Find the values of n and m to solve this puzzle int n = ? int m = ? int t = 39; int s = 0; while(n>1){ if(n & 1){ n = (n<<2) - n + 1; } else { n = n >> 1; } if(s == t && m == t){ return; } s++; } failure("Seems you forgatz the essence of Collatz");
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Find the values of n and m to solve this puzzle
int n = ?
int m = ?
int t = 39;
int s = 0;
while(n>1){
if(n & 1){
n = (n<<2) - n + 1;
}
else {
n = n >> 1;
}
if(s == t && m == t){
return;
}
s++;
}
failure("Seems you forgatz the essence of Collatz");
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- sum = 0; for (int i = 1; i< n; i = sum++ || 2*i)int funcB(int); int funcA(int n) { if (n 4) { return n* funcA(n - 5); } else { return n- funcB(n - 1); int main() { cout << funcA(13); return 0; What is the output of this program? Please show our work.for (int i = 1; i <= 3; i++) { for (int j = 1; j <= 3; j++) { System.out.print((i * j) + " "); }
- inhinclude Rsing namespace std; int maxResult( ) int maxVal for (int i { for (int j = 0; j <= n 0; i <= n; i += a) i; j += b) %3D %3D float z = (float)(n (i + j)) / (float)(c); if (floor(z) { int x = int y ceil(z)) i / a; j/ b; maxVal = max(maxVal, x + y (int)z); return maxVal; } int main() { max cout << maxResult( ); return 0; 1 } Input Compilation failed due to fellowing ons main.cpp:7:23: error: 'n' was not declared in this scope 7| for (int i = 0; i <= n; i a) main.cpp:7:31: error: 'a was not declared in this scope for (int i = 0; i <= n; i t= a) %3D main.cpp:9:36: error: b' was not declared in this scope | 6 for (int j = 0; j <= n - i; j - b) %3D main.cpp:11:45: error: 'c was not declared in this scopeGiven code: int s=0; for ( int i=1; i<5; i++ ){ s = s + i ; } Which one is correct, after running the code. Group of answer choices s=1 s=15 s=10 s=5Java Program: Recursive Method There are n people in a room where n is an integer greater then or equal to 2. Each person shakes hands once with every other person. What is the total number of handshakes in the room? Write a recursive method to solve this problem with the following header:public static int handshake(int n)where handshake(n) returns the total number of handshakes for n people in the room. To get you started if there are only one or two people in the room, then:handshake(1)=0handshake(2)=1
- int calc=1; for (i=1;ia) FindMinIterative public int FindMin(int[] arr) { int x = arr[0]; for(int i = 1; i < arr.Length; i++) { if(arr[i]< x) x = arr[i]; } return x; } b) FindMinRecursive public int FindMin(int[] arr, int length) { if(length == 1) return arr[0]; return Math.Min(arr[length - 1], Find(arr, length - 1)); } What is the Big-O for this functions. Could you explain the recurisive more in details ?void deleteRange( int from, int to) { int i, j = 0; for (i = 0; i < counter; i++) { if (i <= from - 1 || i >= to + 1) { A[j] = A[i]; j++; } } for (int i = 0; i < j; i++) cout << A[i] << " "; } Above method deletes range of elements from an array. Please explain the logic of above code in simple english (algorithm and comments).void deleteRange( int from, int to) {int i, j = 0;for (i = 0; i < counter; i++) {if (i <= from - 1 || i >= to + 1) {A[j] = A[i];j++;}}for (int i = 0; i < j; i++)cout << A[i] << " ";} Above method deletes range of elements from an array. Consider array A[] globally declared and counter is its size. Please explain the logic of above code in simple english (algorithm and comments).using System; class HelloWorld { static void Main() { int rows=21; int columns=76; for(int i=0;i<rows;i++) //for loop for printing the pattern for 21 rows { for(int j=1;j<=columns;j++) //for loop for printing the pattern in 76 columns { if((i+j)%7!=1 ) //if the addition of i and j does not give remainder of 1 when divided by 7 then Console.Write("-"); //print dash - on console else //otherwise peint a space on console Console.Write(" "); } Console.WriteLine(); //print a newline for printing on new row... } } }JAVA Question 2: For two integers m and n, their GCD (Greatest Common Divisor) can be computed by a recursive method. Write a recursive method gcd(m,n) to find their Greatest Common Divisor. Method body: If m is 0, the method returns n. If n is 0, the method returns m. If neither is 0, the method can recursively calculate the Greatest Common Divisor with two smaller parameters: One is n, the second one is m mod n (or m % n). The recursive method cannot have loops. Note: although there are other approaches to calculate Greatest Common Divisor, please follow the instructions in this question, otherwise you will not get the credit. main method: Prompt and read in two numbers to find the greatest common divisor. Call the gcd method with the two numbers as its argument. Print the result to the monitor. Example program run: Enter m: 12 Enter n: 28 GCD(12,28) = 4 And here is what I have so far, package CSCI1302;import java.util.*;public class RecursionDemo { public static void…SEE MORE QUESTIONS