Find the centroid for the shaded area . [Qx] :- 120 150 Y=60 30 90 130 [Q] 4 4 6
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- Find for the shaded area the centroid [Q2] 120 r=5 150 Y=60 30 90 1304.15. Calculate I,, ly, Iy for the section of Figure P4.9 above. You can use the results from Example B.1.3一4 Problem 1 Find the centroidal coordinates for the following triangles using the integrals SycdA S dA and %3D = X vp S You may utilize symmetry when appropriate. (-3,4) (3,4) (0,0) a. (5,4) (5,1) b. (4'0) (0) C. ×て (3,4) す Th-てh:8018 (-)
- 216 Home Works Find the Centroid for the Shaded area. [Q2] 120 150 30 90 130 4 4For the given 2D element shown in the diagram with positions A = 5 m and B = 5 m, answer the following: a) X (0,B) 1 2 (0,0) 3 (A,B) DIAGRAM NOT TO SCALE Write the expression of basis function associated with point 1, in terms of x and y Submit part Unanswered b) The displacement of node 3 is 0.3 m in the x direction, and 0 in the y. All other node displacements are zero. What is the normal strain component across the element? Submit part UnansweredThe y coordinate of the center of mass of the disk element given in the figure is [ft]. Determine. [Volume of disk element dV=πz2dy can be calculated from the equation].
- Given the triangle described by the homogenous point matrix: [2 2 0 11 5 0 1 1 5 5 0 11 Scale it to three-fourth size keeping the centroid in the same location. (5,5) P= 2 (2.5) (2.2)Solve the first page (2) using the second pictureFor the area below, evaluate 1. The (x,y) coordinates of the centroid (please mark your origin or reference point on the diagram) 2. The 2nd moments and product of area in centroidal-based xy (horizontal-vertical) coordinates 3. The principal 2nd moments of area, and the direction of the first principal axis relative to the horizontal (x) axis (anticlockwise positive) 50 75 30 150 60 50 15 Figure 1: Cross section (all dimensions in mm) Quantity Xc (please mark your origin on the diagram) Yc (please mark your origin on the diagram) Ix ly Ixv I₁ I₂ a1 (please show the direction) Value 30 Units
- A certain two dimensional shape has the following integrals S dA fx dA 3 13.5 in fydA = 13.5 in³ fx² dA = 42.75 in 4 fx y d A = 4.5 in² AMERION 4 dA = 39.375 in fy² dA = 42.75 in where dA is a differential area element, dx*dy. Find the following properties of the shape Centroid = (X, Y) = ([ 3 3) in. The Area Moments of Intertia about axes parallel to the x and y axes through the centroid. |x' = in4 4 ly' =| Product of Inertia, Ix'y' i MEN Polar Moment of Inertia, J(x'y') F in 4 424 - Constant thickness homogeneous planar plate in the figure coordinates of the center of gravity M (Xm, Ym) of the surface area, Find it on the (x, y) set. t = 3 cm and a = 9 cm. Find the coordinates (Xm; Ym) of the rectangle extracted from this planar plate in the x and y axes.A) (9; 15)B) (9; 13)C) (9; 25.5)D) (9; 18)E) (9; 22.5)10 / 36 110% Q22](problem 2/28: p37) (¿ãt2) Determine the resultant `R" of the two forces Shown in fiqure, and find the angle o" between R and A- 10 800 N the x-axis . 900 N 25 4" Ane R=10379 N . 0 =66-8 Q23]( problem 2/25 's p37) Exemple201-2o At What angle x must the Type here to search