Given the equation, V – Voe-(2.6x10-3)t, at what time will | %3D oe the voltage drop by its original value? Select one: a. t= 2566 s b. t 2666 s C. t= 2746 s d. t= 2646 s
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- An ECG monitor must have an KC time constant lessthan 1.00102s to be able to measure variations involtage oversmall time intervals, (a) If the resistance of the circuit (duemostly to that of the patient's chest) is 1.00kTwhat is the maximum capacitance of the circuit?(b) Would It be difficult in practice to limit the capacitance to less than the value found in (a)?what is the total resistance? Assume that the current enters one coraer and the sides of a cube. exits at the diagonally opposite corner. B. A cell with internal resistance of 1.0 o is connected in series withn5.0 oresistor and 3.0 N. The voltage across the 5 n resistor is 5 V. (al What current flows through the circuit? (b) What is the voltage across the 3 a resistor? iel What is the terminal voltage of the cell? (d) What is the emf of the cell? 9. There are 100 graduations In the scale of an ammeter with internal resistance of 0.18 n and intended to measure a current up to 10 A. (a) What is the value of each graduation? (b) Convert this to an ammeter that can measure up to 100 A. (c) How will the value of the graduations change? 10. There are 30 graduations in the scale of a voltmeter with an internal ading of 30 V.In the schematic below two batteries are in series and drive current through the circuit as shown. The first resistor has a voltage drop AV₁ = 1.2 V, the middle resistor has a resistance of R = 64, and the last resistor has a voltage drop AV₂ = 1 V. Given these parameters, what is the magnitude of current flowing through the circuit in milli-amps (mA)? Giver your answer to 3 significant figures. AV, ww 3.0 V 4.5 V ww ΔV, ww R
- Given the equation V =Voe-(7.7x10-)t. at what time will the voltage drop by its original value? Select one Oa t= 155 O b. t= 165 Oc t= 145 O d. t= 175In the figure resistor 1 = 126 2, resistor 2 = 81 N, and the ideal batteries have emfs ɛ1 E2 = 5 volts, and ɛ3 = 7 volts. Find the current through resistor 1. = 29 volts, Round off answer up to 3 decimal places. Consider absolute value. Include the unit (A for ampere, V for volt and ohm for ohm). Rz RI wwIn the schematic below two batteries are in series and drive current through the circuit as shown. The first resistor has a voltage drop AV = 2.8 V, the middle resistor has a resistance of R = 154 Q, and the last resistor has a voltage drop AV2 = 1.6 V. Given these parameters, what is the magnitude of current flowing through the circuit in milli-amps (mA)? Giver your answer to 3 significant figures. %3D AV, 3.0 V 4.5 V ww
- connected con sist of five resis tors 7.a A circit as below. Determine the effective Tesistance in the circuit. RI RS- R2 R+ Ginen R, = sor, Rz=25Jr, R3= 30r, R¢=60r, Rs= 70r iD Wlhat is Hhe current is Hhe circuit iç the potential the resistors is 24 V? CICcross What is the potential that ccin be tapped across Rs? b.A circuit consist sisc capacitors connicted as below, detemine the effective capacitalnce. (3 G= SmF, G= Smf, G= 6mF, C4 = 6mF, Gaigg fo Cs= 8mF, C6 = 8 mF. What is the energy stored in the capacitors in ;circuit if the potential across %3D the the capacitors is 24V? C- lwo charges +3C and t 5C are placed 20Cm from in Yacuum- Wlhat magnitude of force will. their Centres they ebcert on each other, If Hhe sccond charge hes its polacity changed to negative (-sc). Inlliat would be the nature of the force ? Will there be a change in magnitude ? LPermitivity of free space a 8.8sx 10 -12mam/sir how do u draw an electrical circuit, with a voltometer and a anmeter.3:26 A docs.google.com What is the voltage drop across the 4 ohm resistor? Your answer ww 42 v=? What is the voltage drop across the 5 ohm resistor?
- 01701&cmid=97298page38 For the following circuit in the figure below. Determine V,-V, (in units of V) for E = 48.5 V. a t of estion 20 20 50 9. Select one: OA. 8.08 OB. -40.42 OC. -9.70 OD. -8.08 OE 9.70 ous page brt sc delete backsoace entA. Determine the equivalent resistance fir the circuit.keep vaules in ohms B. Determine hiw much current the battery produces. keep vaules in amps C. Determine the voltage across R12 and R3; call these values V12 and V3, keep the vaules in volts. then usr ohms law: V=i r, to fkmd the current across R12 and R3; call tjese 12 and 13, keep these vaules in amps. D. use ohms law to caculare the voltages across R1 and R2; call these vaules V1 and V2, keep results in volts. Requivatont,scris= Sihi=R1 tket . kequivaknt, papli=Zi Ri =RI K You circuit are given the following below. combination Z Rz R3 where V is a 12 V battery; R1 is 330ohms R2 is 180 ohms R3 is 270 ohms please write all work legaie thanks :)1.3 Ohmmeter: In order to use the basic meter as an ohmmeter, a variable resistor and a DC voltage source, for example a battery, should be connected in series to the meter. The connection diagram is given in Fig. 3. The resistor to be measured is connected between terminals a and b. Ry max 1 mA Rm A + a Rx Figure 3. . VDC 9