return indexList