Write a function sort_and_return_in_pairs_list for example: [12, 13, 11, 15] return =>(11.12) and (12,13) [14,19,16,18,17,15] return =>(14.15) (16.17) (18.19)
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Write a function sort_and_return_in_pairs_list
for example:
[12, 13, 11, 15] return =>(11.12) and (12,13)
[14,19,16,18,17,15] return =>(14.15) (16.17) (18.19)
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- struct insert_at_back_of_sll { // Function takes a constant Book as a parameter, inserts that book at the // back of a singly linked list, and returns nothing. void operator()(const Book& book) { /// TO-DO (3) /// // Write the lines of code to insert "book" at the back of "my_sll". Since // the SLL has no size() function and no tail pointer, you must walk the // list looking for the last node. // // HINT: Do not attempt to insert after "my_sll.end()". // ///// END-T0-DO (3) ||||// } std::forward_list& my_sll; };Look at the two functions Merge-and-Count & Sort-and-Count. You are also given an array- Awesome_Array= 3 7 10 14 18 19 2 11 Merge-and-Count (A, B){ curA = 0; curB = 0; count = 0; mergedList = empty list while (not at end of A && not at end of B){ a = A[curA]; b = B[curB]; if (a < b) append a to mergedList; curA++; else append b to mergedList; curB++; count = count + number of elements left in A } if (at end of A) append rest of B to mergedList; else append rest of A to mergedList; return (count, mergedList); } Sort-and-Count(L){ if list L has one element return (0, L) Divide the list into two halves A and B (rA, A) ← Sort-and-Count(A) (rB, B) ← Sort-and-Count(B) (rC, L) ← Merge-and-Count(A, B) total_count =…Write a function reverse_iter_for that takes a list and returns a new list that is the reverse of the original using a for loop. You should not need any indexing notation. def reverse_iter_for(lst): """Returns the reverse of the given list. >>> reverse_iter_for([1, 2, 3, 4]) [4, 3, 2, 1] TELEEL "*** YOUR CODE HERE ***" Complete the function reverse_iter_while that behaves identically to reverse_iter_for but is implemented as using a while loop. You may use indexing or slicing notation. Do not use 1st [::-1] ! def reverse_iter_while(lst): """Returns the reverse of the given list. >>> reverse_iter_while([1, 2, 3, 4]) [4, 3, 2, 1] rev_lst, i = [], 0 while i < len(lst): "*** YOUR CODE HERE ***"
- In OCaml Programming Language, write a function: val prime_separator : int list -> int list * int list = <fun> that takes an integer list as an input, and returns a pair of integer lists where the prime numbers are in the first while the composite numbers are in the second returned list. #prime_separator [1; 2; 3; 4; 5; 6; 7; 8; 9; 10; 11];; - : int list * int list = ([11; 7; 5; 3; 2], [10; 9; 8; 6; 4; 1])struct insert_at_back_of_dll { // Function takes a constant Book as a parameter, inserts that book at the // back of a doubly linked list, and returns nothing. void operator()(const Book& book) { / // TO-DO (2) |||| // Write the lines of code to insert "book" at the back of "my_dll". // // // END-TO-DO (2) ||| } std::list& my_dll; };Listdiff Use the built-in higher order functions2 and write a non-recursive function val listdiff : ’a list -> ’a list -> ’a list = that, given 2 lists, returns a third, containing elements of the first list that are not in the second list. # listdiff [1;2;2;6;3;9;1;4;6] [2;3]; Using OCaml
- OCAML programming language Listdiff Use the built-in higher order functions2 and write a non-recursive function val listdiff : 'a list -> 'a list -> 'a list = <fun> that, given 2 lists, returns a third, containing elements of the first list that are not in the second list. # listdiff [1;2;2;6;3;9;1;4;6] [2;3];;- : int list = [1; 6; 9; 1; 4; 6]Exercise 1: //The max function the max between a and b, it returns a if a == //b public double max(double a, double b); //The mult function returns the result of a * b public double mult(double a, double b); //The exist in array function returns the index of the element //‘a’ if //‘a’ exist in array ‘arr’ otherwise returns ‘-1’ public int existsInArray(int [] arr, int a); //Are array equals method compares two arrays and returns true // if the elements of array ‘a’ are equal to elements of array // ‘b’, element by element. If equals it returns 0, it returns - // 1 if not public int areArrayEquals(int [] a, int [] b); Devise four executable test cases for every method in the JUnit notation. See the attached handout for a refresher on the notation.Suppose a node of a doubly linked list is defined as follows: struct Node{ int data; struct Node* next; struct Node* prev; }; Write the function definition of the function deleteElement as presented below. This function deletes a node at position n from a doubly linked list. struct Node* deleteElement(struct Node* head, int n){ //write the function definition }
- Write a recursive function named Multiply2 that multiples by 2 and prints each element in a given list. For example: mylist=[1,2,3,4] Multiply2(mylist) prints: 2 4 6 8 Note: the function takes only one parameter, which is the list on which the operation will be performed.Language: C++ Solve the following problem using a Singly Linked List.Given a singly linked list of characters, write a function to make a word out of given letters in the list Example:Input:C->S->A->R->B->B->E->LNULLOutput:S->C->R->A->B->B->L->E->NULLIn OCaml Programming Language: Use the built-in higher order functions and write a non-recursive function val listdiff : ’a list -> ’a list -> ’a list = <fun> that, given 2 lists, returns a third, containing elements of the first list that are not in the second list. # listdiff [1;2;2;6;3;9;1;4;6] [2;3];; - : int list = [1; 6; 9; 1; 4; 6]